/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Which of the following sequence ... [FREE SOLUTION] | 91影视

91影视

Which of the following sequence is incorrec?? (a) \(\mathrm{Sc}, \mathrm{V}, \mathrm{Cr}, \mathrm{Mn}-\) incressing number of oxidarion state (b) \(\mathrm{MO}, \mathrm{M}_{2} \mathrm{O}_{3}, \mathrm{MO}_{2}, \mathrm{MO}_{5}-\) decrcasing basic strcogrh (c) \(\mathrm{d}^{5}, \mathrm{~d}^{3}, \mathrm{~d}^{1}, \mathrm{~d}^{4}\) increasing magnetic moment (d) \(\mathrm{Co}^{2+}, \mathrm{Fe}^{\mathrm{J}+}, \mathrm{Cr}^{3-}, \mathrm{S} c^{3+}\) increasing stability

Short Answer

Expert verified
Option C is incorrect due to the wrong sequence of magnetic moments.

Step by step solution

01

Understanding the Sequences

We need to evaluate each sequence to determine the ordering based on the specified criteria. For option (a), assess if the sequence is ordered by increasing oxidation states. For option (b), verify if it decreases in basic strength. For option (c), check the sequence of increasing magnetic moment based on electron configuration. Lastly, for option (d), determine if stability increases in the given ion list.
02

Evaluate Option A

Option (a) provides a series of transition metals: Scandium (Sc), Vanadium (V), Chromium (Cr), and Manganese (Mn). We need to verify if the oxidation states are in increasing order: Sc typically has +3, V varies but can reach +5, Cr ranges from +2 to +6, and Mn ranges from +2 to +7. Therefore, the order Sc, V, Cr, Mn is correct for increasing oxidation states.
03

Assess Option B

This sequence includes oxides with increasing oxidation states: MO, M鈧侽鈧, MO鈧, MO鈧. As metals increase in oxidation state, their basicity typically decreases, which aligns with the given sequence. Therefore, the sequence is correct for decreasing basicity.
04

Investigate Option C

This involves electron configurations: d鈦, d鲁, d鹿, d鈦. Magnetic moment increases with the number of unpaired electrons, following Hund's rule. So, d鈦 (5 unpaired), d鲁 (3 unpaired), d鹿 (1 unpaired), d鈦 (4 unpaired) should be checked. The sequence of increasing magnetic moment should be d鹿 < d鲁 < d鈦 < d鈦, making this sequence incorrect.
05

Evaluate Option D

Consider the ions: Co虏鈦, Fe鲁鈦, Cr鲁鈦, Sc鲁鈦. The stability of these ions is influenced by stable electron configurations and crystal field considerations. Stability generally increases with higher positive charge and stable electronic configurations. While typically Sc鲁鈦 is most stable followed by Cr鲁鈦, Fe鲁鈦, and Co虏鈦. Therefore, the proposed sequence of increasing stability is incorrect.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation States
Transition metals like Scandium (Sc), Vanadium (V), Chromium (Cr), and Manganese (Mn) exhibit a fascinating property known as oxidation states. Different metals can have a variety of oxidation states, allowing them to participate in various chemical reactions.

Oxidation state is simply the effective charge of an atom within a compound. For example, Scandium typically holds an oxidation state of +3. Vanadium can range from +2 to +5, while Chromium varies from +2 to +6. Manganese stands out with its ability to exhibit numerous states from +2 up to +7. All these options showcase how these metals play dynamic roles in chemistry.

Understanding the varying oxidation states is crucial, as this determines how metals react, their color, and their ability to act as catalysts. The transition from one oxidation state to another often results in distinct changes in these properties.
Basic Strength
Basic strength, in the context of transition metal oxides, refers to the ability of these oxides to react with acids to form water and the metal salt. As metals form oxides with increasing oxidation states, there is typically a decrease in basic strength.

This is observed in the given sequence: MO, M鈧侽鈧, MO鈧, MO鈧. In MO, the metal is in the lowest oxidation state, meaning the oxide still retains some basic character. As the oxygen content increases (e.g., in transition from M鈧侽鈧 to MO鈧), the oxide becomes less basic and more acidic. At the highest oxidation state, such as MO鈧, the basicity is minimal, and such oxides act more like acids.

The logical deduction is that as the oxidation state of metal oxides increases, they become less willing to donate electrons, leading to decreased basicity and an increased tendency toward acidity.
Magnetic Moment
The magnetic moment of transition elements relates directly to the number of unpaired electrons within their d-orbitals. The higher the number of unpaired electrons, the greater the magnetic moment and the magnetic behavior of the substance.

The progression of magnetic moments in the sequence provided: d鈦, d鲁, d鹿, and d鈦, depends on following Hund's rule. A d鈦 configuration, like that in manganese in a high spin state, has five unpaired electrons resulting in a significant magnetic moment. Conversely, d鹿 has only one unpaired electron, resulting in a much smaller magnetic moment.

It's crucial to understand that knowing the electronic configuration and the spin states of these metals lets us predict and rationalize their magnetic properties. This knowledge is vital in various practical applications, such as magnetic materials and catalysts.
Stability of Ions
Ion stability within transition metals is influenced by both electron configurations and the associated energy states. The stability of metal ions often depends on achieving a half-filled or full-filled configuration, which is typically more stable due to symmetrical distribution of electrons.

In the ion series Co虏鈦, Fe鲁鈦, Cr鲁鈦, Sc鲁鈦, the stability usually increases with a higher positive oxidation state, e.g., Cr鲁鈦 is more stable than Co虏鈦 because it's closer to having a half-filled d-orbital. Sc鲁鈦 has a strong +3 charge balanced by its noble gas configuration, making it extremely stable.

It's also important to keep crystal field stabilization in mind, as some configurations help lower the system's overall energy, further granting stability. By understanding these principles, we can predict behaviors in both natural settings and synthetic chemical reactions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which of these pair does not represent any type of constitutional isomerism here? (a) \(\left[\mathrm{Co}\left(\mathrm{N} 1 \mathrm{I}_{3}\right), \mathrm{Br}\right] \mathrm{SO}_{1}\) and \(\left[\mathrm{Co}\left(\mathrm{N} 1 \mathrm{l}_{3}\right)_{5} \mathrm{SO}_{1}\right] \mathrm{Br}\) (b) \(\left[\mathrm{CrCl}\left(\mathrm{H}_{2} \mathrm{O}\right)_{3}\right] \mathrm{Cl}_{2} \cdot \mathrm{H}_{2} \mathrm{O}\) and \(\left[\mathrm{CrCl}_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{4}\right]\) \(\mathrm{Cl}_{2} \mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{Cis}-\left[\mathrm{CrCl}_{2}(\mathrm{Ox})\right]^{3}\) and rrans-[CrCl \(_{2}\) \(\left.(\mathrm{Ox})_{2}\right]^{3}\) (d) \(\left[\operatorname{Pr}\left(\mathrm{NII}_{3}\right)_{4}\right](\mathrm{PtCl})\) and \(\left[\operatorname{Pr}\left(\mathrm{N} 1 \mathrm{I}_{3}\right)_{4} \mathrm{Cl}_{2}\right]\) \(\left(\operatorname{PrCl}_{4}\right)\)

Which is correct abour ED'R \(\Lambda ?\) (a) The abbreviation represents ethylenediamine triacetate. (b) It is flexidentare ligand. (c) The ligand cannor form chelare complexcs. (d) The abbrcviarion stands for cthylencdiaminc rermacctate.

Which of the following is/are not bidcnrate ligands? (a) 1,2 -diamino propane (b) Hydrazinium (c) Cyano (d) Oxalato

The oxidation states of \(C_{O}\) and Cr respectively in the following complex are: \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]\) \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{\mathrm{q}}\right]_{3}\) (a) \(+2,+3\) (b) \(+3,+2\) (c) \(+3,+3\) (d) \(+3,+1\)

Which of rhe following is nor a bidenrare ligand? (a) Acetyl acetonate (acac) (b) Bis (dimethyl glyoximato) system (dmg H) (c) Bis (diphenyl phosphino) ethane (dppe) (d) Glyme, \(\mathrm{CH}_{3} \mathrm{O} \mathrm{CH}_{2} \mathrm{CH}_{2}\) O CH \(_{3}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.