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The experimental data for the reaction \(2 \mathrm{~A}+\mathrm{B}_{2} \rightarrow 2 \mathrm{AB}\) is \(\begin{array}{llll}\operatorname{Exp} . & {[\mathrm{A}]} & {\left[\mathrm{B}_{2}\right]} & \text { Rate }\left(\mathrm{Ms}^{-1}\right) \\\ 1 & 0.50 \mathrm{M} & 0.50 \mathrm{M} & 1.6 \times 10^{-4} \\ 2 & 0.50 \mathrm{M} & 1.00 \mathrm{M} & 3.2 \times 10^{-4} \\ 3 & 1.00 \mathrm{M} & 1.00 \mathrm{M} & 3.2 \times 10^{-4}\end{array}\) the rate equation for the above data is a. rate \(=\mathrm{k}\left[\mathrm{B}_{2}\right]\) b. rate \(=\mathrm{k}\left[\mathrm{B}_{2}\right]^{2}\) c. rate \(=\mathrm{k}[\mathrm{A}]^{2}[\mathrm{~B}]^{2}\) d. rate \(=\mathrm{k}[\mathrm{A}]^{2}[\mathrm{~B}]\)

Short Answer

Expert verified
The rate equation is \( \text{rate} = k [\text{B}_2] \).

Step by step solution

01

Determine the order with respect to B2

Compare Experiments 1 and 2. The concentration of \([\text{A}]\) remains constant while \([\text{B}_2]\) doubles. The rate also doubles (from \(1.6 \times 10^{-4}\) to \(3.2 \times 10^{-4}\)), indicating that the rate is directly proportional to \([\text{B}_2]\). This suggests the reaction is first order with respect to \([\text{B}_2]\).
02

Determine the order with respect to A

Compare Experiments 2 and 3. The concentration of \([\text{B}_2]\) is constant while \([\text{A}]\) doubles. The rate remains the same (\(3.2 \times 10^{-4}\)), indicating the rate is independent of \([\text{A}]\). Thus, the reaction is zero order with respect to \([\text{A}]\).
03

Write the rate equation

From the earlier steps, the reaction order is zero with respect to \([\text{A}]\) and first with respect to \([\text{B}_2]\). Hence, the rate equation is \( \text{rate} = k [\text{B}_2] \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Law
In chemical kinetics, the rate law is a mathematical expression that describes how the rate of a chemical reaction depends on the concentration of its reactants. The form of a rate law can reveal important information about the reaction mechanism and the relative speed of reaction.
By examining the rates at which reactions proceed in various conditions, chemists can deduce the specific rate law.
For the reaction given as \(2\, A + B_{2} \rightarrow 2\, AB\), we derive the rate law by observing changes in reactant concentrations against the reaction rate.
To decipher the rate law, the general process involves:
  • Conducting experiments to gather rate data at different concentrations.
  • Noting how the rate responds to changes in each reactant's concentration. This data helps determine the order of each reactant.
  • Formulating the rate law based on these observations and ensuring it matches experimental data.
The resulting rate law for this particular reaction is \( \text{rate} = k [B_2] \), where \(k\) is the rate constant and \([B_2]\) represents the concentration of \( B_2 \). This indicates the reaction is influenced solely by the concentration of \( B_2 \).
Reaction Order
The concept of reaction order is crucial for understanding how different concentrations affect reaction rates. Reaction order is defined as the power to which a reactant concentration is raised in the rate law. It reveals the dependency of the rate on a reactant's concentration.In our example problem, we learned that:
  • The order with respect to \([B_2]\) is 1. This is determined by observing that doubling \([B_2]\) also doubles the rate. Therefore, each doubling of \([B_2]\) leads to the rate doubling, showing a direct proportionality (first order) relationship.
  • The order with respect to \([A]\) is 0. This means changes in \([A]\) have no effect on the rate. Doubling \([A]\) leaves the rate unchanged, suggesting zero order.
The overall reaction order is the sum of the individual orders. In this case, the reaction is first order overall because it only depends on \([B_2]\), the first order component.
Experimental Data Analysis
Experimental data analysis is pivotal in formulating rate laws and understanding reaction mechanisms. In chemical kinetics, data from experiments are analyzed to discern patterns and relationships between reactant concentrations and reaction rates.For the given reaction, the analysis steps included:
  • Identifying experiments where only one reactant concentration changes. This helps isolate the effect of that specific reactant on the rate.
  • Comparing the effect of changes to one reactant while keeping others constant. For instance, changing \([B_2]\) while keeping \([A]\) constant showed a direct relation to the reaction rate.
  • Data interpretation to deduce reaction orders. A consistent pattern across experiments points to the orders of reactants. For instance, a doubling in \([B_2]\) leading to a doubled rate signified first order.
Through experimental data analysis, we find that just \([B_2]\) affects the rate, solidifying its role in the rate law expression \(\text{rate} = k[B_{2}]\). Such analyses are foundational for mastering chemical kinetics, ensuring accurate predictions for reaction behaviors.

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Most popular questions from this chapter

Match the following: (Here \(\mathrm{a}=\) Initial concentration of the reactant, \(\mathrm{p}=\) Initial pressure of the reactant) List I List II A. \(t \frac{1}{2}=\) constant (p) Zero order B. \(\mathrm{t} \frac{1}{2} \alpha \mathrm{a}\) (q) First order C. \(\mathrm{t} 1 / 2 \alpha \mathrm{l} / \mathrm{a}\) (r) Second order D. \(t^{1 / 2} \alpha p^{-1}\) (s) Pseudo first order

Match the following: List I List II 1\. zero order reaction (p) mole- \({ }^{1} \mathrm{Lt} \sec -1\) 2\. first order reaction (q) \(\mathrm{mole}-{ }^{2}\) Lt2 \(\mathrm{sec}-1\) 3\. second order reaction (r) mole Lt- \({ }^{-1} \sec -1\) 4\. third order reaction (s) \(\sec -1\)

Consider a reaction \(\mathrm{aG}+\mathrm{bH} \rightarrow\) Products. When concentration of both the reactants \(\mathrm{G}\) and \(\mathrm{H}\) is doubled, the rate increases by eight times. However when concentration of \(\mathrm{G}\) is doubled keeping the concentration of \(\mathrm{H}\) fixed, the rate is doubled. The overall order of the reaction is a. 0 b. 1 c. 2 d. 3

Which of the following expressions is/are not correct? a. \(\log \mathrm{k}=\log \mathrm{A}-\frac{\mathrm{Ea}}{2.303 \mathrm{RT}}\). b. \(\operatorname{In} \mathrm{A}=\operatorname{In} \mathrm{k}+\frac{\mathrm{Ea}}{\mathrm{RT}}\). c. \(\mathrm{k}\) Ae \(^{-R T / E a}\) d. In \(\mathrm{k}=\operatorname{In} \mathrm{A}+\mathrm{Ea} / \mathrm{RT}\)

For a first order reaction, which is/are correct here? a. The time taken for the completion of \(75 \%\) reaction is twice the \(t_{1 / 2}\) of the reaction b. The degree of dissociation is equal to \(1-\mathrm{e}^{-k t}\). c. A plot of reciprocal concentration of the reactant versus time gives a straight line d. The pre-exponential factor in the Arrhenius equation has the dimension of time, \(\mathrm{T}^{-1}\).

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