/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Find the roots and sketch the gr... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the roots and sketch the graphs of the quadratic functions:\(3 x^{2}-3 x-1\)

Short Answer

Expert verified
Roots are \(x = \frac{3 + \sqrt{21}}{6}\) and \(x = \frac{3 - \sqrt{21}}{6}\); graph is an upward-opening parabola.

Step by step solution

01

Identify the Quadratic Equation Format

The given equation is in the standard quadratic form \(ax^2 + bx + c = 0\). In the equation \(3x^2 - 3x - 1 = 0\), we have \(a = 3\), \(b = -3\), and \(c = -1\).
02

Calculate the Discriminant

To find the roots, first calculate the discriminant \(\Delta = b^2 - 4ac\). Substituting the values, we get \((-3)^2 - 4 \cdot 3 \cdot (-1) = 9 + 12 = 21\). Since the discriminant is positive, there will be two distinct real roots.
03

Find the Roots Using the Quadratic Formula

The quadratic formula \(x = \frac{-b \pm \sqrt{\Delta}}{2a}\) provides the roots. Substituting the known quantities, \(x = \frac{-(-3) \pm \sqrt{21}}{2 \cdot 3}\) simplifies to \(x = \frac{3 \pm \sqrt{21}}{6}\). Therefore, the roots are \(x = \frac{3 + \sqrt{21}}{6}\) and \(x = \frac{3 - \sqrt{21}}{6}\).
04

Determine the Vertex of the Parabola

The vertex \((h, k)\) of a quadratic function \(ax^2 + bx + c\) is given by \(h = -\frac{b}{2a}\). For this quadratic, \(h = \frac{-(-3)}{2 \cdot 3} = \frac{3}{6} = \frac{1}{2}\). Substitute this back into the original equation to find \(k: k = 3\left(\frac{1}{2}\right)^2 - 3\left(\frac{1}{2}\right) - 1 = \frac{3}{4} - \frac{3}{2} - 1 = -\frac{7}{4}\). Thus, the vertex is \(\left(\frac{1}{2}, -\frac{7}{4}\right)\).
05

Sketch the Graph

The graph of a quadratic function is a parabola. Since \(a = 3 > 0\), the parabola opens upwards. Plot the vertex \(\left(\frac{1}{2}, -\frac{7}{4}\right)\), and indicate the roots on the x-axis where the parabola crosses the axis: \(x = \frac{3 + \sqrt{21}}{6}\) and \(x = \frac{3 - \sqrt{21}}{6}\). Connect these points to sketch the parabolic shape.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discriminant
In quadratic equations, the discriminant plays a crucial role in determining the nature of the roots. The discriminant is given by the formula \( \Delta = b^2 - 4ac \). It serves as an indicator of how the parabola intersects the x-axis, if at all.

For the quadratic equation \(3x^2 - 3x - 1 = 0\), the discriminant is calculated as follows:
  • \(a = 3\)
  • \(b = -3\)
  • \(c = -1\)
Substitute these values to get \((-3)^2 - 4 \cdot 3 \cdot (-1) = 9 + 12 = 21\).
This positive value implies two distinct real roots exist, indicating the parabola will intersect the x-axis at two points.
Quadratic Formula
The quadratic formula is a powerful tool for finding the roots of any quadratic equation. It is given by \( x = \frac{-b \pm \sqrt{\Delta}}{2a} \), where \(\Delta\) is the discriminant. This formula provides a straightforward method to solve any quadratic equation.

For our example \(3x^2 - 3x - 1 = 0\), we substitute the values:
  • \(b = -3\)
  • \(\Delta = 21\)
  • \(a = 3\)
This results in: \[x = \frac{-(-3) \pm \sqrt{21}}{2 \times 3}\]Solving this gives two roots:
  • \(x = \frac{3 + \sqrt{21}}{6}\)
  • \(x = \frac{3 - \sqrt{21}}{6}\)
These represent the points where the parabola crosses the x-axis.
Parabola
Graphically, every quadratic equation corresponds to a parabola. A parabola is a symmetric curve and the shape of its graph depends on the coefficient \(a\) in the equation \(ax^2 + bx + c\).

If \(a > 0\), the parabola opens upwards like a smile; if \(a < 0\), it opens downwards like a frown. In our example, the coefficient \(a = 3\) is positive, so the parabola opens upwards.
Understanding the direction and position of the parabola helps in sketching it and knowing where it meets the x-axis—i.e., at the roots.
Vertex
The vertex of a parabola is its highest or lowest point, depending on whether it opens upwards or downwards. The coordinates of the vertex \((h, k)\) are calculated using:
  • \(h = -\frac{b}{2a}\)
  • \(k = ax^2 + bx + c\) evaluated at \(x = h\)
For \(3x^2 - 3x - 1 = 0\), we find:
  • \(h = -\frac{-3}{2 \times 3} = \frac{1}{2}\)
  • Substituting \(h\) in the equation gives \(k = 3\left(\frac{1}{2}\right)^2 - 3\left(\frac{1}{2}\right) - 1 = -\frac{7}{4}\)
Hence, the vertex is \(\left(\frac{1}{2}, -\frac{7}{4}\right)\). This point is a critical feature used to draw the parabola and understand its minimum value since it opens upward.
Real Roots
Real roots of a quadratic function are the x-values where the parabola intersects the x-axis. The presence of real roots entirely depends on the discriminant:
  • If \(\Delta > 0\), there are two distinct real roots.
  • If \(\Delta = 0\), there is one real root, which means the parabola touches the x-axis at the vertex.
  • If \(\Delta < 0\), there are no real roots, and the parabola does not intersect the x-axis.
For the equation \(3x^2 - 3x - 1 = 0\), with \(\Delta = 21\) (which is greater than zero), two real roots exist:
  • \(x = \frac{3 + \sqrt{21}}{6}\)
  • \(x = \frac{3 - \sqrt{21}}{6}\)
These roots confirm the parabola intersects the x-axis at the calculated points.

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