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Given that \(x-1\) is a factor of the cubic, (i) find the roots, (ii) sketch the graph:\(x^{3}-3 x^{2}+3 x-1\)

Short Answer

Expert verified
Root is \(x = 1\) with multiplicity 3; graph touches x-axis at this root.

Step by step solution

01

Understand the Given Polynomial

We have a cubic polynomial: \(x^3 - 3x^2 + 3x - 1\). We are told that \(x - 1\) is a factor of this polynomial.
02

Factor the Polynomial

The factor theorem tells us that if \(x - 1\) is a factor, then substituting \(x = 1\) into the polynomial should give 0. So we test it: \(1^3 - 3(1)^2 + 3(1) - 1 = 0\). To factor \(x^3 - 3x^2 + 3x - 1\), perform synthetic division or polynomial division by \(x - 1\).
03

Perform Synthetic Division

Perform synthetic division of \(x^3 - 3x^2 + 3x - 1\) by \(x - 1\):\[\begin{array}{r|rrrr}1 & 1 & -3 & 3 & -1 \ & & 1 & -2 & 1 \\hline & 1 & -2 & 1 & 0 \\end{array}\] The quotient is \(x^2 - 2x + 1\), and the remainder is 0.
04

Factor the Quotient

The quotient obtained, \(x^2 - 2x + 1\), can be factored further. Notice that it matches the perfect square formula: \(x^2 - 2x + 1 = (x - 1)^2\). Thus the polynomial can be written as \((x-1)^3\).
05

Find All Roots

Since \(x^3 - 3x^2 + 3x - 1 = (x-1)^3\), the root of the polynomial is \(x = 1\) with a multiplicity of 3.
06

Sketch the Graph

The cubic polynomial \((x-1)^3\) touches the x-axis at \(x = 1\) and exhibits a behavior similar to \(y = x^3\) at that point. The curve will flatten and then gently curve away, all happening at the root, \(x = 1\). This shows it has a turning point at \(x = 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factor Theorem
The Factor Theorem is a crucial part of understanding polynomials, especially when it comes to finding their roots. It states that if a polynomial \( f(x) \) has a factor \( (x - a) \), then \( f(a) = 0 \). In simple terms, this means that when you substitute \( a \) into the polynomial, the result should be zero. This gives us a powerful tool for finding the roots of a polynomial.

Let's apply this to our polynomial \( x^3 - 3x^2 + 3x - 1 \). We are informed that \( x - 1 \) is a factor. Using the Factor Theorem, we check by substituting \( x = 1 \) into the polynomial:
- \( 1^3 - 3(1)^2 + 3(1) - 1 = 0 \).

The result is zero, confirming that \( (x - 1) \) is indeed a factor. Thus, the root \( x = 1 \) exists for the polynomial.
Synthetic Division
Synthetic Division is a fast and efficient method of dividing polynomials, commonly used when dividing by a linear factor. It simplifies the division process, eliminating variables and reducing complex calculations.

To use Synthetic Division for \( x^3 - 3x^2 + 3x - 1 \) by \( x - 1 \), we set it up as follows, using the coefficients of the polynomial:
- Write down 1 (from \( x-1 \)) to the left.
- Draw a horizontal and vertical line to separate the workspace.
- Write the coefficients 1, -3, 3, -1 beside the vertical line.
- Perform the calculations:
- Bring down the first coefficient (1).
- Multiply by the number on the left (1), add to the next coefficient (-3 + 1 = -2), repeat for all coefficients.
- The last number gives the remainder, which should be zero if \( x-1 \) is a factor.

After completing these steps, the resulting quotient is \( x^2 - 2x + 1 \), indicating successful division.
Multiplicity of Roots
Understanding the multiplicity of roots is essential for analyzing polynomial behavior. A root's multiplicity indicates how many times it appears as a solution.

For the polynomial \( x^3 - 3x^2 + 3x - 1 \), we found that it can be expressed fully as \((x-1)^3\). This indicates that the root \( x = 1 \) has a multiplicity of 3.

Multiplicity affects how the graph behaves at the root:
- If a root has odd multiplicity, the graph will cross the x-axis at the root point.
- If even, the graph only touches or bounces off the x-axis.

In our scenario, since the multiplicity is odd (3), the graph flattens as it passes through the x-axis around \( x = 1 \). This makes the turning point at this root very gentle.

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