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The specics thar undcrgocs disproportionation in an alkaline modium arc (a) \(\mathrm{Cl}_{2}\) (b) \(\mathrm{MnO}_{d}^{2-}\) (c) \(\mathrm{NO}_{2}\) (d) \(\mathrm{ClO}_{\text {. }}^{-}\)

Short Answer

Expert verified
(a) \(\mathrm{Cl}_2\) and (d) \(\mathrm{ClO}^-\) undergo disproportionation in alkaline medium.

Step by step solution

01

Understanding Disproportionation

Disproportionation is a type of redox reaction in which an element in one oxidation state is simultaneously oxidized and reduced. We need to find the species that can undergo such a reaction in an alkaline medium.
02

Evaluate Disproportionation for Chlorine Gas

For chlorine gas, \[ \mathrm{Cl}_2 + 2 \mathrm{OH}^- \rightarrow \mathrm{Cl}^- + \mathrm{ClO}^- + \mathrm{H}_2\mathrm{O} \]In alkaline medium, chlorine gas disproportionates as shown. It gets both oxidized to hypochlorite ion \(\mathrm{ClO}^-\) and reduced to chloride ion \(\mathrm{Cl}^-\).
03

Evaluate Disproportionation for Permanganate Ion

Permanganate ion \(\mathrm{MnO}_4^{2-}\) is generally stable in alkaline medium and does not disproportionate. Therefore, \(\mathrm{MnO}_4^{2-}\) does not undergo disproportionation in such a condition.
04

Evaluate Disproportionation for Nitrogen Dioxide

Nitrogen dioxide \(\mathrm{NO}_2\) does not undergo disproportionation in an alkaline medium. Instead, it tends to form nitrogen oxides or other compounds, so it doesn't fit the criterion of disproportionation in this context.
05

Evaluate Disproportionation for Hypochlorite Ion

Hypochlorite ion \(\mathrm{ClO}^-\) can disproportionate in alkaline medium:\[ 3 \mathrm{ClO}^- \rightarrow 2 \mathrm{Cl}^- + \mathrm{ClO}_3^- \]Here, the hypochlorite ion is reduced to chloride ion and oxidized to chlorate ion \(\mathrm{ClO}_3^-\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Redox Reactions
Redox reactions, short for reduction-oxidation reactions, are chemical processes where oxidation and reduction occur simultaneously. In these reactions, the oxidation state of elements changes. Oxidation refers to the loss of electrons, while reduction means the gain of electrons. This electron transfer is what drives the reactions and changes the substances involved.
In a disproportionation reaction, which is a special kind of redox reaction, a single element in one oxidation state is both oxidized and reduced. Such reactions are intriguing because they involve the same substance undergoing two different transformations. Identifying elements that can exist in multiple oxidation states is crucial in predicting disproportionation reactions.
Understanding these foundational concepts helps in comprehending broader chemical processes like those in industrial applications, biological systems, and environmental chemistry.
Alkaline Medium
An alkaline solution is a medium with a pH greater than 7, meaning it has excess hydroxide ions (\(\mathrm{OH}^-\)). Such conditions significantly influence the behavior of chemical reactions, including redox and disproportionation reactions.
In the context of a disproportionation reaction, the presence of hydroxide ions can either stabilize or destabilize certain ions or molecules, influencing their tendency to disproportionate. The alkaline medium is often a factor when determining the fate of reactive species. For instance, the \(\mathrm{Cl_2}\) undergoes disproportionation in an alkaline medium to form chloride (\(\mathrm{Cl^-}\)) and hypochlorite (\(\mathrm{ClO^-}\)).
Studying reactions in alkaline conditions is essential for chemistry fields such as environmental science, where understanding the behavior of pollutants or active compounds in different pH conditions is critical.
Chlorine Chemistry
Chlorine is a versatile element found in many chemical reactions, particularly redox reactions. It can exist in multiple oxidation states from -1 to +7, allowing it to partake in a variety of chemical processes. This variability makes chlorine a key player in reactions such as disproportionation.
In alkaline conditions, chlorine gas (\(\mathrm{Cl_2}\)) undergoes disproportionation, resulting in the formation of chloride (\(\mathrm{Cl^-}\)) and hypochlorite ions (\(\mathrm{ClO^-}\)). This process is critical in chlorine chemistry and has substantial applications in the production of cleaning agents and disinfectants.
Understanding the nuances of chlorine chemistry aids in grasping broader concepts in industrial chemistry, including the manufacturing of bleaches and the treatment of drinking water through chlorination.
Permanganate Ion Stability
The permanganate ion, \(\mathrm{MnO_4^-}\), is a well-known oxidizing agent in chemistry, particularly stable under alkaline conditions. In most cases, it does not undergo disproportionation. Instead, it participates in other types of reactions, where it typically gets reduced due to its high oxidation state of +7.
Its stability and oxidative properties make it valuable in various chemical analyses and reactions, such as in titrations to determine the concentration of certain substances.
Recognizing the stability of the permanganate ion in different conditions is central to leveraging its reactivity in laboratory and industrial processes.
Hypochlorite Ion
The hypochlorite ion, \(\mathrm{ClO^-}\), plays a crucial role in disproportionation reactions under alkaline conditions. It is a reactive ion, readily undergoing disproportionation to form chloride (\(\mathrm{Cl^-}\)) and chlorate (\(\mathrm{ClO_3^-}\)) ions. This reaction is notable because it illustrates the transformation of one species into two distinct forms.
Hypochlorite is widely used for its bleaching and disinfecting properties, being a key component in household bleach. Its ability to undergo disproportionation under certain conditions underpins its versatile use and importance in maintaining hygiene standards in both household and industrial settings.
Exploring the chemistry of hypochlorite aids in understanding its applications as well as its behavior in environmental and biological systems.
Chlorate Formation
Chlorate ions (\(\mathrm{ClO_3^-}\)) are formed as a product of hypochlorite ion disproportionation in alkaline conditions. The formation of chlorate is an example of how seemingly simple ions can transform into more complex ions under certain chemical conditions.
Chlorate compounds are known for their strong oxidizing properties. They are widely used in industrial applications, including the manufacturing of explosives, matches, and herbicides.
By understanding the process through which chlorates are formed, chemists can better harness these reactions in commercial and industrial processes, ensuring efficiency and safety in applications where chlorates' properties are desirable.

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Most popular questions from this chapter

Concentrated hydrochloric acid whea kept in open air sometimes produces a cloud of white fumes. The explanation for it is that (a) strong affinity of HCI gas for moisture in air results in formation of droplets of liquid solution which appeas like a cloudy \(\mathbf{s m o k e} .\) (b) oxygen in air reacts wirh rhe emirred \(\mathrm{HCl}\) gas ro form a cloud of chlorinc gas. (c) due ro srrong affinity for water, concentrarct hytrochloric acid pulls moisrure of air rowards irsclf. This moisture forms troplcrs of warcr and hence rhe cloud. (d) concentrared hydrochloric acid emits strongly smelling \(\mathrm{HCl}\) gas all the time.

A yellow metallic powder is buent in a stream of fluorine to obtain a colourless gas \((A)\) which is thermally stable and chemically inert. Its molecule has octahedral geometry. Anocher colourless gas (B) with same constituenc atoms as that of \((\Lambda)\) is obtained when sulphur dichloride is heated with sodium fluoride. Its molecule has trigonal bipyramidal geomecry, Gases \((\Lambda)\) and (B) are, respectively (a) \(\mathrm{SF}_{6}\) and \(\mathrm{SF}_{4}\) (b) \(\mathrm{SF}_{4}\) and \(\mathrm{SF}_{6}\) (c) \(\mathrm{SF}_{4}\) and \(\mathrm{S}_{2} \mathrm{~F}_{2}\) (d) \(\mathrm{KCl}\) and \(\mathrm{KBr}\)

Hypo is used in photography for (a) developing piccure (b) picrurc printing (c) colouring of rhe picrure (d) fixarion of rhe picrure

In which of the following pairs both members show reducing property but not oxidizing property? (a) \(\mathrm{H}_{3} \mathrm{PO}_{2}, \mathrm{H}_{2} \mathrm{~S}\) (b) \(\mathrm{PH}_{3}, \mathrm{H}_{2} \mathrm{~S}\) (c) \(11_{2} \mathrm{~S}, 11_{2} \mathrm{O}_{2}\) (d) \(\mathrm{SO}_{2}, \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}\)

The final acid obrained during rhe manufacrure of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) by contacr proccss is (a) \(\mathrm{H}_{2} \mathrm{SO}_{4}\), dil.) (b) \(\mathrm{H}_{2} \mathrm{~S}_{2} \mathrm{O}_{+}\) (c) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (conc.) (d) \(\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{dil})\)

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