Chapter 8: Problem 78
The first order isomerisation reaction: Cyclopropane \(\rightarrow\) propene, has a rate constant of \(1.10 \times 10^{-4} \mathrm{~s}^{-1}\) at \(470^{\circ} \mathrm{C}\) and an activation energy of \(264 \mathrm{~kJ} / \mathrm{mol}\). What is the temperature of the reaction when the rate constant is equal to \(4.36 \times 10^{-3} \mathrm{~s}^{-1}\) ? a. \(240^{\circ} \mathrm{C}\) b. \(150^{\circ} \mathrm{C}\) c. \(540^{\circ} \mathrm{C}\) d. \(450^{\circ} \mathrm{C}\)
Short Answer
Step by step solution
Understand the Arrhenius equation
Use the two-point form of the Arrhenius equation
Substitute known values into the equation
Simplify and calculate
Solve for \( T_2 \)
Convert to temperature
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding First Order Reactions
- \( [A] \) is the concentration of reactant \( A \),
- \( k \) is the rate constant, having units of \( \mathrm{s^{-1}} \).
What is a Rate Constant?
- Frequency of reactant collisions,
- Orientation of colliding molecules,
- Energy of reactant molecules when they collide.
The Role of Activation Energy
- A lower activation energy means the reaction is more likely to occur, leading to a faster reaction rate.
- A higher activation energy means fewer molecules have sufficient energy to react, resulting in a slower reaction.
Temperature Dependence in Reactions
- More molecules achieve the necessary activation energy,
- The rate constant \( k \) typically increases, thus speeding up the reaction.