Chapter 7: Problem 52
Find the radius of convergence of each of the following series: \(\sum_{m=0}^{\infty} \frac{x^{m}}{4^{m}}\)
Short Answer
Expert verified
The radius of convergence is 4.
Step by step solution
01
Identify the General Form of the Series
The given series is \(\sum_{m=0}^{\infty} \frac{x^{m}}{4^{m}}\). This is a power series of the form \(\sum_{m=0}^{\infty} a_m x^m\), where \(a_m = \frac{1}{4^m}\).
02
Recognize the Standard Form
The series can be rewritten as \(\sum_{m=0}^{\infty} \left( \frac{x}{4} \right)^m\). This is a geometric series with common ratio \(r = \frac{x}{4}\).
03
Use the Geometric Series Convergence Condition
For the geometric series \(\sum_{m=0}^{\infty} r^m\) to converge, the common ratio \(r\) must satisfy \(|r| < 1\).
04
Apply the Convergence Condition
In this series, \(r = \frac{x}{4}\). Therefore, the condition for convergence is \(\left| \frac{x}{4} \right| < 1\).
05
Solve the Inequality for \(x\) to Find the Radius
Solve \(\left| \frac{x}{4} \right| < 1\), which gives \(|x| < 4\). This means the radius of convergence \(R\) is 4.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Power Series
A power series is an infinite sum of terms in the form \(a_m x^m\), where \(a_m\) are coefficients and \(x\) is a variable. Think of it like a polynomial, but with infinitely many terms. Power series can represent many functions, and their usefulness includes approximating functions and analyzing their behavior. They depend on the variable \(x\) and a point where the series is centered. For example, the series given by
- \(\sum_{m=0}^{\infty} \frac{x^m}{4^m}\)
Exploring Geometric Series
A geometric series is a special type of power series where each term is obtained by multiplying the previous term by a constant factor, called the common ratio \(r\). Formally, a geometric series can be written as:
- \(\sum_{m=0}^{\infty} ar^m\)
- \(\left( \frac{x}{4} \right)^m\)
Applying Convergence Criteria
To determine if a series converges, we apply specific criteria. For geometric series, the key criterion is that the series converges if the magnitude of the common ratio \(|r|\) is less than 1. This is a simple inequality:
- \(|r| < 1\)
- \(|\frac{x}{4}| < 1\)
- \(|x| < 4\)