/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 The rate constant, the activatio... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The rate constant, the activation energy and the Arrhenius parameter of a chemical reaction at \(25^{\circ} \mathrm{C}\) are \(3.0 \times 10^{-4} \mathrm{~s}^{-1}, 104.4 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(6 \times 10^{14}\) \(\mathrm{s}^{-1}\) respectively. The value of the rate constant as \(\mathrm{T} \rightarrow \infty\) is a. \(2.0 \times 10^{18} \mathrm{~s}^{-1}\) b. \(6.0 \times 10^{14} \mathrm{~s}^{-1}\) c. infinity d. \(3.6 \times 10^{30} \mathrm{~s}^{-1}\)

Short Answer

Expert verified
The rate constant as \( T \to \infty \) is \( 6.0 \times 10^{14} \text{s}^{-1} \) (option b).

Step by step solution

01

Understanding the Arrhenius Equation

The Arrhenius Equation is given by \( k = A e^{-E_a/(RT)} \) where \( k \) is the rate constant, \( A \) is the Arrhenius pre-exponential factor, \( E_a \) is the activation energy, \( R \) is the universal gas constant, and \( T \) is the absolute temperature in Kelvin. When \( T \to \infty \), the exponential term \( e^{-E_a/(RT)} \) approaches 1 because \( E_a/(RT) \to 0 \).
02

Evaluating the Limit

As \( T \to \infty \), the rate constant \( k \) approaches the value of \( A \) since the exponential factor \( e^{-E_a/(RT)} \) approaches 1. Therefore, \( k = A \) when \( T \to \infty \).
03

Selecting the Correct Answer

Given that the Arrhenius parameter \( A \) is \( 6 \times 10^{14} \text{s}^{-1} \), the value of the rate constant as \( T \to \infty \) is \( 6 \times 10^{14} \text{s}^{-1} \). Thus, the correct choice is (b).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Constant
In the realm of chemical kinetics, the rate constant is a crucial factor in determining how fast a chemical reaction proceeds. Represented by the symbol \( k \), it is found in the Arrhenius Equation \( k = A e^{-E_a/(RT)} \). The rate constant isn't merely an arbitrary number; it provides insight into the speed of a reaction under specific conditions.

What makes the rate constant significant is its dependence on temperature. As the temperature increases, the rate constant typically increases, reflecting that reactions occur faster at higher temperatures. This is because molecules move more energetically and collide with greater force. However, it’s essential to note that the rate constant is unique to each reaction, influenced by factors such as the nature of reactants and products.

Understanding the rate constant helps chemists predict how a change in temperature might affect the speed of a reaction. It is a fundamental concept for anyone studying reaction dynamics, providing a window into the molecular world's fast-paced changes.
Activation Energy
Activation energy, denoted by \( E_a \), is the minimum amount of energy that reactant molecules must possess to react. It is a barrier or energy threshold that must be overcome for a reaction to proceed. In the Arrhenius Equation \( k = A e^{-E_a/(RT)} \), the term \( E_a \) plays a pivotal role in understanding how temperature affects the rate constant.

A higher activation energy means that fewer molecules will have enough energy to react, leading to a slower reaction rate. Conversely, a lower activation energy typically results in a faster reaction, as more molecules have sufficient energy to surpass the energy barrier.
  • The activation energy is often visualized using an energy profile diagram, showing the energy change during a reaction.
  • It helps explain why certain reactions are slow even under favorable conditions.
  • Reducing activation energy is a principle behind using catalysts to speed up reactions.
Activation energy is a key concept that underscores the importance of energy in chemical reactions, providing insight into their feasibility and speed.
Pre-exponential Factor
The pre-exponential factor, symbolized as \( A \) in the Arrhenius equation, is sometimes referred to as the frequency factor. This factor represents the number of times that reactants approach the activation barrier per unit time. In the equation \( k = A e^{-E_a/(RT)} \), \( A \) is crucial because it reflects conditions specific to the given reaction other than temperature effects.

The pre-exponential factor depends on various elements, including the frequency of collisions and the probability that those collisions are favorably oriented to lead to a reaction. Even when the activation energy is significant, a high pre-exponential factor suggests that many collisions still result in a reaction, ensuring that \( k \) remains relatively large.
  • It incorporates data about molecular orientation and steric factors, offering a more detailed picture of the dynamics involved.
  • \( A \) is often determined experimentally and can vary widely among different reactions.
Understanding the pre-exponential factor allows us to appreciate the complex interplay of molecules in a reaction, going beyond just energy considerations to also involve molecular geometry and movement.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the following question two statements Assertion (A) and Reason (R) are given Mark. a. If \(\mathrm{A}\) and \(\mathrm{R}\) both are correct and \(\mathrm{R}\) is the correct explanation of \(\mathrm{A}\); b. If \(A\) and \(R\) both are correct but \(R\) is not the correct explanation of \(\mathrm{A}\); c. \(\mathrm{A}\) is true but \(\mathrm{R}\) is false; d. \(\mathrm{A}\) is false but \(\mathrm{R}\) is true, e. \(\mathrm{A}\) and \(\mathrm{R}\) both are false. (A): Order can be different from molecularity of a reaction. (R): Slow step is the rate determining step and may involve lesser number of reactants.

The basic theory of Arrhenius equation is that (1) Activation energy and pre exponential factors are always temperature independent (2) The number of effective collisions is proportional to the number of molecule above a certain threshold energy. (3) As the temperature increases, the number of molecules with energies exceeding the threshold energy increases. (4) The rate constant in a function of temperature a. 2,3 and 4 b. 1,2 and 3 c. 2 and 3 d. 1 and 3

In the following question two statements Assertion (A) and Reason (R) are given Mark. a. If \(\mathrm{A}\) and \(\mathrm{R}\) both are correct and \(\mathrm{R}\) is the correct explanation of \(\mathrm{A}\); b. If \(A\) and \(R\) both are correct but \(R\) is not the correct explanation of \(\mathrm{A}\); c. \(\mathrm{A}\) is true but \(\mathrm{R}\) is false; d. \(\mathrm{A}\) is false but \(\mathrm{R}\) is true, e. \(\mathrm{A}\) and \(\mathrm{R}\) both are false. (A): A catalyst enhances the rate of reaction. ( \(\mathbf{R}\) ): The energy of activation of the reaction is lowered in presence of a catalyst.

The rate law for the reaction \(\mathrm{RCl}+\mathrm{NaOH} \rightarrow \mathrm{ROH}+\mathrm{NaCl}\) is given by Rate \(=\mathrm{k}(\mathrm{RCl})\). The rate of the reaction is a. Halved by reducing the concentration of \(\mathrm{RCl}\) by one half. b. Increased by increasing the temperature of the reaction. c. Remains same by change in temperature. d. Doubled by doubling the concentration of \(\mathrm{NaOH}\).

Hydrogen iodide decomposes at \(800 \mathrm{~K}\) via a second order process to produce hydrogen and iodine according to the following chemical equation. \(2 \mathrm{HI}(\mathrm{g}) \rightarrow \mathrm{H}_{2}(\mathrm{~g})+\mathrm{I}_{2}(\mathrm{~g})\) At \(800 \mathrm{~K}\) it takes 142 seconds for the initial concentration of \(\mathrm{HI}\) to decrease from \(6.75 \times 10^{-2} \mathrm{M}\) to \(3.50 \times 10^{-2} \mathrm{M}\). What is the rate constant for the reaction at this temperature? a. \(6.69 \times 10^{-3} \mathrm{M}^{-1} \mathrm{~s}^{-1}\) b. \(7.96 \times 10^{-2} \mathrm{M}^{-1} \mathrm{~s}^{-1}\) c. \(19.6 \times 10^{-3} \mathrm{M}^{-1} \mathrm{~s}^{-1}\) d. \(9.69 \times 10^{-2} \mathrm{M}^{-1} \mathrm{~s}^{-1}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.