/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 The decomposition of dinitrogen ... [FREE SOLUTION] | 91Ó°ÊÓ

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The decomposition of dinitrogen pentoxide is described by the chemical equation \(2 \mathrm{~N}_{2} \mathrm{O}_{5}(\mathrm{~g}) \rightarrow 4 \mathrm{NO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g})\) If the rate of appearance of \(\mathrm{O}_{2}\) is equal to \(2.40 \mathrm{~mol} / \mathrm{min}\) at a particular moment, what is the rate of disappearance of \(\mathrm{N}_{2} \mathrm{O}_{5}\) at that moment? a. \(3.48 \mathrm{~mol} / \mathrm{min}\) b. \(4.80 \mathrm{~mol} / \mathrm{min}\) c. \(2.40 \mathrm{~mol} / \mathrm{min}\) d. \(1.80 \mathrm{~mol} / \mathrm{min}\)

Short Answer

Expert verified
The rate of disappearance of \(\mathrm{N}_{2}\mathrm{O}_{5}\) is \(4.80 \mathrm{~mol} / \mathrm{min}\), corresponding to option b.

Step by step solution

01

Write the Rate Expressions

The chemical equation for the decomposition of dinitrogen pentoxide is given as \(2 \mathrm{~N}_{2} \mathrm{O}_{5}(\mathrm{~g}) \rightarrow 4 \mathrm{NO}_{2}(\mathrm{~g}) + \mathrm{O}_{2}(\mathrm{~g})\). From this equation, we can write the rate expressions: \(-\frac{1}{2} \frac{d[\mathrm{N}_{2}\mathrm{O}_{5}]}{dt} = \frac{1}{4} \frac{d[\mathrm{NO}_{2}]}{dt} = \frac{d[\mathrm{O}_{2}]}{dt}\).
02

Identify Given Rate

The problem states that the rate of appearance of \(\mathrm{O}_{2}\) is \(2.40 \mathrm{~mol} / \mathrm{min}\). Therefore, we have: \(\frac{d[\mathrm{O}_{2}]}{dt} = 2.40 \mathrm{~mol} / \mathrm{min}\).
03

Relate Rates of Reaction Using Stoichiometry

Using the rate expressions from Step 1, relate the rate of appearance of \(\mathrm{O}_{2}\) with the rate of disappearance of \(\mathrm{N}_{2}\mathrm{O}_{5}\) using the stoichiometry of the reaction. From the expression \(-\frac{1}{2} \frac{d[\mathrm{N}_{2} \mathrm{O}_{5}]}{dt} = \frac{d[\mathrm{O}_{2}]}{dt}\), substitute \(\frac{d[\mathrm{O}_{2}]}{dt} = 2.40 \mathrm{~mol} / \mathrm{min}\).
04

Solve for Rate of Disappearance

Substitute the given rate of appearance of \(\mathrm{O}_{2}\) to find the rate of disappearance of \(\mathrm{N}_{2} \mathrm{O}_{5}\): \(-\frac{1}{2} \frac{d[\mathrm{N}_{2} \mathrm{O}_{5}]}{dt} = 2.40 \mathrm{~mol} / \mathrm{min}\). Solving, we find \(\frac{d[\mathrm{N}_{2} \mathrm{O}_{5}]}{dt} = -2 \times 2.40 \mathrm{~mol} / \mathrm{min} = -4.80 \mathrm{~mol} / \mathrm{min}\). Therefore, the rate of disappearance of \(\mathrm{N}_{2} \mathrm{O}_{5}\) is \(4.80 \mathrm{~mol} / \mathrm{min}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

reaction rate
The reaction rate in chemical kinetics refers to how fast or slow a chemical reaction occurs. It is an essential concept that helps us understand the speed at which reactants are transformed into products. In the context of the given reaction, the rate is typically measured by the change in concentration of a reactant or a product per unit time. In mathematical terms, this is represented using rate expressions, like \[ \frac{d[\mathrm{O}_2]}{dt} \]or\[ \frac{d[\mathrm{N}_2\mathrm{O}_5]}{dt}. \]These expressions tell us how the concentrations of specific substances change over time. The decomposition of dinitrogen pentoxide (\(\mathrm{N}_2\mathrm{O}_5\)) into nitrogen dioxide (\(\mathrm{NO}_2\)) and oxygen (\(\mathrm{O}_2\)) is a classic example used to demonstrate reaction rates. If you know how fast \(\mathrm{O}_2\) is produced, you can infer how fast \(\mathrm{N}_2\mathrm{O}_5\) is consumed, thanks to stoichiometry. This specific problem illustrates that the rate of appearance of \(\mathrm{O}_2\) is \(2.40\, \mathrm{mol/min}\), which affects how quickly \(\mathrm{N}_2\mathrm{O}_5\) decomposes.
stoichiometry
Stoichiometry is the branch of chemistry that deals with the quantitative relationships between the amounts of reactants and products in a chemical reaction. In a balanced chemical equation, stoichiometric coefficients indicate the ratios in which substances react and form. For example, in the balanced equation\[ 2 \mathrm{N}_{2} \mathrm{O}_{5}(\mathrm{g}) \rightarrow 4 \mathrm{NO}_{2}(\mathrm{g}) + \mathrm{O}_{2}(\mathrm{g}), \]stochiometry tells us that - 2 moles of dinitrogen pentoxide decompose to produce: - 4 moles of nitrogen dioxide - 1 mole of oxygen gas.These coefficients are crucial because they allow us to calculate unknowns such as rates of appearance or disappearance. By using stoichiometry, we relate the rate of appearance of \(\mathrm{O}_2\) (\(2.40\, \mathrm{mol/min}\)) to find the rate of disappearance of \(\mathrm{N}_2\mathrm{O}_5\). The stoichiometric ratio between \(\mathrm{N}_2\mathrm{O}_5\) and \(\mathrm{O}_2\) in this reaction is 2:1, indicating that when 1 mole of \(\mathrm{O}_2\) is formed, 2 moles of \(\mathrm{N}_2\mathrm{O}_5\) are consumed.
dinitrogen pentoxide decomposition
Dinitrogen pentoxide (\(\mathrm{N}_2\mathrm{O}_5\)) is a chemical compound prone to decomposition, meaning it breaks down into simpler substances. In the process, it forms nitrogen dioxide (\(\mathrm{NO}_2\)) and oxygen (\(\mathrm{O}_2\)). The decomposition reaction is represented as:\[ 2 \mathrm{N}_{2} \mathrm{O}_{5}(\mathrm{g}) \rightarrow 4 \mathrm{NO}_{2}(\mathrm{g}) + \mathrm{O}_{2}(\mathrm{g}). \]This reaction is critical in understanding atmospheric chemistry and certain industrial processes. During decomposition, the bond energies in \(\mathrm{N}_2\mathrm{O}_5\) influence how easily it breaks down. Factors such as temperature and pressure can affect the rate of this decomposition. By solving problems involving \(\mathrm{N}_2\mathrm{O}_5\), students can learn valuable skills in predicting the behavior of other similar decomposition reactions based on molecular structure and energy considerations. Understanding such decomposition kinetics is vital for students learning about more complex reaction mechanisms or those interested in industrial applications where controlling reaction rates is necessary.

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Most popular questions from this chapter

Match the following: (Here \(\mathrm{a}=\) Initial concentration of the reactant, \(\mathrm{p}=\) Initial pressure of the reactant) List I List II A. \(t \frac{1}{2}=\) constant (p) Zero order B. \(\mathrm{t} \frac{1}{2} \alpha \mathrm{a}\) (q) First order C. \(\mathrm{t} 1 / 2 \alpha \mathrm{l} / \mathrm{a}\) (r) Second order D. \(t^{1 / 2} \alpha p^{-1}\) (s) Pseudo first order

What happens when the temperature of a reaction system is increased by \(10^{\circ} \mathrm{C}\) ? a. The effective number of collisions between the molecules possessing certain threshold energy increases atleast by \(100 \%\). b. The total number of collisions between reacting molecules increases atleast by \(100 \%\) c. The activation energy of the reaction is increased d. The total number of collisions between reacting molecules increases merely by \(1-2 \%\).

In the following question two statements Assertion (A) and Reason (R) are given Mark. a. If \(\mathrm{A}\) and \(\mathrm{R}\) both are correct and \(\mathrm{R}\) is the correct explanation of \(\mathrm{A}\); b. If \(A\) and \(R\) both are correct but \(R\) is not the correct explanation of \(\mathrm{A}\); c. \(\mathrm{A}\) is true but \(\mathrm{R}\) is false; d. \(\mathrm{A}\) is false but \(\mathrm{R}\) is true, e. \(\mathrm{A}\) and \(\mathrm{R}\) both are false. (A): Order of reaction is an experimental property and irrespective of the fact whether the reaction is elementary or complicated, it is the sum of the powers of the concentration terms appearing in the rate law that is, experimentally observed rate law. (R): Order of reaction may change with change in experimental conditions.

For the reaction \(\mathrm{P}+\mathrm{Q} \rightarrow 2 \mathrm{R}+\mathrm{S}\). Which of the following statement is/are correct? a. Rate of disappearance of \(\mathrm{P}=\) rate of appearance of \(\mathrm{S}\) b. Rate of disappearance of \(\mathrm{P}=\) rate of disappearance of \(\mathrm{Q}\) c. Rate of disappearance of \(\mathrm{Q}=2 \times\) rate of appearance of \(\mathrm{R}\) d. Rate of disappearance of \(\mathrm{Q}=1 / 2 \times\) rate of appearance of \(\mathrm{R}\)

The equation of tris(1,10-phenanthroline) iron(II) in acid solution takes place according to the equation: \(\mathrm{Fe}(\text { phen })_{3}^{2+}+3 \mathrm{H}_{3} \mathrm{O}^{+}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow\) \(\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}+3\) (phen) \(\mathrm{H}^{+}\) If the activation energy (Ea) is \(126 \mathrm{~kJ} / \mathrm{mol}\) and the rate constant at \(30^{\circ} \mathrm{C}\) is \(9.8 \times 10^{-3} \mathrm{~min}^{-1}\), what is the rate constant at \(50^{\circ} \mathrm{C}\) ? a. \(2.2 \times 10^{-1} \mathrm{~min}^{-1}\) b. \(3.4 \times 10^{-2} \mathrm{~min}^{-1}\) c. \(0.23 \times 10^{-1} \mathrm{~min}^{-1}\) d. \(1.2 \times 10^{-1} \min ^{-1}\)

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