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Chapter 9: Q2TY (page 194)

Find the pH of 0.050 M triethylammonium bromide.

Short Answer

Expert verified

The pH value is 6.01

Step by step solution

01

Step 1: Define the term pH.

The negative logarithm of H+ ion concentration is used to calculate pH.

As a result, the meaning of pH is justified as hydrogen power.

02

Calculate the pH

$Given 0.050 M triethylammonium bromide K_{a} = 10^{- {pK}_{a}} = 10^{- 10.72} = 1.9 脳 10^{- 11} {(C_{2} H_{5})}_{3} {NH}^{+} \overset{K_{a}}{饾啅 {(C_{2} H_{5})}_{3} N + H^{+}}^{0.050 - X X X at equilibrium} \frac{[{(C_{2} H_{5})}_{3} N] [H^{+}]}{[{(C_{2} H_{5})}_{3} {NH}^{+}]} = K_{a} \frac{x^{2}}{0.050 - x} = 1.9 脳 10^{- 11} A quadratic equation is used to solve the value of x . x = 9.75 脳 10^{- 7} From the x value the is calculated as pH = - \log [H_{3} O^{+}] = - \log (9.75 脳 10^{- 7}) = 6.01 Thus the PH value is 6.01$

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Most popular questions from this chapter

Find the pH of 0.050 M sodium butanoate (the sodium salt of

butanoic acid, also called butyric acid).

The pH of $0.10$ M ethyl amine is $11.82$

(a) Without referring to Appendix G, find Kb for methyl amine.

(b) Using results from part (a), calculate the pH of $0.10$ M methyl ammonium chloride.

Find the pH of 0.050 M sodium butanoate (the sodium salt ofbutanoic acid, also called butyric acid).

${Cr}^{3 +}$ is acidic by virtue of the hydrolysis reaction ${Cr}^{3 +} H_{2} O \overset{K_{aI}}{鈬�} Cr {(OH)}^{2 +} + H^{+}$ . [Further reactions produce $Cr {(OH)}_{2,}^{+} Cr {(OH)}_{3}$ and.] Find the value role="math" localid="1654864894349" $K_{aI}$ of in Figure 6-9. Considering only the $K_{aI}$ reaction, find pH value ofrole="math" localid="1654865110221" $0.010 MCr {({CIO}_{4})}_{3}$ What fraction of chromium is in the formrole="math" localid="1654865163335" $Cr {(OH)}^{2 +}$ ?

Describe how to prepare 250mLof 1.00M ammonia bufferpH9.00 starting with 28 wt % ${NH}_{3}$ (鈥渃oncentrated ammonium hydroxide鈥� listed on the back inside cover of the book) and 鈥渃oncentrated鈥滺CI(37.2 wt %)or 鈥渃oncentrated鈥� NaOH(50.5wt%)

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