/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 The addition of a catalyst incre... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The addition of a catalyst increases the rate of the reaction but not the equilibrium constant. True/False

Short Answer

Expert verified
True. A catalyst increases the reaction rate but does not change the equilibrium constant.

Step by step solution

01

Understanding the Statement

The problem asks whether adding a catalyst affects the reaction's rate and the equilibrium constant. A catalyst is a substance that speeds up a chemical reaction without being consumed by the reaction.
02

Identifying Catalyst Effect on Reaction Rate

A catalyst provides an alternative reaction pathway with a lower activation energy, increasing the reaction rate. This means that it allows the reaction to reach equilibrium faster.
03

Analyzing Catalyst Effect on Equilibrium Constant

The equilibrium constant ( K eq) is dependent only on temperature for a given reaction and not on the rate at which equilibrium is achieved. Hence, a catalyst does not change the equilibrium constant, only the rate at which equilibrium is reached.
04

Interpreting the Statement

Given that a catalyst increases the rate of the reaction but has no effect on the equilibrium constant, the statement given in the problem is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Rate
In chemistry, the reaction rate refers to how quickly or slowly a chemical reaction occurs. It is often expressed as the change in concentration of a reactant or product per unit time. The rate of reaction can be influenced by various factors including temperature, concentration of reactants, presence of a catalyst, and surface area of the reactants.
A catalyst plays an important role in altering the reaction rate. By providing an alternative pathway with a lower activation energy, a catalyst increases the reaction rate without being consumed in the process.
  • Temperature: Higher temperatures increase reaction rates as particles move faster and collide more frequently.
  • Concentration: Greater concentrations of reactants increase the likelihood of collisions, speeding up the reaction.
  • Catalysts: Catalysts are substances that alter how quickly reactions occur without being altered themselves.
Understanding these factors helps in controlling reaction rates, enabling desired reactions to proceed at an optimal pace either in industrial processes or lab experiments.
Equilibrium Constant
The equilibrium constant, denoted as \( K_{eq} \), is a numerical value that characterizes the equilibrium of a chemical reaction at a given temperature. It helps determine the extent of a reaction and whether products or reactants are favored at equilibrium. At equilibrium, the rate of the forward reaction equals the rate of the reverse reaction.
The value of the equilibrium constant is affected only by changes in temperature, not by concentrations of reactants or products, nor by the presence of a catalyst. This is because catalysts speed up both the forward and reverse reactions equally, allowing equilibrium to be reached faster, but without changing the position of equilibrium itself.
  • Favoring Products: If \( K_{eq} \) is greater than 1, products are favored at equilibrium.
  • Favoring Reactants: If \( K_{eq} \) is less than 1, reactants are favored at equilibrium.
  • Temperature Effect: Only changes in temperature can alter \( K_{eq} \).
Understanding \( K_{eq} \) is crucial in predicting the concentrations of substances at equilibrium in chemical reactions.
Activation Energy
Activation energy is the minimum energy required for a reaction to take place. It acts like an energy barrier that reactants need to overcome during a chemical reaction. A higher activation energy means that fewer molecules will have enough energy to react, resulting in a slower reaction rate.
Catalysts play a crucial role in decreasing the activation energy required for reaction processes. They provide an alternative pathway for the reaction, which requires less energy, thereby increasing the rate at which the reaction occurs.
  • Energy Barrier: Catalysts lower the energy barrier, making it easier for reactions to occur.
  • Reaction Profile: With a catalyst, the peak of the energy barrier in the reaction profile is lowered.
  • Temperature Influence: Lowering the activation energy can make reactions more feasible at lower temperatures.
The concept of activation energy is essential for understanding how and why reactions speed up in the presence of catalysts, making them invaluable in industrial and biochemical processes.

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Most popular questions from this chapter

The activation energy for proline isomerization of a peptide depends on the identity of the preceding residue and obeys Arrhenius rate behavior. Experiments are conducted on the isomerization of an alanineproline peptide. At \(25^{\circ} \mathrm{C}(298 \mathrm{~K})\) the observed rate constant is \(0.05 \mathrm{sec}^{-1}\) and the value of \(E_{\mathrm{A}}\) is calculated to be \(60 \mathrm{~kJ} \mathrm{~mol}^{-1}\). What is the value of the preexponential factor \((A)\) ? Similar measurements are performed on a phenylalanine-proline peptide at \(25^{\circ} \mathrm{C}\), with a measured rate constant of \(0.005 \mathrm{sec}^{-1}\). Assuming an identical preexponential factor as the alanine-proline peptide, what is the activation energy for this peptide?

The rate constant for a -order elementary reaction is \(\mathrm{M}^{-1} \cdot \mathrm{Sec}^{-1}\).

The probability of a bimolecular reaction occurring is related to the rate of collisions between the two species of molecules. True/False

An experiment is performed to measure the affinity of the human proline isomerase hCypA to the inhibitor cyclosporin, analogous to the experiments described for imatinib in this chapter. At \(25 \mu \mathrm{M}\) cyclosporin, the value of \(k_{\text {obs }}\) is measured to be \(12.55 \mathrm{sec}^{-1}\). Given that the offrate is \(0.01 \mathrm{sec}^{-1}\), what is the on-rate?

The most basic step used to describe a reaction process is: a. The transition state. b. An elementary reaction. c. A unimolecular reaction. d. The steady state. e. The equilibrium rate.

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