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If the rate of the reaction is equal to the rate constant, the order of the reaction is a. 3 b. 0 c. 1 d. 2

Short Answer

Expert verified
The reaction order is 0.

Step by step solution

01

Understand the Concept of Reaction Order

Reaction order is determined by the sum of the powers of the concentration terms in the rate law equation. For a general reaction \( aA + bB \rightarrow cC \), the rate law can be expressed as \( ext{rate} = k[A]^m[B]^n \), where \( m \) and \( n \) are the orders with respect to reactants \( A \) and \( B \), respectively, and \( k \) is the rate constant.
02

Analyze the Given Condition

According to the problem, the rate of the reaction is equal to the rate constant. This implies that the concentration terms in the rate law do not affect the rate of the reaction. This situation arises when the reaction order is zero.
03

Conclusion Based on Analysis

When the reaction order is zero, the rate law becomes \( ext{rate} = k[A]^0[B]^0 = k \). This means the rate is solely dependent on the rate constant \( k \) and independent of the concentrations \( [A] \) and \( [B] \). Therefore, the correct order of the reaction is zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Constant
The rate constant, denoted as \( k \), plays a pivotal role in chemical kinetics as it determines the speed at which a reaction occurs. It appears in the rate law equation, which describes how the rate of reaction relates to the concentrations of reactants. Unlike concentrations, the rate constant is inherent to the reaction's nature and conditions. It varies with temperature and catalysts but remains unchanged with different concentrations of reactants.
To determine the value of \( k \), one must have experimental data which gives the rate of reaction at specific concentrations. It is a fundamental characteristic that not only indicates the reaction speed but also allows predictions of how variations in conditions may impact the reaction rate. By taking into account the temperature dependence of \( k \) through the Arrhenius equation, chemists can predict how reactions will proceed under various thermal conditions.
Rate Law Equation
The rate law equation is a mathematical expression that shows the relationship between the rate of a chemical reaction and the concentration of its reactants. It is fundamental in understanding how chemical reactions occur over time. The general form for a rate law is \( \text{rate} = k[A]^m[B]^n \), where \( [A] \) and \( [B] \) are the concentrations of the reactants, and \( m \) and \( n \) represent the reaction order with respect to each reactant. The sum of \( m \) and \( n \) gives the overall reaction order.
The coefficients \( m \) and \( n \) are determined experimentally and describe how changes in reactant concentrations influence the rate of reaction. Therefore, understanding the rate law equation helps predict whether increasing the concentration of a reactant will speed up or slow down the reaction. It enables chemists to manipulate conditions to optimize rates for industrial and laboratory processes.
Zero Order Reaction
A zero order reaction is a unique case wherein the rate of reaction is independent of the concentration of reactants. This essentially means that the concentration terms in the rate law equation are raised to the power of zero, yielding: \( \text{rate} = k \). This equation signifies that the rate is constant and only dependent on the rate constant \( k \).
In practical terms, zero order reactions often occur under conditions where a reactant is present in large excess or where the reaction surface is the limiting factor, such as in catalytic reactions. Because changes in concentration do not affect the rate, these reactions exhibit a linear decrease in reactant concentration over time. Such reactions are simpler to model mathematically and can provide insights into processes where one reactant does not deplete during the reaction.

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Most popular questions from this chapter

The rate constant for an isomerization reaction \(\mathrm{A} \rightarrow\) \(\mathrm{B}\), is \(4.5 \times 10^{-3} \mathrm{~min}^{-1}\). If the initial concentration of \(\mathrm{A}\) is \(1 \mathrm{M}\). Calculate the rate of reaction after 1 hour. a. \(0.34354 \mathrm{M} \mathrm{min}^{-1}\) b. \(0.034354 \mathrm{M} \mathrm{min}^{-1}\) c. \(0.0034354 \mathrm{M} \mathrm{min}^{-1}\) d. \(0.0003454 \mathrm{M} \mathrm{min}^{-1}\)

(A): A catalyst enhances the rate of reaction. (R) : The energy of activation of the reaction is lowered in presence of a catalyst.

The rate law has the form; Rate \(=\mathrm{k}[\mathrm{A}][\mathrm{B}]^{3 / 2}\), can the reaction be an elementary process? a. yes b. no c. may be yes or no d. can not be predicted

For the reaction \(2 \mathrm{NH}_{3} \rightarrow \mathrm{N}_{2}+3 \mathrm{H}_{2}\) it is found that \(-\frac{\mathrm{d} \mathrm{NH}_{3}}{\mathrm{dt}}=\mathrm{K}_{1}\left(\mathrm{NH}_{3}\right)\) \(\frac{\mathrm{d} \mathrm{N}_{2}}{\mathrm{dt}}=\mathrm{K}_{2}\left[\mathrm{NH}_{3}\right]\) \(\frac{\mathrm{dH}_{2}}{\mathrm{dt}}=\mathrm{K}_{3}\left[\mathrm{NH}_{3}\right]\) the correct relation between \(\mathrm{K}_{1}, \mathrm{~K}_{2}\) and \(\mathrm{K}_{3}\) can be given as ? a. \(3 \mathrm{~K}_{1}=2 \mathrm{~K}_{2}=6 \mathrm{~K}_{3}\) b. \(6 \mathrm{~K}_{1}=3 \mathrm{~K}_{2}=2 \mathrm{~K}_{3}\) c. \(\mathrm{K}_{1}=\mathrm{K}_{2}=\mathrm{K}_{3}\) d. \(2 \mathrm{~K}_{1}=3 \mathrm{~K}_{2}=6 \mathrm{~K}_{3}\)

Hydrogen iodide decomposes at \(800 \mathrm{~K}\) via a second order process to produce hydrogen and iodine according to the following chemical equation. \(2 \mathrm{HI}(\mathrm{g}) \rightarrow \mathrm{H}_{2}(\mathrm{~g})+\mathrm{I}_{2}(\mathrm{~g})\) At \(800 \mathrm{~K}\) it takes 142 seconds for the initial concentration of HI to decrease from \(6.75 \times 10^{-2} \mathrm{M}\) to \(3.50 \times 10^{-2} \mathrm{M}\). What is the rate constant for the reaction at this temperature?a. \(6.69 \times 10^{-3} \mathrm{M}^{-1} \mathrm{~s}^{-1}\) b. \(7.96 \times 10^{-2} \mathrm{M}^{-1} \mathrm{~s}^{-1}\) c. \(19.6 \times 10^{-3} \mathrm{M}^{-1} \mathrm{~s}^{-1}\) d. \(9.69 \times 10^{-2} \mathrm{M}^{-1} \mathrm{~s}^{-1}\)

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