/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q40P Explain how slinization reduces ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 23: Q40P (page 631)

Explain how slinization reduces tailing of chromatographic peaks.

Short Answer

Expert verified

Silanization creates hydroxyl groups that can form strong hydrogen bonds.

Step by step solution

01

of 2

We will explain how slinization can reduce chromatographic peak tailing in this task.

02

of 2

- the process of applying alkoxysilane molecules to a surface.

- By blocking the silanol groups with nonpolar trimethylsilyl groups, this technique reduces tailing.

- It's called end-capping because silanization can cap hydroxyl groups that can create strong hydrogen bonds, which reduces chromatographic peak tailing.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A chromatogram with ideal Gaussian bands hastr=9minand
w1/2=2min.

(a) How many theoretical plates are present?

(b) Find the plate height if the column is 10cm long.

Which of the following columns will provide:

(a) highest number of plates?

(b) greatest retention?

(c) highest relative retention?

(d) best separation?

Column1:N=1000;k2=3.9;伪=1.16;resolution=0.6Column2:N=5000;k2=3.9;伪=1.06;resolution=0.8Column3:N=500;k2=4.7;伪=1.31;resolution=1.1Column4:N=2000;k2=2.4;伪=1.24;resolution=1.5

The three chromatograms shown here obtained with 2.5, 1.0 and 0.4 渭Lof ethyl acetate injected on the same column under the same conditions. Explain why the peak becomes less symmetrical with increasing sample size.

2.5渭L 1.0L 0.4渭L

23-38. What is the optimal flow rate in Figure 23-17 for best separation of solutes?

Match statements 1鈥�5 with the band broadening terms in the second list.

1. Depends on radius of open tubular column.

2. Not present in an open tubular column.

3. Depends on length and radius of connecting tubing.

4. Increases with diffusion coefficient of solute.

5. Increases with thickness of stationary phase film.

A Multiple paths

B Longitudinal diffusion

Cm Equilibration time in mobile phase

Cs Equilibration time in stationary phase

EC Extra column band broadening
See all solutions

Recommended explanations on Chemistry Textbooks

Organic Chemistry

Read Explanation

Making Measurements

Read Explanation

Chemical Analysis

Read Explanation

Physical Chemistry

Read Explanation

Kinetics

Read Explanation

The Earths Atmosphere

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.