/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 A reversible reaction is one whi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A reversible reaction is one which : (a) Proceeds in one direction (b) Proceeds in both directions (c) Proceeds spontaneously (d) All the statements are wrong

Short Answer

Expert verified
Option (b) is correct as a reversible reaction proceeds in both directions.

Step by step solution

01

Understanding the Concept of a Reversible Reaction

A reversible reaction is one where the reactants form products, which can themselves react together to form the reactants again. This means that this type of reaction can proceed in both forward and reverse directions under certain conditions.
02

Analyzing the Given Options

Option (a) suggests that the reaction proceeds in one direction, which is characteristic of an irreversible reaction, not a reversible one. Option (c) refers to spontaneity, which is a different concept that does not solely determine if a reaction is reversible. Option (d) suggests that all statements are wrong, which is not true since we know some reactions are indeed reversible.
03

Identifying the Correct Answer

Option (b) states that a reversible reaction proceeds in both directions, which aligns with the definition of a reversible reaction. Therefore, option (b) is the correct choice.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
Chemical equilibrium represents a state in a chemical reaction where the rate of the forward reaction equals the rate of the reverse reaction, meaning that the concentrations of reactants and products remain constant over time, though not necessarily equal. It is important to understand that the equilibrium is dynamic. This indicates that while the overall concentrations don't change, the molecules are still reacting with one another. Equilibrium can be reached in both reversible reactions, where compounds can react in both forward and reverse directions, and is indicated by the equilibrium constant (\( K_{eq} \)), which quantifies the ratio of product concentrations to reactant concentrations at equilibrium.

For learners grappling with this topic, it’s helpful to visualize a balance scale that is evenly positioned; this represents the equilibrium state. Neither side is heavier (faster) than the other; reaction rates are perfectly balanced. This analogy can simplify the understanding of equilibrium without getting lost in the complexity of chemical reactions.
Irreversible Reaction
An irreversible reaction, in contrast to a reversible one, proceeds in one direction only, leading to a complete consumption of the reactants. Once the reactants have been converted to products, the reaction cannot naturally go backwards to re-form the original reactants. This is similar to pressing a 'one-way road' button from reactants to products; there's no turning back.

Most chemical reactions in real-life scenarios are considered irreversible due to the reactants undergoing permanent change. Examples include combustion, precipitation, and the mixing of an acid with a base to neutralize each other. In educational settings, picturing an irreversible reaction as a slide from which you cannot climb back up could enhance a student's understanding of this concept.
Reaction Spontaneity
Reaction spontaneity refers to whether a chemical reaction can occur without the continuous input of energy from an external source. Spontaneous reactions, despite the name, do not necessarily happen quickly; they may proceed at any speed, but the essential point is that they are thermodynamically favorable under the conditions provided. The spontaneity of a reaction is determined by factors including enthalpy, entropy, and temperature, and is often assessed through the Gibbs free energy formula: \( G = H - TS \), where \( G \) is the Gibbs free energy, \( H \) the enthalpy, \( T \) the temperature, and \( S \) the entropy.

A negative Gibbs free energy implies that the reaction is spontaneous. To further support learners, the concept of spontaneity might be equated to a ball rolling downhill—once started (after reaching the activation energy), the ball continues rolling without additional pushing, which in this metaphor, represents the spontaneous progression of the reaction.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

One mole of pure ethyl alcohol was treated with one mole of pure acetic acid at \(25^{\circ} \mathrm{C}\). One-third of the acid changes into ester at equilibrium. The equilibrium constant for the reaction will be : (a) \(\frac{1}{4}\) (b) 2 (c) 3 (d) 4

The equilibrium constant \(\left(K_{c}\right)\) for the reaction $$ 2 \mathrm{HCl}(g) \rightleftharpoons \mathrm{H}_{2}(g)+\mathrm{Cl}_{2}(g) $$ is \(4 \times 10^{-34}\) at \(25^{\circ} \mathrm{C}\). What is the equilibrium constant for the reaction? $$ \frac{1}{2} \mathrm{H}_{2}(g)+\frac{1}{2} \mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{HCl}(g) $$ (a) \(2 \times 10^{-17}\) (b) \(2.5 \times 10^{33}\) (c) \(5 \times 10^{6}\) (d) None of these

If the pressure in a reaction vessel for the following reaction is increased by decreasing the volume, what will happen to the concentrations of \(\mathrm{CO}\) and \(\mathrm{CO}_{2}\) ? $$ \mathrm{H}_{2} \mathrm{O}(g)+\mathrm{CO}(g) \rightleftharpoons \mathrm{H}_{2}(g)+\mathrm{CO}_{2}(g)+\text { Heat } $$ (a) both the [CO] and [CO \(\left._{2}\right]\) will decrease (b) neither the [CO] nor the \(\left[\mathrm{CO}_{2}\right]\) will change (c) the [CO] will decrease and the [CO \(_{2}\) ] will increase (d) both the [CO] and [CO \(\left._{2}\right]\) will increase

The pressure on a sample of water at its triple point is reduced while the temperature is held constant. Which phases changes are favoured? (I) melting of ice (II) sublimation of ice (III) vaporization of liquid water (a) I only (b) III only (c) II only (d) II and III

At a certain temperature, only \(50 \% \mathrm{HI}\) is dissociated at equilibrium in the following reaction: $$ 2 \mathrm{HI}(g) \rightleftharpoons \mathrm{H}_{2}(g)+\mathrm{I}_{2}(g) $$ The equilibrium constant for this reaction is : (a) \(0.25\) (b) \(1.0\) (c) \(3.0\) (d) \(0.5\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.