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In each pair of aqueous systems, which will have the higher boiling point? a. pure water or a \(1.0 \mathrm{M} \mathrm{NaCl}\) b. \(1.0 \mathrm{M} \mathrm{NaCl}\) or \(1.0 \mathrm{M} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\) c. \(1.0 \mathrm{M} \mathrm{CaCl}_{2}\) or \(1.0 \mathrm{M}\left(\mathrm{NH}_{4}\right)_{3} \mathrm{PO}_{4}\)

Short Answer

Expert verified
NaCl solution, NaCl solution, and (NH鈧)鈧働O鈧 solution have higher boiling points respectively.

Step by step solution

01

Understand Boiling Point Elevation

The phenomenon of boiling point elevation is when the boiling point of a liquid (solvent) increases when a solute is added. It is related to the number of particles in the solution and is given by the formula: \[ \Delta T_b = i \cdot K_b \cdot m \]where \( \Delta T_b \) is the boiling point elevation, \( i \) is the van't Hoff factor (number of particles the solute separates into), \( K_b \) is the ebullioscopic constant, and \( m \) is the molality of the solution.
02

Comparing Pure Water vs. 1.0 M NaCl

Pure water has a boiling point of 100掳C, but when a solute like NaCl is added, the boiling point increases. NaCl dissociates into Na鈦 and Cl鈦, so its van't Hoff factor \( i \) is 2. Thus, a 1.0 M NaCl solution has a higher boiling point than pure water due to the presence of solute particles.
03

Comparing 1.0 M NaCl vs. 1.0 M Glucose (C鈧咹鈧佲倐O鈧)

Glucose (C鈧咹鈧佲倐O鈧) does not dissociate in solution since it is a non-electrolyte, so its van't Hoff factor \( i \) is 1. Since NaCl dissociates into two ions, it has more solute particles per unit volume, leading to a higher boiling point for 1.0 M NaCl compared to 1.0 M glucose under the same conditions.
04

Comparing 1.0 M CaCl鈧 vs. 1.0 M (NH鈧)鈧働O鈧

CaCl鈧 dissociates into three ions: one Ca虏鈦 and two Cl鈦, giving it a van't Hoff factor of 3. (NH鈧)鈧働O鈧 dissociates into four ions: three NH鈧勨伜 and one PO鈧劼斥伝, resulting in a van't Hoff factor of 4. Since (NH鈧)鈧働O鈧 has a higher van't Hoff factor, it will cause a greater boiling point elevation than CaCl鈧 for the same molality.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

van't Hoff factor
The van't Hoff factor (\( i \)) is a crucial component when it comes to understanding how solutes affect boiling point elevation in solutions. It essentially tells us how many particles a substance separates into when dissolved in a solvent. This factor plays a significant role in colligative properties, such as boiling point elevation.

To determine the van't Hoff factor, we need to look at the solute's nature:
  • For non-electrolytes, which do not dissociate, the van't Hoff factor is typically 1.
  • For electrolytes, which dissociate into ions, the van't Hoff factor is greater than 1. Each type of electrolyte will have a characteristic factor depending on its dissociation pattern.
For example, NaCl, a common salt, dissociates into two ions: Na鈦 and Cl鈦, giving it a van't Hoff factor of 2. On the other hand, more complex ionic compounds, like \((\text{NH}_4)_3\text{PO}_4\), dissociate into four ions: three \(\text{NH}_4^+\) and one \(\text{PO}_4^{3-}\), resulting in a factor of 4. The higher the van't Hoff factor, the greater the number of particles, and hence the greater the colligative effect.
aqueous solutions
Aqueous solutions are solutions where water acts as the solvent. These solutions are vital in many scientific and everyday processes. Understanding how solutes impact aqueous solutions is essential, especially in terms of boiling and freezing point changes.

Water, being a polar solvent, dissolves a variety of substances:
  • Ionic compounds, like NaCl or CaCl鈧, dissolve by separating into their respective ions due to water's polar nature.
  • Non-ionic compounds, like sugar, dissolve not by dissociation into ions, but rather by spreading out as whole molecules amidst the water molecules.
In terms of boiling point elevation, aqueous solutions behave differently from their pure counterparts. The addition of a solute causes the boiling point to increase because the solute particles disrupt the structure of the liquid, requiring more energy (i.e., a higher temperature) to transition into the gaseous state. This concept is clearly seen when comparing the boiling points of pure water with solutions like 1.0 M \(\text{NaCl}\) (which elevates the boiling point significantly due to ion formation) and solutions like 1.0 M glucose (with a lesser effect as it doesn鈥檛 dissociate into ions).
colligative properties
Colligative properties are unique because they depend only on the number of solute particles, not their identity. These properties affect boiling point elevation, freezing point depression, vapor pressure lowering, and osmotic pressure.

When solving a problem involving boiling point elevation, it鈥檚 essential to consider:
  • The concentration of the solution, as higher molality leads to greater colligative effects.
  • The van't Hoff factor, since a higher factor increases the effect by increasing the total number of solute particles in the solution.
For example, in boiling point elevation, the equation \(\Delta T_b = i \cdot K_b \cdot m\) captures these elements. \(\Delta T_b\) defines the increase in boiling point temperature, \(K_b\) is the ebullioscopic constant of the solvent, and \(m\) is the molality of the solution. This formula puts in perspective the colligative nature of boiling point elevation by showing direct proportionality to the number of particles (via the product \(i \cdot m\)). Therefore, systems with solutes like \((\text{NH}_4)_3\text{PO}_4\) with a high van't Hoff factor, dramatically show elevation as they introduce more particles into the solution compared to solutes with lower dissociation levels.

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