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Fluorescent derivatives of amino acids separated by capillary zone electrophoresis had migration times with the following order: arginine (fastest) \(<\) phenylalanine \(<\) asparagine \(<\) serine \(<\) glycine (slowest). Explain why arginine has the shortest migration time.

Short Answer

Expert verified
Arginine migrates fastest due to its high positive charge, increasing its electrophoretic mobility despite its size.

Step by step solution

01

Understand Capillary Zone Electrophoresis

Capillary Zone Electrophoresis (CZE) is a technique that separates analytes based on their charge-to-size ratio via the application of an electric field. Molecules that are more charged or smaller will generally have a faster migration time.
02

Analyze Arginine's Properties

Arginine is an amino acid with a basic side chain, which means it can carry a positive charge at physiological pH. This makes arginine highly charged relative to neutral amino acids like phenylalanine, asparagine, serine, and glycine.
03

Determine the Influence of Charge on Electrophoretic Mobility

In electrophoresis, the electrophoretic mobility of an ion depends on its charge: the higher the charge, the faster it migrates. Since arginine can carry a positive charge, its electrophoretic mobility is increased, resulting in a faster migration time.
04

Consider Size and Shape Factors

While arginine is larger than some of the other amino acids, the influence of its high charge outweighs the effects of its size. In CZE, the charge-to-size ratio is more determinant, and a higher positive charge on arginine gives it a faster migration time despite its size.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Amino Acids
Amino acids are the building blocks of proteins. They are organic compounds containing both amino \((-NH_2)\) and carboxyl \((-COOH)\) functional groups, along with a side chain that is specific to each amino acid. In the context of capillary zone electrophoresis, these side chains play a crucial role in determining how quickly an amino acid might move under an electric field.

Amino acids can have different charges depending on the pH level. For example, some like arginine can carry a strong positive charge at physiological pH, which affects their behavior in electrophoresis. Neutral amino acids such as phenylalanine, on the other hand, will migrate more slowly because they lack this additional charge. The unique chemical properties of each amino acid's side chain, therefore, influence their migration times when separated by techniques like CZE.

Understanding the characteristics of amino acids is key to predicting their behavior in different analytical techniques.
Electrophoretic Mobility
Electrophoretic mobility is a measure of how fast a molecule moves in an electric field. It largely depends on two main factors: the charge of the molecule and its size. Molecules with a higher charge tend to move faster than those with a lower charge when exposed to the same electric field.

In the case of capillary zone electrophoresis, highly charged species have higher electrophoretic mobility, resulting in faster migration times. Arginine is an example of such a highly charged amino acid. Its basic side chain allows it to carry a positive charge, enhancing its mobility under electrophoresis.

The speed at which molecules travel is not only a function of their charge but also of their size in relation to their charge, making electrophoretic mobility a key concept in understanding migration times.
Charge-to-Size Ratio
The charge-to-size ratio is a critical factor in evaluating how an analyte will behave during capillary zone electrophoresis. This ratio reflects the balance between the electric charge a particle carries and its physical size. In simpler terms, it tells us how effectively a molecule can move through a medium when an electric field is applied.

Molecules with a high charge-to-size ratio tend to migrate faster because the electric force propelling them forward outweighs the frictional resistance due to their size. Arginine, for example, despite being fairly large, has a significant positive charge relative to its size, which increases its charge-to-size ratio and lets it move more swiftly compared to other amino acids with lower ratios.

Understanding this concept helps to predict and explain the sequence of amino acids' migration times observed in capillary zone electrophoresis.
Fluorescent Derivatives
Fluorescent derivatives are modified forms of molecules that emit light when excited by a source, typically used in analytical chemistry to increase the detectability of non-fluorescent analytes. In the context of capillary zone electrophoresis, these derivatives can enhance the resolution and sensitivity of the separation processes.

When amino acids are transformed into fluorescent derivatives, it becomes easier to track their migration through the capillary tube because they emit detectable signals. This is particularly useful for amino acids that do not naturally fluoresce or have low concentrations, as it allows scientists to observe and measure their separation more accurately.

Using fluorescent derivatives is a common strategy in electrophoresis to achieve better analytical results, ensuring that even subtle differences in electrophoretic mobility or migration time can be effectively studied.

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Most popular questions from this chapter

What is the principal source of zone broadening in ideal capillary electrophoresis?

What is electroosmosis?

Explain how neutral molecules can be separated by micellar electrokinetic chromatography. Why is this a form of chromatography?

Benzoic acid containing \({ }^{16} \mathrm{O}\) can be separated from benzoic acid containing \({ }^{18} \mathrm{O}\) by electrophoresis at a suitable \(\mathrm{pH}\) because they have slightly different acid dissociation constants. The difference in mobility is caused by the different fraction of each acid in the anionic form, \(\mathrm{A}^{-}\). Calling this fraction \(\alpha\), we can write $$ \begin{array}{ll} \mathrm{H}^{16} \mathrm{~A} \rightleftharpoons \mathrm{H}^{+}+{ }^{16} \mathrm{~A}^{-} & \mathrm{H}^{18} \mathrm{~A} \rightleftharpoons \mathrm{H}^{+}+{ }^{18} \mathrm{~N}^{18} \mathrm{~A}^{-} \\ { }^{16} \alpha=\frac{{ }^{16} K}{{ }^{16} K+\left[\mathrm{H}^{+}\right]} & { }^{18} \alpha=\frac{{ }^{18} K}{{ }^{18} K+\left[\mathrm{H}^{+}\right]} \end{array} $$ where \(K\) is the equilibrium constant. The greater the fraction of acid in the form \(\mathrm{A}^{-}\), the faster it will migrate in the electric field. It can be shown that, for electrophoresis, the maximum separation will occur when \(\Delta \alpha / \sqrt{\alpha}\) is a maximum. In this expression, \(\Delta \alpha={ }^{16} \alpha-{ }^{18} \alpha\), and \(\bar{\alpha}\) is the average fraction of dissociation \(\left[=\frac{1}{2}\left({ }^{16} \alpha+{ }^{18} \alpha\right)\right] .\) (a) Let us denote the ratio of acid dissociation constants as \(R={ }^{16} K /{ }^{18} K .\) In general, \(R\) will be close to unity. For benzoic acid, \(R=1.020\). Abbreviate \({ }^{16} K\) as \(K\) and write \({ }^{18} K=K / R\). Derive an expression for \(\Delta \alpha / \sqrt{\bar{\alpha}}\) in terms of \(K,\left[\mathrm{H}^{+}\right]\), and \(R\). Because both equilibrium constants are nearly equal ( \(R\) is close to unity), set \(\bar{\alpha}\) equal to \({ }^{16} \alpha\) in your expression. (b) Find the maximum value of \(\Delta \alpha / \sqrt{\alpha}\) by taking the derivative with respect to \(\left[\mathrm{H}^{+}\right]\)and setting it equal to 0 . Show that the maximum difference in mobility of isotopic benzoic acids occurs when \(\left[\mathrm{H}^{+}\right]=(K / 2 R)(1+\sqrt{1+8 R})\) (c) Show that, for \(R \approx 1\), this expression simplifies to \(\left[\mathrm{H}^{+}\right]=2 K\), or \(\mathrm{pH}=\mathrm{p} K-0.30\). That is, the maximum electrophoretic separation should occur when the column buffer has \(\mathrm{pH}=\mathrm{p} K-0.30\), regardless of the exact value of \(R .{ }^{63}\)

(a) A long thin molecule has a greater friction coefficient than a short fat molecule. Predict whether fumarate or maleate will have greater electrophoretic mobility. (b) Electrophoresis is run with the injection end positive and the detection end negative. At \(\mathrm{pH} 8.5\), both anions have a charge of \(-2\). The electroosmotic flow from the positive terminal to the negative terminal is greater than the electrophoretic flow, so these two anions have a net migration from the positive to the negative end of the capillary in electrophoresis. From your answer to part (a), predict the order of elution of these two species. (c) At \(\mathrm{pH} 4.0\), both anions have a charge close to \(-1\), and the electroosmotic flow is weak. Therefore, electrophoresis is run with the injection end negative and the detection end positive. The anions migrate from the negative end of the capillary to the positive end. Predict the order of elution.

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