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Which of the following reaction is/are not possible at anode? a. \(\mathrm{F}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{~F}^{-}\) b. \(2 \mathrm{H}^{+}+1 / 2 \mathrm{O}_{2}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}\) c. \(2 \mathrm{Cr}_{2}^{3+}+7 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-}\) d. \(\mathrm{Fe}^{2+} \rightarrow \mathrm{Fe}^{3+}+\mathrm{e}^{-}\)

Short Answer

Expert verified
Reactions A and B are not possible at the anode.

Step by step solution

01

Understanding the Role of Anode

In electrochemistry, the anode is the electrode where oxidation occurs. An oxidation reaction involves the loss of electrons. To find reactions that are not possible at the anode, identify which ones are reduction reactions or have electrons on the reactant side.
02

Analyze Reaction A

The reaction given is \( \mathrm{F}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{~F}^{-} \). This reaction involves the gain of electrons by \( \mathrm{F}_{2} \), which indicates a reduction process, not oxidation.
03

Analyze Reaction B

The reaction is \( 2 \mathrm{H}^{+}+1/2 \mathrm{O}_{2}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O} \). This involves the gain of electrons by \( 2 \mathrm{H}^{+} \) and \( 1/2 \mathrm{O}_{2} \), indicating reduction, not oxidation.
04

Analyze Reaction C

The reaction \( 2 \mathrm{Cr}_{2}^{3+}+7 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-} \) produces electrons on the product side, meaning this is an oxidation reaction, which is possible at the anode.
05

Analyze Reaction D

The reaction \( \mathrm{Fe}^{2+} \rightarrow \mathrm{Fe}^{3+}+\mathrm{e}^{-} \) involves the loss of electrons from \( \mathrm{Fe}^{2+} \), indicating an oxidation reaction, which can occur at the anode.
06

Determine Which Reactions Cannot Occur at the Anode

Reactions A and B are reduction reactions as they involve the gain of electrons. Since reduction occurs at the cathode, not the anode, both reactions cannot occur at the anode.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Anode Reactions
In electrochemistry, the concept of the anode is crucial in understanding half-cell reactions. The anode is where oxidation takes place. During oxidation, a species loses electrons and this electron loss usually results in an increase in the oxidation state of the species involved.
As electrons are released, they travel through an external circuit to the cathode, where reduction occurs. Therefore, anode reactions are always oxidation processes. For example, in reaction D:
* \( \mathrm{Fe}^{2+} \rightarrow \mathrm{Fe}^{3+} + \mathrm{e}^{-} \)* This represents the oxidation of iron (Fe), as it loses an electron.To determine if a reaction can occur at the anode, carefully look for electron release, or a lone electron on the products side of the equation.
Oxidation and Reduction
Oxidation and reduction reactions, also known as redox reactions, are essential processes in electrochemistry. These reactions always occur simultaneously, with oxidation being the loss of electrons and reduction the gain of electrons. When you see electrons on the right-hand side of a chemical equation, it indicates an oxidation reaction; whereas electrons on the left-hand side suggest a reduction reaction occurs.
For instance, in reaction C:
  • \(2 \mathrm{Cr}_{2}^{3+} + 7 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-} + 14 \mathrm{H}^{+} + 6 \mathrm{e}^{-}\)
* Here, chromium ions undergo oxidation, since the equation results in the production of electrons.Understanding these concepts helps in predicting the feasibility of a reaction at either the anode or the cathode in electrochemical cells.
Electron Transfer Processes
Electron transfer is the foundation of all electrochemical reactions. In a redox process, electrons are transferred from one chemical species to another. It's a delicate dance where one species' loss is another's gain. An electron transfer process can be analyzed based on the movement direction of electrons and the types of chemical species involved.
In reaction A:
  • \(\mathrm{F}_{2} + 2 \mathrm{e}^{-} \rightarrow 2 \mathrm{~F}^{-}\)
* Fluorine molecules gain electrons, indicating a reduction.By analyzing the presence of electrons in the reactant and product sides, one can determine the nature of the reaction. Only those reactions involving the release of electrons can occur at the anode, as oxidation leads to electron release. This small yet crucial understanding helps distinguish between possible and impossible reactions at the anode in an electrochemical cell.

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Most popular questions from this chapter

The emf of the cell \(\mathrm{Zn}\left|\mathrm{Zn}^{2+}(0.01 \mathrm{M}) \| \mathrm{Fe}^{2+}(0.001 \mathrm{M})\right| \mathrm{Fe}\) at 298 \(\mathrm{K}\) is \(0.2905\) volt. Then the value of equilibrium constant for the cell reaction is a. \(\mathrm{e}^{0.32 / 0.0295}\) b. \(10^{0.32 / 00295}\) c. \(10^{0.26 / 0.0295}\) d. \(10^{0.32 / 00591}\)

The \(\mathrm{emf}, \mathrm{E}\), is related to the change in Gibbs free energy, \(\Delta \mathrm{G}: \Delta \mathrm{G}=-\mathrm{nFE}\), where is the number of electrons transferred during the redox process and \(F\) is a unit called the Faraday. The faraday is the amount of charge on \(1 \mathrm{~mol}\) of electrons: \(1 \mathrm{~F}=96,500 \mathrm{C} / \mathrm{mol}\). Because \(\mathrm{E}\) is related to \(\Delta \mathrm{G}\), the sign of \(\mathrm{E}\) indicates whether a redox process is spontaneous: \(\mathrm{E}>0\) indicates a spontaneous process, and \(\mathrm{E}<0\) indicates a non-spontaneous one. The \(\mathrm{E}^{\circ}\) at \(298 \mathrm{~K}\) for the following reaction at the indicated concentrations is \(1.5 \mathrm{~V}\). Find the \(\Delta \mathrm{G}\) in \(\mathrm{kJ}\) at \(298 \mathrm{~K}\). \(\mathrm{Cr}(\mathrm{s})+3 \mathrm{Ag}^{+}(\mathrm{aq}, 0.1 \mathrm{M}) \rightarrow\) $$ \mathrm{Ag}(\mathrm{s})+\mathrm{Cr}^{3+}(\mathrm{aq}, 0.1 \mathrm{M}) $$ a. \(-422.83 \mathrm{~kJ}\) b. \(-212\) c. \(-295\) d. \(-140.94\)

While \(\mathrm{Fe}^{3+}\) is stable, \(\mathrm{Mn}^{3+}\) is not stable in acid solution because a. \(\mathrm{O}_{2}\) oxidizes \(\mathrm{Mn}^{2+}\) to \(\mathrm{Mn}^{3+}\) b. \(\mathrm{O}_{2}\) oxidizes both \(\mathrm{Mn}^{2+}\) to \(\mathrm{Mn}^{3+}\) and \(\mathrm{Fe}^{2+}\) to \(\mathrm{Fe}^{3+}\) c. \(\mathrm{Fe}^{3+}\) oxidizes \(\mathrm{H}_{2} \mathrm{O}\) to \(\mathrm{O}_{2}\) d. \(\mathrm{Mn}^{3+}\) oxidizes \(\mathrm{H}_{2} \mathrm{O}\) to \(\mathrm{O}_{2}\)

In the following question two statements (Assertion) A and Reason (R) are given. Mark a. if \(\mathrm{A}\) and \(\mathrm{R}\) both are correct and \(\mathrm{R}\) is the correct explanation of \(\mathrm{A}\); b. if \(A\) and \(R\) both are correct but \(R\) is not the correct explanation of A; c. \(\mathrm{A}\) is true but \(\mathrm{R}\) is false; d. A is false but \(\mathrm{R}\) is true, e. A and \(R\) both are false. (A): The mobility of sodium ion is lower than that of potassium ion. \((\mathbf{R}):\) The ionic mobilities depend upon the effective radius of the ion.

\(4.5 \mathrm{~g}\) of aluminium (at. mass 27 amu) is deposited at cathode from \(\mathrm{Al}^{3+}\) solution by a certain quantity of electric charge. The volume of hydrogen produced at STP from \(\mathrm{H}^{+}\)ions is solution by the same quantity of electric charge will be a. \(44.8 \mathrm{~L}\) b. \(22.4 \mathrm{~L}\) c. \(11.2 \mathrm{~L}\) d. \(5.6 \mathrm{~L}\).

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