Chapter 5: Problem 7
The compound which on reaction with \(\mathrm{NaOH}, \Delta\)
doesn'\operatorname{tg} i v e ~ c a r b o x y l i c ~ a c i d / s a l t ~ a s
~ a ~ p r o d u c t , ~ i s ~
(A)
Short Answer
Expert verified
The compound which doesn't give a carboxylic acid/salt as a direct transformation product when reacting with \(\mathrm{NaOH}\) and heat (\(\Delta\)) is (C) 3-Chlorobutanone.
Step by step solution
01
Reaction with NaOH
When any of these compounds react with \(\mathrm{NaOH}\), they generally undergo either acyl substitution or hydrolysis reaction.
02
Analyze Compound (A) - 2-Chloropropanoyl chloride
When 2-Chloropropanoyl chloride reacts with \(\mathrm{NaOH}\), the chlorine atom on the acid chloride will be replaced with hydroxyl group, forming a carboxylic acid which further reacts with \(\mathrm{NaOH}\) to form carboxylate salt:
\(CC(=O)CCCl + NaOH \rightarrow CC(=O)CC(OH) + NaCl \rightarrow CC(=O)CC(ONa) + HCl\)
03
Analyze Compound (B) - 2-bromopropanone
When 2-bromopropanone reacts with \(\mathrm{NaOH}\), it undergoes a nucleophilic acyl substitution reaction where the bromine atom is replaced with a hydroxyl group, forming a carboxylic acid which further reacts with \(\mathrm{NaOH}\) to form carboxylate salt:
\(CC(=O)C(C)Br + NaOH \rightarrow CC(=O)C(C)(OH) + NaBr \rightarrow CC(=O)C(C)(O-Na) + HBr\)
04
Analyze Compound (C) - 3-Chlorobutanone
When 3-Chlorobutanone reacts with \(\mathrm{NaOH}\), the chlorine atom involved is in alpha position, therefore the compound is classified as an α-halo ketone. α-Halo ketones react with \(\mathrm{NaOH}\) to give a carboxylic acid as a product through the haloform reaction, which doesn't involve direct transformation from ketone to carboxylic acid or its salt:
\(CCC(=O)CCl+ NaOH+4HCl \rightarrow CC(=O)OH+CHCl_{3}+Na^{+}Cl^{-}\)
05
Analyze Compound (D) - Butyryl chloride
When Butyryl chloride reacts with \(\mathrm{NaOH}\), the chlorine atom on the acid chloride will be replaced with hydroxyl group, forming a carboxylic acid which further reacts with \(\mathrm{NaOH}\) to form carboxylate salt:
\(CCCC(=O)Cl + NaOH \rightarrow CCCC(=O)OH + NaCl \rightarrow CCCC(=O)O-Na + HCl\)
06
Conclusion
Based on the reactions in steps 2-5, the only compound that doesn't give a carboxylic acid/salt as a direct transformation product when reacting with \(\mathrm{NaOH}\) is Compound (C) 3-Chlorobutanone. Therefore, the correct answer is (C) 3-Chlorobutanone.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nucleophilic Acyl Substitution
Nucleophilic acyl substitution is a fundamental reaction in organic chemistry, particularly important for the transformation of acyl compounds like acid chlorides, anhydrides, esters, and amides. At its core, this reaction involves the replacement of a leaving group by a nucleophile.
The mechanism typically begins with the nucleophile attacking the carbonyl carbon, forming a tetrahedral intermediate, which then collapses, expelling the leaving group and regenerating the carbonyl.
One common example of this is the reaction of acid chlorides with sodium hydroxide ( ac{NaOH}) to form a carboxylate salt. Here, the hydroxide ion acts as the nucleophile, replacing the chloride ion, a good leaving group, resulting in the formation of a carboxylic acid. This newly formed acid can then react further with sodium hydroxide to yield the carboxylate salt.
The mechanism typically begins with the nucleophile attacking the carbonyl carbon, forming a tetrahedral intermediate, which then collapses, expelling the leaving group and regenerating the carbonyl.
One common example of this is the reaction of acid chlorides with sodium hydroxide ( ac{NaOH}) to form a carboxylate salt. Here, the hydroxide ion acts as the nucleophile, replacing the chloride ion, a good leaving group, resulting in the formation of a carboxylic acid. This newly formed acid can then react further with sodium hydroxide to yield the carboxylate salt.
- Key Points:
- Attack by a nucleophile at the carbonyl carbon.
- Formation and collapse of a tetrahedral intermediate.
- Used predominantly for acyl chlorides and other reactive acyl groups.
Haloform Reaction
The haloform reaction is a notable transformation in organic chemistry. It occurs primarily with methyl ketones when they react with halogens in the presence of a base, such as sodium hydroxide (
ac{NaOH}).
This reaction is characterized by the cleavage of a methyl ketone to give a carboxylic acid or its salt and a haloform (such as chloroform, bromoform, or iodoform). The haloform reaction is performed in several stages: the halogenation of the alpha position followed by base induced cleavage of the C-C bond, ultimately leading to the generation of a haloform.
For example, when 3-chlorobutanone (an α-halo ketone) is treated with ac{NaOH}, the haloform reaction is triggered, and products such as chloroform and a carboxylate ion are formed, instead of carboxylic acid formation via direct nucleophilic substitution.
This reaction is characterized by the cleavage of a methyl ketone to give a carboxylic acid or its salt and a haloform (such as chloroform, bromoform, or iodoform). The haloform reaction is performed in several stages: the halogenation of the alpha position followed by base induced cleavage of the C-C bond, ultimately leading to the generation of a haloform.
For example, when 3-chlorobutanone (an α-halo ketone) is treated with ac{NaOH}, the haloform reaction is triggered, and products such as chloroform and a carboxylate ion are formed, instead of carboxylic acid formation via direct nucleophilic substitution.
- Key Points:
- Primarily occurs with methyl ketones and α-halo ketones.
- Involves halogenation of the methyl group followed by C-C bond cleavage.
- Produces a haloform and a carboxylate ion.
Carboxylate Salt Formation
Carboxylate salt formation is a common reaction in organic chemistry where a carboxylic acid reacts with a base to form its corresponding salt. This process is important for the stabilization of carboxylic acids, especially in aqueous solutions.
Typically, when a carboxylic acid interacts with a strong base like sodium hydroxide ( ac{NaOH}), the acidic hydrogen of the carboxylic acid is removed, resulting in the formation of a carboxylate ion. This carboxylate ion is paired with the sodium ion to form a carboxylate salt.
This reaction is highly favorable as it transforms a potentially volatile or unstable carboxylic acid into a more stable ionic species. For example, the reaction of a carboxylic acid derived from an acid chloride such as butyryl chloride with ac{NaOH} will yield a stable sodium carboxylate salt.
Typically, when a carboxylic acid interacts with a strong base like sodium hydroxide ( ac{NaOH}), the acidic hydrogen of the carboxylic acid is removed, resulting in the formation of a carboxylate ion. This carboxylate ion is paired with the sodium ion to form a carboxylate salt.
This reaction is highly favorable as it transforms a potentially volatile or unstable carboxylic acid into a more stable ionic species. For example, the reaction of a carboxylic acid derived from an acid chloride such as butyryl chloride with ac{NaOH} will yield a stable sodium carboxylate salt.
- Key Points:
- Involves deprotonation of carboxylic acids by a strong base.
- Results in the formation of a stable ionic salt.
- Relevance in stabilizing carboxylic acids in aqueous mediums.