Chapter 6: Problem 166
Use the following data at \(25^{\circ} \mathrm{C}\) for the questions given below \(\mathrm{Ni}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{Ni}(\mathrm{s}) \quad \mathrm{E}^{\circ}=-0.28 \mathrm{~V}\) \(\mathrm{Mg}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{Mg}(\mathrm{s}) \quad \mathrm{E}^{\circ}=-2.37 \mathrm{~V}\) What is \(\mathrm{K}\) for the equilibrium at \(25^{\circ} \mathrm{C}\) ? a. \(4 \times 10^{-70}\) b. \(4 \times 10^{70}\) c. \(2 \times 10^{-35}\) d. \(2 \times 10^{70}\)
Short Answer
Step by step solution
Write the overall cell reaction
Calculate the standard cell potential (E°cell)
Use the Nernst equation to find the equilibrium constant (K)
Compare calculated K with options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nernst Equation
- E is the cell potential at non-standard conditions.
- E\circ is the standard cell potential.
- R is the universal gas constant (8.314 J/mol K).
- T is the temperature in Kelvin.
- n is the number of moles of electrons transferred in the reaction.
- F is Faraday's constant (96485 C/mol), representing the charge of one mole of electrons.
- Q is the reaction quotient, representing the ratio of the concentrations of the products to the reactants.
Standard Cell Potential
- The cathode is where reduction occurs, and its potential should be negative in spontaneous galvanic cells.
- The anode is where oxidation takes place, typically having a more negative potential.
Half-Reactions in Electrochemistry
- The reduction half-reaction: \( \text{Ni}^{2+} + 2e^- \rightarrow \text{Ni} \) occurs at the cathode.
- The oxidation half-reaction: \( \text{Mg} \rightarrow \text{Mg}^{2+} + 2e^- \) occurs at the anode.
Redox Reactions
- Reduction refers to the gain of electrons, leading to a decrease in oxidation state.
- Oxidation refers to the loss of electrons, resulting in an increase in oxidation state.