(i) Show that a square matrix \(\mathbf{A}\) and its transpose
\(\mathbf{A}^{\top}\) have the same set of eigenvalues.
(ii) Show that the following two equations are equivalent:
$$
\mathbf{A}^{\top} \mathbf{y}=\lambda \mathbf{y}, \quad \mathbf{y}^{\top}
\mathbf{A}=\lambda \mathbf{y}^{\top}
$$
The eigenvectors of \(\mathbf{A}^{\top}\) are in general different from those of
\(\mathbf{A}\) (unless \(\mathbf{A}\) is symmetric). The vector \(\mathbf{y}\) is
sometimes called a left-eigenvector of \(\mathbf{A}\), and an 'ordinary'
eigenvector \(\mathbf{x}\) of \(\mathrm{A}\) is then called a right-eigenvector.
(iii) Find the eigenvalues and corresponding normalized right- and left-
eigenvectors of
$$
\mathbf{A}=\left(\begin{array}{ll}
3 & 2 \\
0 & 2
\end{array}\right).
$$