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The total number of moles of solute per litre of solution is known as a solution's molarity. Because, unlike mass, the volume of a system fluctuates with changes in physical conditions, the molality of a solution is affected by changes in physical parameters of the system such as pressure and temperature. Molarity is represented by the letter M, which stands for molar.

The molarity of a solution is defined as one gram of solute dissolved in one litre of solution.

$$\begin{gathered} \mathrm{volume}\mathrm{of}\mathrm{NaOH} \\ \mathrm{Solution}=34.26\mathrm{mL}=0.03426\mathrm{L} \\ \mathrm{mass}\mathrm{of}{\mathrm{H}}_3{\mathrm{NSO}}_3=0.3337\mathrm{g} \\ {\mathrm{FM}}_3\mathrm{of}{\mathrm{H}}_3{\mathrm{NSO}}_3=97.094\mathrm{g}/\mathrm{mol} \\ \mathrm{By}\mathrm{using}\mathrm{the}\mathrm{mole}\mathrm{concept}\mathrm{and}\mathrm{molarity}\mathrm{formula}\mathrm{to}\mathrm{calculate}\mathrm{the}\mathrm{molarity}\mathrm{of}\mathrm{NaOH} \\ {\mathrm{M}}_{\mathrm{NaOH}}=\frac{0.333{\mathrm{gH}}_3{\mathrm{NSO}}_3\left({\displaystyle \frac{1{\mathrm{molH}}_3{\mathrm{NSO}}_3}{97.094{\mathrm{gH}}_3{\mathrm{NSO}}_3}}\right)\left({\displaystyle \frac{1\mathrm{molNaOH}}{1{\mathrm{molH}}_3{\mathrm{NSO}}_3}}\right)}{0.03426\mathrm{L}} \\ =0.1001\frac{\mathrm{molNaOH}}{\mathrm{L}} \\ =0.1001\mathrm{MNaOH} \\ \mathrm{Thus},\mathrm{The}\mathrm{molarity}\mathrm{of}\mathrm{NaOH}\mathrm{is}{\mathrm{M}}_{\mathrm{NAOH}}=0.1001\mathrm{MNaOH} \end{gathered}$$