The lead nitrate, \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\), in \(25
\mathrm{~mL}\) of a \(0.15 \mathrm{M}\) solution reacts with all of the aluminium
sulphate, \(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\), in \(20
\mathrm{~mL}\) of solution. What is the molar concentration of the
\(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} ?\) \(3
\mathrm{~Pb}\left(\mathrm{NO}_{3}\right)_{2}(a
q)+\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q) \longrightarrow 3
\mathrm{PbSO}_{4}(s)+2 \mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}(a q)\)
(a) \(6.25 \times 10^{-2} M\)
(b) \(2.421 \times 10^{-2} M\)
(c) \(0.1875 M\)
(d) None of these