Chapter 8: Problem 5
\((1-3 i)^{2}\)
Short Answer
Expert verified
The result is \(-8 - 6i\).
Step by step solution
01
Understand the Expression
The expression \((1-3i)^2\) involves a complex number \(1-3i\), which needs to be squared. Squaring a complex number is analogous to squaring a binomial.
02
Apply the Binomial Theorem
To square the expression \((a+bi)^2\), we use the identity: \((a+bi)^2 = a^2 + 2abi + (bi)^2\). In our case, \(a = 1\) and \(b = -3\). So, the expression becomes \((1)^2 + 2(1)(-3)i + (-3i)^2\).
03
Calculate Each Term Separately
1. Calculate \(a^2 = 1^2 = 1\).2. Calculate \(2abi = 2(1)(-3)i = -6i\).3. Calculate \((bi)^2 = (-3i)^2 = (-3)^2(i^2) = 9(-1) = -9\).
04
Combine the Results
Now, combine the calculated results: \[1 - 6i - 9\]Combine similar terms, which gives: \[1 - 9 - 6i = -8 - 6i\].
05
Write the Final Answer
The simplified form of \((1-3i)^2\) is: \[-8 - 6i\].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Squaring Complex Numbers
To square a complex number like \((1-3i)^2\), we must approach the problem similarly to squaring binomials in algebra. A complex number has the form \(a + bi\), where \(a\) is the real part and \(bi\) is the imaginary part. In our exercise, \(a = 1\) and \(b = -3\). The square of a complex number is found using:
- \((a + bi)^2 = a^2 + 2abi + (bi)^2\)
Binomial Theorem
The binomial theorem is a powerful tool that extends beyond real numbers and helps simplify operations with complex numbers. It provides a formula to expand expressions that are raised to a power, specifically in the form \((a + b)^n\). When n equals 2, as in our expression \((1-3i)^2\), the binomial theorem simplifies our task.
- For any complex number \((a + bi)^2\), it expands into \(a^2 + 2abi + (bi)^2\).
- The square of the real part, \(a^2\),
- The product of the real and imaginary parts multiplied by 2, \(2abi\),
- And the square of the imaginary part, \((bi)^2\)
Complex Number Arithmetic
Complex number arithmetic often involves operations similar to those with real numbers, but with added rules due to the imaginary unit \(i\), where \(i^2 = -1\). In our squared expression \((1-3i)^2\), we used arithmetic operations such as multiplication, addition, and subtraction.
- First, we calculated the square of the real part, \(1^2 = 1\).
- Next, the multiplication of the parts combined by two: \(2 \times 1 \times (-3)i = -6i\).
- The square of the imaginary part involved dealing with the imaginary unit: \((-3i)^2 = 9(i^2) = 9(-1) = -9\).
- Add and simplify real terms to get: \(1 - 9 = -8\)
- Combine the imaginary part: \(-8 - 6i\)