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Which of the following statement is/are correct regarding a catalyst? a. Decreases the activation energy. b. Increases the average kinetic energy of reacting molecules. c. Increases the frequency of collision of reacting. d. Alters the reaction mechanism.

Short Answer

Expert verified
Correct statements are A and D.

Step by step solution

01

Understand the Role of a Catalyst

A catalyst is a substance that increases the rate of a chemical reaction without being consumed in the process. Catalysts work by providing an alternative reaction pathway with a lower activation energy.
02

Evaluate Statement A

Statement A suggests that a catalyst decreases the activation energy. This is correct because a catalyst provides an alternative pathway for the reaction, which requires less energy to initiate.
03

Evaluate Statement B

Statement B claims that a catalyst increases the average kinetic energy of reacting molecules. This is incorrect since a catalyst does not directly affect the kinetic energy of molecules; it only changes the pathway with lower activation energy.
04

Evaluate Statement C

Statement C suggests that a catalyst increases the frequency of collision of reacting molecules. This is incorrect as the catalyst does not increase the frequency of collisions but simply makes better use of the collisions that occur by lowering the activation energy threshold.
05

Evaluate Statement D

Statement D claims that a catalyst alters the reaction mechanism. This is correct because a catalyst provides an alternative mechanism for the reaction to proceed, typically with a lower activation energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Activation Energy
Activation energy is like a hurdle that reactants must overcome to form products during a chemical reaction. It’s the minimum amount of energy needed for reactants to collide with enough force to lead to a reaction. By lowering this threshold, reactions can occur more easily and quickly.
In a chemical process, reactants first need to overcome this energy barrier. Only then can they transition into products. Typically, higher activation energy means slower reactions, unless a catalyst is present.
  • A high activation energy implies a greater energy requirement for a reaction.
  • A low activation energy indicates that a reaction can occur more easily.
A catalyst facilitates reactions by creating an alternative pathway with a lower activation energy. This allows more reactant molecules to successfully collide and react, fostering quicker and more efficient reactions.
Reaction Mechanism
The reaction mechanism outlines the step-by-step sequence of elementary steps by which a chemical reaction occurs. It’s essentially the route that the molecules follow to transform from reactants to products. Each reaction mechanism consists of several intermediate stages, often involving transient species called intermediates.
Catalysts play a key role here. They provide an alternative reaction mechanism with a lower activation energy. This means even if the substance is not consumed in the process, it reshapes the path of the reaction.
  • Catalysts do not change the overall thermodynamics of the reaction but alter its kinetics.
  • By offering an alternative mechanism, catalysts ensure the reaction pathway becomes more favorable.
Through altering the mechanism, catalysts can make a seemingly slow reaction occur rapidly, without altering the quantity or nature of the final products.
Kinetic Energy
Kinetic energy, the energy of motion, plays a crucial part in chemical reactions. It’s the energy that reactants possess due to their movement or velocity. When molecules tumble and collide, it is this kinetic energy that contributes to breaking and forming new bonds.
Though a catalyst alters the reaction pathway, it doesn’t increase the average kinetic energy of reacting molecules. Rather, it makes existing kinetic energy more effective by providing a path of lower resistance in terms of activation energy.
Here are key points about kinetic energy in reactions:
  • Temperature often influences kinetic energy, as increased heat can mean more energetic collisions.
  • More energetic collisions can help overcome activation energy, thus speeding up reactions.
Overall, catalysts enhance reaction rates without affecting the inherent kinetic energy of individual molecules.
Collision Frequency
Collision frequency refers to how often reacting molecules collide with each other during a reaction. A general rule for making reactions faster is to increase how often reactant molecules collide.
While temperature, concentration, and pressure can heighten collision frequency, a catalyst doesn’t inherently increase this frequency. Instead, it optimizes the effectiveness of collisions through lowering the activation energy threshold.
This means that even if the collision frequency remains unchanged, more collisions result in a successful reaction due to the altered pathway.
  • Catalysts work by enhancing the productivity of each collision.
  • Not all collisions result in products; only those overcoming the activation energy do.
By making each collision count more effectively, catalysts enhance the overall efficiency of the reaction process.

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Most popular questions from this chapter

For the hypothetical second order reaction: \(\mathrm{A} \rightarrow\) Products, the general rate law is: Rate \(=\mathrm{k}[\mathrm{A}]^{2}\) How long is the third half life of the reaction if \([\mathrm{A}]_{0}\) is \(0.080 \mathrm{M}\) and the first half life is 22 minutes. a. \(48 \mathrm{~min}\) b. \(66 \mathrm{~min}\) c. \(88 \mathrm{~min}\) d. \(78 \mathrm{~min}\)

Which of the following expressions is/are not correct? a. \(\log \mathrm{k}=\log \mathrm{A}-\frac{\mathrm{Ea}}{2.303 \mathrm{RT}}\) b. \(\operatorname{In} \mathrm{A}=\operatorname{In} \mathrm{k}+\frac{\mathrm{Ea}}{\mathrm{RT}}\). C. \(\mathrm{k} \mathrm{Ae}^{-\mathrm{RT} / \mathrm{Fa}}\) d. \(\operatorname{In} \mathrm{k}=\operatorname{In} \mathrm{A}+\mathrm{Ea} / \mathrm{RT}\)

The decomposition of hydrogen peroxide is given by the following reaction: \(2 \mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{O}_{2}(\mathrm{~g})\) In the presence of KI the reaction is thought to occur by the following mechanism: Step \(\mathrm{I}: \mathrm{H}_{2} \mathrm{O}_{2}+\mathrm{I}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{IO}^{-}\) Step II: \(\mathrm{IO}^{-}+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}+\mathrm{I}^{-}\) What is the role of \(\mathrm{I}^{-}\)in this mechanism? a. Intermediate b. Transition state c. Catalyst d. Frequency factor

The rate law for the reaction \(\mathrm{RCl}+\mathrm{NaOH}(\mathrm{aq}) \rightarrow \mathrm{ROH}+\mathrm{NaCl}\) is given by Rate \(=\mathrm{k}[\mathrm{RCl}] .\) The rate of the reaction will be a. Doubled on doubling the concentration of sodium hydroxide b. Halved on reducing the concentration of alkyl halide to one half c. Decreased on increasing the temperature of reaction d. Unaffected by increasing the temperature of the reaction.

A complex reaction, \(2 \mathrm{~A}+\mathrm{B} \rightarrow \mathrm{C}\) takes place in two steps as follows: \(\mathrm{A}+\mathrm{B} \stackrel{\mathrm{k}_{1}}{\longrightarrow} 2 \mathrm{C}, \mathrm{A}+2 \mathrm{~B} \stackrel{\mathrm{k}_{2}}{\longrightarrow} \mathrm{C}\) If \(\mathrm{K}_{1}<<\mathrm{K}_{2}\), order of reaction is a. Zero order b. One c. Two d. Three

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