/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A circular garden bed of radius ... [FREE SOLUTION] | 91Ó°ÊÓ

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A circular garden bed of radius \(1 \mathrm{~m}\) is to be planted so that \(N\) seeds are uniformly distributed oser the circular area. Then we can talk about the number \(n\) of seeds in some particular area \(A\), or we can call \(n / N\) the probability for any one particular seed to be in the area \(A\). Find the probability \(F(r)\) that a seed (that is, some particular seed) is within \(r\) of the center.

Short Answer

Expert verified
The probability \(F(r)\) that a seed is within \(r\) meters of the center is \(r^2\).

Step by step solution

01

Calculate the total area of the circular garden bed

The total area, \(A_{\text{total}}\), of a circle is given by the formula \(A = \pi r^2\). Substituting the radius of the garden bed, which is 1 meter, we find \(A_{\text{total}} = \pi (1)^2 = \pi \).
02

Calculate the area of a circle of radius r within the garden

The area, \(A_r\), of a circle with radius \(r\) is given by \(A = \pi r^2\). This represents the area within which we want to find the probability of a seed falling.
03

Use the probability interpretation

The probability \( F(r) \) that a seed lies within a radius \( r \) is given by the ratio of the area \(A_r \) to the total area \( A_{\text{total}} \). Thus, \( F(r) = \frac{A_r}{A_{\text{total}}} = \frac{\bf{(\bf{\frac{\pi r^2}{\bf{\pi}}}\)}}{\}= }\r^2 \ }.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

circular garden bed
A circular garden bed is essentially a garden patch shaped like a circle. In this problem, the garden bed has a radius of 1 meter. This implies that any point on the boundary of this garden is exactly 1 meter away from its center.

Understanding the structure of the garden bed is crucial. All calculations and probabilities will be based on this circular layout. A circle's geometry simplifies many assumptions and calculations due to its symmetrical properties.

The fundamental attributes of the circle, like its radius and area, will form the basis of our discussion.
uniform distribution of seeds
When we say that seeds are uniformly distributed in the circular garden bed, it means every part of the garden has an equal chance of having seeds.

Imagine spreading seeds evenly across the garden. No matter where you look within the circle, the density of seeds remains consistent.

This uniform spread ensures that the probability calculations remain straightforward. Each section of the garden, regardless of its size, will have a proportionate share of seeds relative to its area.
area calculation
The area is an essential property when dealing with circles. The total area of our circular garden bed can be calculated using the formula for the area of a circle: \[\text{Area} = \pi r^2\].

Given that the radius \((r)\) of the garden is 1 meter:

\[A_{\text{total}} = \pi (1)^2 = \pi \text{ square meters}\]

This area forms the foundation for understanding how seeds are spread across the garden.

Similarly, for a smaller circle within the garden with a radius \((r)\), the area can again be computed using the same formula:

\[A_r = \pi r^2\].
probability within a radius
Probability helps us determine the chance that a particular event will occur. In this case, we are interested in finding the probability \(F(r)\) that a seed lies within a specific radius \((r)\) from the center of the garden.

The method involves comparing the area of the smaller circle (of radius \((r)\)) to the total area of the garden:

\[F(r) = \frac{A_r}{A_{\text{total}}} = \frac{\pi r^2}{\pi} = r^2\]

This result indicates a simple relationship: the probability \(F(r)\) that a seed falls within a radius \((r)\) from the center is directly proportional to \(r^2\). For example, if the radius \(r = 0.5\) meters, then:

\[F(0.5) = (0.5)^2 = 0.25 \(or 25%\)\]

This straightforward formula makes it easy to calculate the probability for any given radius within the circular garden.

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Most popular questions from this chapter

An integer \(N\) is chosen at random with \(1 \leq N \leq 100\). What is the probability that \(N\) is divisible by 11? That \(N>90\) ? That \(N \leq 3\) ? That \(N\) is a perfect square?

(a) Suppose you have two quarters and a dime in your left pocket and two dimes and three quarters in your right pocket. You select a pocket at random and from it a coin at random. What is the probability that it is a dime? (b) Let \(x\) be the amount of money you select. Find \(E(x)\). (c) Suppose you selected a dime in (a). What is the probability that it came from your right pocket? (d) Suppose you do not replace the dime, but select another coin which is also a dime. What is the probability that this second coin came from your right pocket?

'Two people are taking turns tossing a pair of coins; the first person to toss two alike wins. What are the probabilities of winning for the first player and for the second player? Himt: Although there are an infinite number of possibilities here (win on first turn, second turn, third turn, etc.), the sum of the probabilities is a geometric series which can be summed; see Chapter 1 if necessary.

Plot a graph of the binomial frequency function \(f(x)\) for the case \(n=6, p=\frac{1}{6}, q=\frac{5}{6}\), representing the probability of, say, \(x\) aces in 6 throws of a die. Also draw graphs of \(n f(x)\) as a function of \(x / n\), and of \(F(x)\). What is the probability of at least 2 aces out of 6 tosses of a die?

In a box there are 2 white, 3 black, and 4 red balls. If a ball is drawn at random, what is the probability that it is black? That it is not red?

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