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In a box there are 2 white, 3 black, and 4 red balls. If a ball is drawn at random, what is the probability that it is black? That it is not red?

Short Answer

Expert verified
The probability of drawing a black ball is \( \frac{1}{3} \) and the probability of drawing a non-red ball is \( \frac{5}{9} \).

Step by step solution

01

- Total Number of Balls

Count the total number of balls in the box. There are 2 white, 3 black, and 4 red balls. So, the total number of balls is: \[ 2 + 3 + 4 = 9 \]
02

- Number of Black Balls

Identify the number of black balls. From the problem, there are 3 black balls.
03

- Probability of Drawing a Black Ball

Use the formula for probability, which is the number of favorable outcomes divided by the total number of outcomes. Therefore, the probability that a ball drawn is black is: \[ \frac{3}{9} = \frac{1}{3} \]
04

- Number of Non-Red Balls

Calculate the number of non-red balls by subtracting the number of red balls from the total number of balls. There are 4 red balls in a total of 9 balls, so the number of non-red balls is: \[ 9 - 4 = 5 \]
05

- Probability of Drawing a Non-Red Ball

Again use the probability formula. The probability that a ball drawn is not red is: \[ \frac{5}{9} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability is a way to measure the likelihood of an event happening. It's calculated by dividing the number of favorable outcomes by the total number of possible outcomes. In our example with the balls, we wanted to find the probability of drawing a black ball and a non-red ball from a box containing various colored balls.

To calculate the probabilities, follow these steps:
  • First, identify the total number of outcomes. In this case, it is the total number of balls in the box, which is 9.
  • Next, figure out the favorable outcomes for the specific event. For drawing a black ball, there are 3 black balls, so there are 3 favorable outcomes.
  • Lastly, use the fraction \((\frac{Number\; of\; Favorable\; Outcomes}{Total\; Number\; of\; Outcomes})\) to find the probability. For a black ball: \(\frac{3}{9} = \frac{1}{3}\), and for a non-red ball: \(\frac{5}{9}\).

Understanding how to calculate probabilities will help you with many other probability-related problems.
Random Variable
A random variable is a variable that can take on different values, each with a certain probability. In the context of our problem, the random variable is the color of the ball that is drawn from the box. Since the ball is drawn at random, every ball has an equal chance of being picked.

When we say we are drawing a ball at random, it means each ball - regardless of its color - has an equal chance of being chosen. Here, each of the 9 balls has an equal 1 in 9 chance initially. After we identify the color categories, like black or non-red, we can calculate the specific probability based on these categories.
Favorable Outcomes
Favorable outcomes are the specific outcomes that we are interested in for a given event. In probability, these are the successful outcomes that contribute to the event happening.

For the event of drawing a black ball, the favorable outcomes are the counts of black balls in the box. In our example, there are 3 black balls, so there are 3 favorable outcomes for drawing a black ball.
For the event of drawing a non-red ball, the favorable outcomes are the counts of all balls that are not red. With 2 white and 3 black balls, there are 5 non-red balls, thus 5 favorable outcomes for drawing a non-red ball.

To summarize:
  • Favorable outcomes for drawing a black ball: 3 (the number of black balls)
  • Favorable outcomes for drawing a non-red ball: 5 (the sum of white and black balls)

Knowing the favorable outcomes and the total number of possible outcomes allows us to find probabilities easily.

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Most popular questions from this chapter

What is the probability that the 2 and 3 of clubs are next to each other in a shuffled deck? Hint: Imagine the two cards accidentally stuck together and shuffled as one card.

Three coins are tossed; what is the probability that two are heads and one tails? That the first two are heads and the third tails? If at least two are heads, what is the probability that all are heads?

(a) Suppose you have two quarters and a dime in your left pocket and two dimes and three quarters in your right pocket. You select a pocket at random and from it a coin at random. What is the probability that it is a dime? (b) Let \(x\) be the amount of money you select. Find \(E(x)\) (c) Suppose you selected a dime in (a). What is the probability that it came from your right pocket? (d) Suppose you do not replace the dime, but select another coin which is also a dime. What is the probability that this second coin came from your right pocket?

(a) A candy vending machine is out of order. The probability that you get a candy bar (with or without return of your money) is \(\frac{1}{2},\) the probability that you get your money back (with or without candy) is \(\frac{1}{3}\), and the probability that you get both the candy and your money back is \(\frac{1}{12}\). What is the probability that you get nothing at all? Suggestion: Sketch a geometric diagram similar to Figure 3.1, indicate regions representing the various possibilities and their probabilities; then set up a four-point sample space and the associated probabilities of the points. (b) Suppose you try again to get a candy bar as in part (a). Set up the 16 -point sample space corresponding to the possible results of your two attempts to buy a candy bar, and find the probability that you get two candy bars (and no money back); that you get no candy and lose your money both times; that you just get your money back both times.

A single card is drawn at random from a shuffled deck. What is the probability that it is red? That it is the ace of hearts? That it is either a three or a five? That it is either an ace or red or both?

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