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The rate constant of a first order reaction, \(\mathrm{A} \rightarrow\) products, is \(60 \times 10^{-4} \mathrm{~s}^{-1}\). Its rate at \([\mathrm{A}]=0.01 \mathrm{~mol}\) \(\mathrm{1}^{-1}\) would be a. \(60 \times 10^{-6} \mathrm{~mol} \mathrm{l}^{-1} \mathrm{~min}^{-1}\) b. \(36 \times 10^{-4} \mathrm{~mol} \mathrm{t}^{-1} \mathrm{~min}^{-1}\) c. \(60 \times 10^{-2} \mathrm{~mol} \mathrm{l}^{-1} \mathrm{~min}^{-1}\) d. \(36 \times 10^{-1} \mathrm{~mol} \mathrm{l}^{-1} \mathrm{~min}^{-1}\)

Short Answer

Expert verified
The correct option is b: \(36 \times 10^{-4} \ \text{mol} \ \text{t}^{-1} \ \text{min}^{-1}\).

Step by step solution

01

Understand the Reaction Rate Formula

For a first order reaction, the rate of the reaction can be expressed using the formula: \( \text{Rate} = k[A] \) where \( k \) is the rate constant and \( [A] \) is the concentration of the reactant A.
02

Insert Known Values into the Formula

The rate constant \( k \) is given as \( 60 \times 10^{-4} \ \text{s}^{-1} \) and the concentration \( [A] \) is given as \( 0.01 \ \text{mol} \ \text{l}^{-1} \). Insert these values into the rate formula: \[ \text{Rate} = 60 \times 10^{-4} \times 0.01 \].
03

Calculate the Rate

Perform the multiplication: \( 60 \times 0.01 = 0.6 \) and then multiply by \( 10^{-4} \), giving \( 0.6 \times 10^{-4} = 6 \times 10^{-5} \ \text{mol} \ \text{l}^{-1} \ \text{s}^{-1} \).
04

Convert Rate to the Correct Units

The options provided are in \( \text{mol} \ \text{l}^{-1} \ \text{min}^{-1} \), so we need to convert seconds to minutes by multiplying by 60 (since there are 60 seconds in a minute): \( 6 \times 10^{-5} \times 60 = 36 \times 10^{-4} \ \text{mol} \ \text{l}^{-1} \ \text{min}^{-1} \).
05

Match the Result with the Options

Compare our calculated rate \( 36 \times 10^{-4} \ \text{mol} \ \text{l}^{-1} \ \text{min}^{-1} \) with the options provided. The correct match is option b: \( 36 \times 10^{-4} \ \text{mol} \ \text{t}^{-1} \ \text{min}^{-1} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Constant
The rate constant is a vital parameter in reaction kinetics. It's a number that links the reaction rate to the concentration of reactants, fundamentally defining how fast a reaction proceeds. In a first order reaction like \(\mathrm{A} \rightarrow \text{products}\),the rate constant is expressed in units of \(\text{s}^{-1}\).This indicates that the reaction rate depends linearly on the concentration of reactant A.

Understanding the reaction rate involves knowing the rate constant \(k\).For example, a given rate constant of \(60 \times 10^{-4} \ \mathrm{s}^{-1}\)means that the reaction speed is relatively moderate, translating to a certain amount of reactant transforming into products per second.

The rate constant is crucial for predicting how long it will take for a reaction to reach a certain stage under specified conditions. It allows us to understand both the immediate rate of reaction and the long-term progress.
Reaction Rate
The reaction rate is a measurement of how quickly a chemical reaction occurs. In a first order reaction, the rate is directly proportional to the reactant's concentration. This can be observed using:
  • \( \text{Rate} = k[A] \)
Where \([A]\)is the concentration, and \(k\)is the rate constant.

By inputting known values into this formula, you can find the rate for any given concentration. For instance, using a rate constant of \(60 \times 10^{-4} \ \mathrm{s}^{-1}\)and a concentration \([A] = 0.01 \ \mathrm{mol} \ \mathrm{l}^{-1}\),the rate becomes:
  • \( \text{Rate} = 60 \times 10^{-4} \times 0.01 \)
This calculation helps understand how rapidly a reactant is transformed.

The reaction rate changes with concentration, and knowing this relationship lets chemists design experiments and predict outcomes more effectively.
Concentration
Concentration tells us how much of a substance is present in a certain volume. It is usually given in moles per liter (\(\mathrm{mol} \ \mathrm{l}^{-1}\)), also known as molarity. Concentration is crucial for determining how fast a reaction will happen.

In the context of first order reactions, the concentration \([A]\)plays a critical role in how quickly the reactants are converted into products. The higher the concentration, the faster the rate of reaction, assuming the rate constant \(k\)stays the same.

For example, with a concentration of \(0.01 \ \mathrm{mol} \ \mathrm{l}^{-1}\),the amount of reactant available at any moment directly affects the speed of the reaction. This highlights why concentration is a key factor in reaction kinetics.

Understanding concentration helps chemists control and manipulate reaction conditions, allowing for efficient and predictable chemical processes.
Unit Conversion
Unit conversion is essential in chemical kinetics to ensure all parameters align properly when performing calculations. In the context of reaction rates, units must often be converted to match the desired output format.

For example, the reaction rate might be calculated initially in \(\mathrm{mol}\ \mathrm{l}^{-1}\ \mathrm{s}^{-1}\),but you may need to express it in \(\mathrm{mol}\ \mathrm{l}^{-1}\ \mathrm{min}^{-1}\)for consistency with the units in a textbook or scientific paper.

To convert seconds to minutes, multiply by 60 (since there are 60 seconds in a minute). For instance:
  • \(6 \times 10^{-5} \ \mathrm{mol} \ \mathrm{l}^{-1} \ \mathrm{s}^{-1} \times 60 = 36 \times 10^{-4} \ \mathrm{mol} \ \mathrm{l}^{-1} \ \mathrm{min}^{-1}\)
This conversion is pivotal for ensuring all components of your calculations remain consistent.

Understanding unit conversions helps streamline quantitative analysis, allowing for coherent and logical progression from raw data to final results.

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Most popular questions from this chapter

The reaction: \(2 \mathrm{HI} \rightarrow \mathrm{H}_{2}+\mathrm{I}_{2}\), is second order and the rate constant at \(800 \mathrm{~K}\) is \(9.70 \times 10^{-2} \mathrm{M}^{-1} \mathrm{~s}^{-1}\). How long will it take for \(8.00 \times 10^{-2}\) mol/litre of HI to decrease to one-fourth of its initial concentration? a. \(587 \mathrm{~s}\) b. \(387 \mathrm{~s}\) c. \(148 \mathrm{~s}\) d. \(687 \mathrm{~s}\)

For a first order reaction, which is/are correct here? a. The time taken for the completion of \(75 \%\) reaction is twice the \(t_{1 / 2}\) of the reaction b. The degree of dissociation is equal to \(1-\mathrm{e}^{-k t}\). c. A plot of reciprocal concentration of the reactant versus time gives a straight line d. The pre-exponential factor in the Arrhenius equation has the dimension of time, \(T^{-1}\).

Which of the following statements are correct? (1) Order of a reaction can be known from experimental results and not from the stoichiometry of reaction. (2) Molecularity a reaction refers to (i) each of the elementary steps in (an overall mechanism of) a complex reaction or (ii) a single step reaction (3) Overall molecularity of a reaction may be determined in a manner similar to overall order of reaction(4) Overall order of a reaction \(\mathrm{A}^{\mathrm{m}}+\mathrm{B}^{\mathrm{n}} \rightarrow \mathrm{AB}_{\mathrm{x}}\) is \(\mathrm{m}+\mathrm{n} .\) Select the correct answer using the following codes: a. 2 and 3 b. 1,3 and 4 c. 2,3 and 4 d. 1,2 and 3

A three-step mechanism has been suggested for the formation of carbonyl chloride: Step I: \(\mathrm{Cl}_{2} \rightarrow 2 \mathrm{Cl}\) (fast, equilibrium) Step II: \(\mathrm{Cl}+\mathrm{CO} \rightarrow \mathrm{COCl}\) (fast, equilibrium) Step III: \(\mathrm{COCl}+\mathrm{Cl}_{2} \rightarrow \mathrm{COCl}_{2}+\mathrm{Cl}\) (slow)What is the molecularity of the rate- determining step? a. Termolecular b. Unimolecular c. Bimolecular d. None of these

The aquation of tris-(1,10-phenanthroline) iron (II) in acid solution takes place according to the equation: $$ \begin{aligned} \mathrm{Fe}(\mathrm{phen})_{3}^{2}+3 \mathrm{H}_{3} \mathrm{O}^{+}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow \\ \mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}+3 \text { (phen) } \mathrm{H}^{+} \end{aligned} $$ If the activation energy is \(126 \mathrm{~kJ} / \mathrm{mol}\) and frequency factor is \(8.62 \times 10^{17} \mathrm{~s}^{-1}\), at what temperature is the rate constant equal to \(3.63 \times 10^{-3} \mathrm{~s}^{-1}\) for the first order reaction?a. \(0^{\circ} \mathrm{C}\) b. \(50^{\circ} \mathrm{C}\) c. \(45^{\circ} \mathrm{C}\) d. \(90^{\circ} \mathrm{C}\)

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