Chapter 6: Problem 67
The products formed when an aqueous solution of \(\mathrm{NaBr}\) is electrolyzed in a cell having inert electrodes are a. \(\mathrm{Na}\) and \(\mathrm{Br}_{2}\) b. \(\mathrm{Na}\) and \(\mathrm{O}_{2}\) c. \(\mathrm{H}_{2}, \mathrm{Br}_{2}\) and \(\mathrm{NaOH}\) d. \(\mathrm{H}_{2}\) and \(\mathrm{O}_{2}\)
Short Answer
Step by step solution
Identify the Electrolysis Reaction
Determine Possible Reactions at the Cathode
Determine Possible Reactions at the Anode
Summarize the Electrolysis Products
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cathode Reaction
In the case of aqueous NaBr, two key sets of ions are floating around: from the NaBr itself, we have Na鈦 and Br鈦, and from the water, there are H鈦 and OH鈦. While it might seem logical for the Na鈦 ions to grab electrons (2Na鈦 + 2e鈦 鈫 2Na), the reduction of water is actually favored under these aqueous conditions. Water molecules (2H鈧侽) also participate by accepting electrons, leading to the formation of hydrogen gas (H鈧) and hydroxide ions (2OH鈦).
- Reduction favored: 2H鈧侽 + 2e鈦 鈫 H鈧 + 2OH鈦
Anode Reaction
For aqueous NaBr, the Br鈦 ions are more readily oxidized than the water molecules. This means they'll lose electrons to form bromine gas (\(2Br^- 鈫 Br鈧 + 2e^-\)). The preference for bromide ion oxidation over water oxidation is crucial because it dictates that bromine (Br鈧) is released at the anode.
- Bromide oxidation favored: 2Br鈦 鈫 Br鈧 + 2e鈦
Reduction and Oxidation Reactions
In the electrolysis of NaBr, reduction occurs at the cathode, where water gains electrons, forming hydrogen gas and hydroxide ions:
- Reduction: 2H鈧侽 + 2e鈦 鈫 H鈧 + 2OH鈦
At the anode, oxidation occurs as bromide ions shed electrons, forming bromine gas:
- Oxidation: 2Br鈦 鈫 Br鈧 + 2e鈦
Formation of NaOH
The key lies in the hydroxide ions generated at the cathode. These 2OH鈦 ions remain in the solution, combining with the Na鈦 ions that had not been reduced. This amalgamation results in the formation of sodium hydroxide (NaOH).
- Net Result:
Na鈦 + OH鈦 鈫 NaOH
This property contributes to making the solution more alkaline and creates an essential by-product widely used in industry.
Electrochemical Cell
Within our cell for aqueous NaBr, inert electrodes serve as conduits for electrons. The cathode receives electrons where reduction of water occurs, while the anode expels electrons, allowing bromide to oxidize.
- Cathode (reduction site): \(2H鈧侽 + 2e鈦 鈫 H鈧 + 2OH鈦籠)
- Anode (oxidation site): \(2Br鈦 鈫 Br鈧 + 2e鈦籠)