Chapter 7: Problem 64
The reaction in which primary amine is obtained as one of the product is
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Chapter 7: Problem 64
The reaction in which primary amine is obtained as one of the product is
These are the key concepts you need to understand to accurately answer the question.
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The decreasing order of rate of esterification of the following acids with MeOH is (I) \(\mathrm{Me}-\mathrm{CH}_{2} \mathrm{COOH}\) (II) Me \(_{2} \mathrm{CHCOOH}\) (III) \(\mathrm{Me}_{3} \mathrm{C}-\mathrm{COOH}\) (A) \(\mathrm{I}>\mathrm{II}>\mathrm{III}\) (B) III \(>\mathrm{II}>\mathrm{I}\) (C) II \(>\mathrm{III}>\mathrm{I}\) (D) II > I > III
In sodalime decarboxylation, sodalime is made of ' \(x\) ' \(\mathrm{NaOH}\) and ' \(y^{\prime} \mathrm{CaO}\), then \(x / y\) is (A) \(1 / 3\) (B) \(1 / 1\) (C) \(3 / 1\) (D) \(5 / 1\)
Ester can be reduced by: (A) DIBAL-H (B) \(\mathrm{Na}-\mathrm{C}_{2} \mathrm{H}_{2} \mathrm{OH}\) (C) \(\mathrm{NaBH}_{4}\) (D) \(\mathrm{CH}_{3} \mathrm{MgX}\)
\(P\) ) is the only benzene dicarboxylic acid which on strong heating produces anhydride, then choose the incorrect option: $$ (\mathrm{P})+\mathrm{NH}_{3} \rightleftharpoons(\mathrm{Q}) \longrightarrow \Delta(\mathrm{R}) \stackrel{\Delta}{-\mathrm{NH}_{3}} \longrightarrow(\mathrm{S}) $$ (A) (S) has common name phthalamide (B) (Q) is known as ammonium phthalate (C) Formation of (Q) is acid-base interaction (D) (S) can be used in Hofmann bromamide degradation reaction
Total number of reactions in which carboxylic acid is obtained as a product is (a) \(\mathrm{R}-\mathrm{Cl} \frac{\text { (i) } \mathrm{Mg}}{\text { (ii) } \mathrm{CO}_{2}}\) (b) \(\mathrm{R}-\mathrm{Cl} \frac{\text { (i) } \mathrm{KCN}}{\text { (ii) } \mathrm{H}_{3} \mathrm{O}^{+}}\) (c) \(\mathrm{R}-\mathrm{CHO} \frac{\mathrm{CrO}_{3}}{\mathrm{H}_{2} \mathrm{SO}_{4}}{\longrightarrow}\) (d) \(\mathrm{R}-\mathrm{C}-\mathrm{Cl} \stackrel{\mathrm{H}_{3} \mathrm{O}^{+}}{\longrightarrow}\) (e) \(\mathrm{R}-\mathrm{CH}_{2} \mathrm{OH} \frac{\mathrm{CrO}_{3}}{\mathrm{H}_{2} \mathrm{SO}_{4}}\) (f) \(\mathrm{R}-\mathrm{CHO} \stackrel{\mathrm{Ag}_{2} \mathrm{O}}{\longrightarrow}\) (g) \(\mathrm{R}-\mathrm{NC} \stackrel{\mathrm{H}_{3} \mathrm{O}^{+}}{\longrightarrow}\)
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