Chapter 4: Problem 9
In the given transformation, which of the following is the most appropriate
reagent?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 4: Problem 9
In the given transformation, which of the following is the most appropriate
reagent?
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
2-Hexyne gives trans -2-Hexene on treatment with (A) \(\mathrm{LiAlH}_{4}\) (B) \(\mathrm{Pt} / \mathrm{H}_{2}\) (C) \(\mathrm{Li} / \mathrm{NH}_{3}\) (D) \(\mathrm{Pd} / \mathrm{BaSO}_{4}\)
Among the following compounds, the one that responds positively to both lodoform test and Fehling'stests (A) propionaldehyde (B) acetaldehyde (C) acetone (D) ethyl alcohol
The incorrect option regarding the following reaction sequence is (A) Reaction is reversible and catalysed by acid (B) \(\mathrm{Z}\) can be alkyl, aryl, \(\mathrm{OH}, \mathrm{NHCONH}_{2}\) (C) Product is favoured because of rapid dehydration of (P) (D) If \(\mathrm{NHZ}_{2}\) is used in place of \(\mathrm{H}_{2} \mathrm{~N}-\mathrm{Z}\), then imine will be obtained as (Q)
(P) has molecular formula ' \(\mathrm{C}_{8} \mathrm{H}_{8} \mathrm{O}\) ' which forms red-orange ppt with (+ve) 2,4-DNP. (Q) on acidification \(\mathrm{f}_{0 \mathrm{rm}} \mathrm{C}_{7} \mathrm{H}_{6} \mathrm{O}_{2}\) Choose the correct option(s): (A) (R) is used as antiseptic (B) Red- Orange ppt. is 2,4 -dinitrophenyl hydrazone (C) (P) is acetophenone (D) (S) evolves \(\mathrm{CO}_{2}\) gas with \(\mathrm{NaHCO}_{3}\)
The product obtained in the following reaction is \(\frac{\text { (i) Tollen'sreagent }}{\text { (ii) } \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2} / \mathrm{H}^{\prime}}{\longrightarrow}\) (A) Tartaric acid (B) Citric acid (C) Succinic acid (D) Malic acid
What do you think about this solution?
We value your feedback to improve our textbook solutions.