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Chapter 10: Problem 62

Which is not a hydrocarbon? (A) OC1CCCCC1 (B) c1ccccc1 (C) CC1CCCCC1C (D)

Short Answer

Expert verified
The correct answer is (A) OC1CCCCC1 since it contains an oxygen atom, in addition to carbon and hydrogen atoms.

Step by step solution

01

Analyze each molecule

First, we need to analyze each molecule option (A), (B), (C), and (D) to determine their composition. (A) OC1CCCCC1 This molecule has an oxygen atom (O) attached to the ring. This indicates the presence of an atom other than hydrogen and carbon in the molecule. (B) c1ccccc1 This molecule is a simple six-membered carbon ring, with all carbons bonded to each other and hydrogen atoms attached to each carbon. Here, only carbon and hydrogen atoms are present. (C) CC1CCCCC1C This molecule consists of a six-membered carbon ring with two methyl groups (-CH3) attached to it. In this case, only carbon and hydrogen atoms are present. (D) CCCCCC This molecule is a linear hydrocarbon (hexane) with six carbon atoms bonded to each other and appropriate hydrogen atoms filling the bonds. Here, only carbon and hydrogen atoms are present.
02

Identify the non-hydrocarbon

As we have analyzed all the molecules, we can now identify which molecule is not a hydrocarbon: (A) OC1CCCCC1 is not a hydrocarbon as it contains an oxygen atom, in addition to carbon and hydrogen atoms. Therefore, the correct answer is (A).

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Most popular questions from this chapter

Circle the functional group and also find out the degree of unsaturation. Column-I Column-II (Compound) (Properties) (A) C=CCCC(=O)CC1C=CCCC1 (P) Odd number of D.B.E (B) (Q) Even number of \(1^{\circ}\) carbon (C) (R) Odd number of different functional group (D) (S) Even number of D.B.E (T) Odd number of \(1^{\circ}\) carbon

Which of the following pair represent different functional group containing compound? (A) \(\mathrm{Me}-\mathrm{CH}_{2}-\mathrm{NH}_{2}, \mathrm{Me}-\mathrm{NH}-\mathrm{Me}\) (B) \(\mathrm{Me}-\mathrm{CH}_{2}-\mathrm{OH}, \mathrm{Me}-\mathrm{O}-\mathrm{Me}\) (C) \(\mathrm{Me}-\mathrm{CH}_{2}-\mathrm{OH}, \mathrm{Me}_{2} \mathrm{CH}-\mathrm{OH}\) (D) \(\mathrm{Me}-\mathrm{C}-\mathrm{NH}_{2}\) CC(=O)NC(C)=O

CCC=CCCCCC (C) (6Z)-dodec-2-yne-6-ene (B) (6E)-dodec-6-en-2-yne 鈥� # The incorrect IUPAC nomenclature of following compound is (A) (6E)-dodec-2-yne-6-ene CC#CCC=CCCCCC (C) (6Z)-dodec-2-yne-6-ene (B) (6E)-dodec-6-en-2-yne (D) (6Z)-dodec-6-en-2-yne

Which of the following is / are incorrect IUPAC names? (A) 1-Chloro-ethanone (B) 1-Methyl-1-Ethanol (C) 1-Chloro-2-Propene (D) 3-Chloro-1-Propene

In all compounds of IUPAC name \(\mathrm{P}_{1}\)-bromo- \(\mathrm{P}_{2}\)-chloro- \(\mathrm{P}_{3}\)-methyl but- \(\mathrm{P}_{4}\)-yne, which is always correct \(\left(\mathrm{P}_{\mathrm{i}}\right.\) represent position of side chain and multiple bond according to IUPAC). (A) \(\frac{\mathrm{P}_{1}}{\mathrm{P}_{4}}=\frac{1}{4}\) (B) \(\frac{P_{1}}{P_{2}}=\frac{1}{2}\) (C) \(\frac{\mathrm{P}_{1}}{\mathrm{P}_{3}}=\frac{1}{3}\) (D) \(\frac{\mathrm{P}_{4}}{\mathrm{P}_{3}}=\frac{1}{3}\)
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