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Referring to Table 28-7, explain how an anion-exchange resin can be used for absorption and analysis of \({\bf{S}}{{\bf{O}}_2}\)released by combustion.

Short Answer

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\({\rm{SO}}_3^{2 - }\) is oxidized to \({\rm{SO}}_4^{2 - }\) by\({{\rm{H}}_2}{{\rm{O}}_2}\). The sulfate is measured by ion chromatography.

Step by step solution

01

Definition of\({\bf{S}}{{\bf{O}}_2}\).

  • Sulfur dioxide (\(S{O_2}\)) is a sulphur oxide and a Sulfonyl group chemical molecule (\(R - S{O_2} - R\))
  • In the field of blood oxygenation, the specific orthogonal group of degree 2 oxygen saturation(SO2)is used.
  • \({S_2}\) (star),also known as\(S{O_2}\),is the name of a star that orbits the central black hole in the centre of the Milky Way galaxy in 16 years.
  • \(S{O_2}\), an Aten asteroid in a co-orbital horseshoe orbit with Earth.
02

Determine the analysis of \({\bf{S}}{{\bf{O}}_2}\)released by combustion

  • Here we will refer to Table \(28 - 7\) in order to explain how an anion-exchange resin could be used for absorption and analysis of \({\rm{S}}{{\rm{O}}_2}\) which is released by combustion.
  • The gas which came from product is passed through an anion exchange column, and \({\rm{S}}{{\rm{O}}_2}\) is absorbed on the gas which can be written by the following reactions:

\({\rm{S}}{{\rm{O}}_2} + {{\rm{H}}_2}{\rm{O}} \to {{\rm{H}}_2}{\rm{S}}{{\rm{O}}_3}{\rm{ }}2{\rm{ resin }}\)

  • The sulfite is eluted with \({\rm{N}}{{\rm{a}}_2}{\rm{C}}{{\rm{O}}_3}/{{\rm{H}}_2}{{\rm{O}}_2}\) solution and is oxidized to sulfate via the solution \({\rm{N}}{{\rm{a}}_2}{\rm{C}}{{\rm{O}}_3}/{{\rm{H}}_2}{{\rm{O}}_2}\)
  • The sulfate is then measured by ion chromatography

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Most popular questions from this chapter

The following wet-ashing procedure was used to measure arsenic in organic soil samples by atomic absorption spectroscopy: A 0.1- to \({\bf{0}}.{\bf{5}} - \)g sample was heated in a \({\bf{150}} - {\bf{mL}}\) Teflon bomb in a microwave oven for \(2.5\;{\rm{min}}\) with \(3.5\;{\rm{mL}}\)of\(70\% \,\,\,{\rm{HN}}{{\rm{O}}_3}\). After the sample cooled, a mixture containing \(3.5\;{\rm{mL}}\)of \(70\% \,\,\,{\rm{HN}}{{\rm{O}}_3},1.5\;{\rm{mL}}\) of\(70\% \,\,{\rm{HCl}}{{\rm{O}}_4}\), and \(1.0\;{\rm{mL}}\) of \({{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}\)was added and the sample was reheated for three \({\bf{2}}.{\bf{5}} - {\bf{min}}\) intervals with 2 -min unheated periods in between. The final solution was diluted with \(0.2{\rm{M}}\,\,\,{\rm{HCl}}\)for analysis. Why was \({\rm{HCl}}{{\rm{O}}_4}\) not introduced until the second heating?

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