Q24P An aqueous solution containing 2... [FREE SOLUTION]

Chapter 1: Q24P (page 23)

An aqueous solution containing 20.0wt%KI has a density of1.168g/mL. Find the molality (m, not M) of the KI solution.

Short Answer

Expert verified

The molality of the KI solution is $1.51 mol / kg$

Step by step solution

Definition of molality.

The number of moles of solute in a solution equivalent to $1 k g$ or $1000 g$ of asolvent is known as its molality. The definition of molarity, on the other hand, is based on a certain volume of solution.

The molality of KI solution.

To begin, remember that molality, expressed as $m 1$ equals:

$m 1 = \frac{moles of solute (KI)}{mass of solvent (water)}$

It is given that the density of $1.168 g / mL$ which is $1.168 g$ of KI in $1 mL$ of water, is $1168 g$ in 1L

The total mass of the solute (KI) is equal to $0.2 脳 1168 g = 233.6 g$

The total mass of the solvent (water) is equal to $0.8 脳 1168 g = 934.4 g$

Now, calculate the number of moles for KI:

$n (KI) = \frac{m}{M} = \frac{233.6 g}{166 g / mol} = 1.407 mol$

Now, calculate the molality $(m 1)$

$m 1 = \frac{n (KI)}{m (water)} = \frac{1.407 mol}{934.4 g} = 1.51 脳 10^{- 3} mol / g = 1.51 mol / kg$

Hence, the molality is $1.51 mol / kg$

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An aqueous solution containing 20.0wt%KI has a density of1.168g/mL. Find the molality (m, not M) of the KI solution.

Short Answer

Step by step solution

Definition of molality.

The molality of KI solution.

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