Chapter 2: Problem 5
Find all the values of the indicated roots and plot them. $$ \sqrt[3]{1} $$
Short Answer
Expert verified
The roots are \(1\), \(-\frac{1}{2} + i\sqrt{3}/2\), and \(-\frac{1}{2} - i\sqrt{3}/2\). Plot them on the complex plane.
Step by step solution
01
Understand the Problem
Given is \(\root[3]{1}\), which requires finding all complex numbers \(z\) such that \(z^3 = 1\).
02
Express 1 in Polar Form
The number 1 can be expressed in polar form as \(1 = e^{i \theta}\). Since \(e^{i \theta} = \cos \theta + i \sin \theta \), we can choose \(\theta = 0 + 2k\frac{\pi}{3}\) for \(\root[n]{1}\).
03
Identify the Principal Root
For \(\theta = 0\), the principal root of the equation is \(z_0 = e^{i \cdot 0} = 1\).
04
Calculate the Remaining Roots
The remaining roots are obtained by adding \(\frac{2\pi}{3}\) and \(2 \cdot \frac{2\pi}{3}\) to the principal argument and evaluating: \(z_1 = e^{i \frac{2\pi}{3}} = \cos(\frac{2\pi}{3}) + i \sin(\frac{2\pi}{3}) = -\frac{1}{2} + i \cdot \frac{\root{3}{4}}\) and \(z_2 = e^{i \frac{4\pi}{3}} = \cos(\frac{4\pi}{3}) + i \sin(\frac{4\pi}{3}) = -\frac{1}{2} - i \cdot \frac{\root{3}{4}}\).
05
Plot the Roots on the Complex Plane
The roots \(z_0 = 1, z_1 = -\frac{1}{2} + i \sqrt{3}/2,\) and \(z_2 = -\frac{1}{2} - i \sqrt{3}/2\ \) should be plotted on the complex plane, forming the vertices of an equilateral triangle centered at the origin.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
Complex numbers are numbers formed by combining real and imaginary parts. A complex number is typically written as \( z = a + bi \), where \( a \) is the real part and \( b \) is the imaginary part.
These numbers allow for calculations that extend beyond the real number system and can solve equations that have no real solutions. For example, the equation \( x^2 + 1 = 0 \) has no real solution but has complex solutions \( x = i \) and \( x = -i \), where \( i \) is the imaginary unit, defined as \( i = \sqrt{-1} \).
These numbers allow for calculations that extend beyond the real number system and can solve equations that have no real solutions. For example, the equation \( x^2 + 1 = 0 \) has no real solution but has complex solutions \( x = i \) and \( x = -i \), where \( i \) is the imaginary unit, defined as \( i = \sqrt{-1} \).
- Real Part: The real part \( a \) of a complex number \( z = a + bi \) is the component along the real axis.
- Imaginary Part: The imaginary part \( b \) is the coefficient of \( i \) and lies along the imaginary axis.
- Complex Conjugate: The complex conjugate of \( z = a + bi \) is \(\bar{z} = a - bi\). It reflects the complex number across the real axis.
Polar Form
Polar form is another way to represent complex numbers. Instead of using rectangular coordinates \( (a, b) \), it uses a magnitude (or modulus) \( r \) and an angle (or argument) \( \theta \).
In polar form, a complex number \( z = a + bi \) can be written as \( z = r e^{i\theta} \), where:
For example, to find the roots of \( 1 \), we express \( 1 \) in its polar form as \( e^{i \cdot 0} \), since its magnitude is 1 and its angle is 0 radians.
In polar form, a complex number \( z = a + bi \) can be written as \( z = r e^{i\theta} \), where:
- \( r = \sqrt{a^2 + b^2} \) is the magnitude, or distance from the origin to the point \( (a, b) \).
- \( \theta = \text{atan2}(b, a) \) is the angle formed with the positive real axis.
For example, to find the roots of \( 1 \), we express \( 1 \) in its polar form as \( e^{i \cdot 0} \), since its magnitude is 1 and its angle is 0 radians.
Roots of Unity
Roots of unity are the solutions to the equation \( z^n = 1 \). They are complex numbers that, when raised to a certain power (\( n \)), yield 1.
To find these roots, we express 1 in its polar form as \( e^{i \cdot 2k\pi} \) where \( k \) is an integer. The \( n \)-th roots of unity are then given by:
\[ z_k = e^{i \cdot \frac{2k\pi}{n}} \text{ for } k = 0, 1, ..., n-1 \]For \( n = 3 \), the cube roots of unity are:
\[ z_0 = e^{i \cdot 0} = 1 \]
\[ z_1 = e^{i \cdot \frac{2\pi}{3}} \approx -\frac{1}{2} + i \cdot \frac{\sqrt{3}}{2} \]
\[ z_2 = e^{i \cdot \frac{4\pi}{3}} \approx -\frac{1}{2} - i \cdot \frac{\sqrt{3}}{2} \]
These roots are equidistant and symmetrically distributed on the unit circle in the complex plane, forming vertices of a regular polygon.
To find these roots, we express 1 in its polar form as \( e^{i \cdot 2k\pi} \) where \( k \) is an integer. The \( n \)-th roots of unity are then given by:
\[ z_k = e^{i \cdot \frac{2k\pi}{n}} \text{ for } k = 0, 1, ..., n-1 \]For \( n = 3 \), the cube roots of unity are:
\[ z_0 = e^{i \cdot 0} = 1 \]
\[ z_1 = e^{i \cdot \frac{2\pi}{3}} \approx -\frac{1}{2} + i \cdot \frac{\sqrt{3}}{2} \]
\[ z_2 = e^{i \cdot \frac{4\pi}{3}} \approx -\frac{1}{2} - i \cdot \frac{\sqrt{3}}{2} \]
These roots are equidistant and symmetrically distributed on the unit circle in the complex plane, forming vertices of a regular polygon.
Complex Plane
The complex plane is a two-dimensional plane used to visualize complex numbers. It consists of a horizontal axis (real axis) and a vertical axis (imaginary axis).
Each complex number \( z = a + bi \) is represented as a point \( (a, b) \) on this plane:
Each complex number \( z = a + bi \) is represented as a point \( (a, b) \) on this plane:
- The horizontal axis represents the real part \( a \).
- The vertical axis represents the imaginary part \( b \).
- \( z_0 = 1 \) lies on the positive real axis.
- \( z_1 = -\frac{1}{2} + i \cdot \frac{\sqrt{3}}{2} \) is plotted above the real axis, forming a 120° angle with it.
- \( z_2 = -\frac{1}{2} - i \cdot \frac{\sqrt{3}}{2} \) is plotted below the real axis, forming a 240° angle with it.