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Chapter 9: Q14P (page 208)

Using activity coefficients, find the pHand fraction of dissociation of 50.0 mM LiBr Take the size of $C_{6} H_{5} O^{-}$ to be 600 pm.

Short Answer

Expert verified

The pH of 50.0 mM hydroxybenzene (phenol) in 0.050 M LiBr is 5.64.

The fraction of dissociation of 50.0 mM hydroxybenzene (phenol) in 0.050 M LiBr is 0.0053%

Step by step solution

01

Step : Definition of pH

pH is defined as a quantitative measure of acidity and basicity.The solutions having less than pH are acidic, and the solutions with pH more than 7 are basic, and the neutral solutions have a pH of 7.

02

Step : Calculation of x value

$K_{a} = \frac{[H^{+}] y (H^{+}) [A^{-}] Y (A^{-})}{[H A] y (H A)} 1.01 脳 10^{- 10} = \frac{(x) (0.86) (x) (0.835)}{(0.05 - x) (1.00)} x = 2.65 脳 10^{- 6}$

03

Step : Calculating and fraction of dissociation

$pH = - \log [H^{+}] y (H^{+}) = - \log ((2.65 脳 10^{- 6}) (0.86)) = 5.64$

$伪 = \frac{[A^{-}]}{[H A] + [A^{-}]} = \frac{2.65 脳 10^{- 6}}{0.05} = 5.3 脳 10^{- 5} 伪 = 0.0053 %$

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Most popular questions from this chapter

Neglecting activity coefficients, calculate the pHof $1.0 脳 10^{- 2} M KOH$

Find theand fraction of dissociation ( a ) of a $0.100 M$ solutionof the weak acid $HA$ with $Ka = 1.00 脳 10^{- 5}$

Use the reaction quotient, Qto explain why the fraction of dissociation of weak acid, HA , increases when the solution is diluted by a factor of 2

Show that the limiting fraction of association of a base in water, as the concentration of base approaches $0, is a = 10^{7} Kb / (1 + 10^{7} K_{b})$ Find the limiting value of $a$ for $K_{b} = 10^{- 4}$ and for $K_{b} = 10^{- 10}$

How many milliliters of $0.246 {MHNO}_{3}$ should be added to $213 mL$ of $0.00666 M 2,$ -bipyridine to give a pH of $4.19$ ?

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