Chapter 6: Problem 117
\(150 \mathrm{~mL}\) of \(0.0008 M\) ammonium sulphate is mixed with \(50
\mathrm{~mL}\) of \(0.04 M\) calcium nitrate. The ionic product of
\(\mathrm{CaSO}_{4}\) will be : \(\left(K_{s p}=2.4 \times 10^{-5}\right.\) for
\(\mathrm{CaSO}_{4}\) )
(a) \(
Short Answer
Step by step solution
Calculate the final concentrations
Find final \(\text{Ca}^{2+}\) concentration
Find final \(\text{SO}_4^{2-}\) concentration
Calculate the ionic product of \(\text{CaSO}_4\)
Compare the ionic product with the solubility product (\(K_{sp}\))
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionic Product
\[ IP = [A^+][B^-] \]
where [A\textsuperscript{+}] and [B\textsuperscript{-}] are the molar concentrations of the respective ions. This is crucial for understanding whether a precipitate will form in a solution. To calculate the ionic product, you must know the concentrations of the individual ions, which can be affected by factors like dilution or mixing with other solutions, as shown in the exercise where a mix of solutions results in new concentrations for the ions involved.