Chapter 1: Problem 155
The number of localised lone pair in purine is (A) 4 (B) 3 (C) 2 (D) 1
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Chapter 1: Problem 155
The number of localised lone pair in purine is (A) 4 (B) 3 (C) 2 (D) 1
These are the key concepts you need to understand to accurately answer the question.
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The heat of hydrogenation per mole is highest for (A) Pent-1-ene (B) Pent-2-ene (C) Penta-1,3-diene (D) Penta-1,4-diene
Arrange the following in decreasing order of dipole moment: (I) \(\mathrm{CH}_{2}=\mathrm{CH}_{2}\) (II) \(\mathrm{CH}_{2}=\mathrm{O}\) (III) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{O}\) \((\mathrm{IV}) \mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{O}\) (A) \(\mathrm{I}>\mathrm{II}>\mathrm{III}>\mathrm{IV}\) (B) \(\mathrm{IV}>\mathrm{III}>\mathrm{II}>\mathrm{I}\) \((\mathrm{C}) \mathrm{II}>\mathrm{III}>\mathrm{IV}>\mathrm{I}\) (D) IV > II > III > I
The true statement regarding glycerol is/are (A) two \(1^{\circ}\) alcohol (B) Trihydric alcohol (C) one \(2^{\circ}\) alcohol (D) All of these
Bond energy of keto form of phenol is - \(361 \mathrm{kcal} /\) mole whereas total energy content of enol form is \(-379 \mathrm{kcal} /\) mole. If enol form is more stable than keto by - \(13 \mathrm{kcal} / \mathrm{mole}\), then the resonance energy is (A) \(-18\) (B) \(-31\) (C) \(-13\) (D) \(-5\)
Which among the following compounds is the most acidic? (A) \(\mathrm{HC} \equiv \mathrm{CH}\) (B) \(\mathrm{Ph}-\mathrm{OH}\) (C) \(\mathrm{H}_{2} \mathrm{O}\) (D) \(\mathrm{Ph}-\mathrm{CH}_{2} \mathrm{OH}\)
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