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Consider the following: (I) \(\mathrm{KCl}\) (II) \(\mathrm{NH}_{4} \mathrm{Cl}\) (III) \(\mathrm{KCN}\) (IV) HCl The correct sequence in the order of increasing \(\mathrm{pH}\) of \(0.2 \mathrm{M}\) solution of these compounds will be a. \(I \|

Short Answer

Expert verified
The correct sequence is (d) \(\mathrm{IV}<\mathrm{I}<\mathrm{II}<\mathrm{III}\).

Step by step solution

01

Understand the nature of each compound

We must determine how each compound affects the \(\mathrm{pH}\) of its solution. \(\mathrm{KCl}\) and \(\mathrm{NH}_{4}\mathrm{Cl}\) dissociate into neutral and acidic ions, respectively. \(\mathrm{KCN}\) forms a basic solution due to the cyanide ion. \(\mathrm{HCl}\) is a strong acid and will lower the \(\mathrm{pH}\) significantly.
02

Analyzing KCl

KCl dissociates into K鈦 and Cl鈦 ions. K鈦 comes from KOH (which is a strong base) and Cl鈦 from HCl (strong acid), so KCl forms a neutral solution with pH = 7.
03

Analyzing NH鈧凜l

NH鈧凜l dissociates into NH鈧勨伜 (weak acid) and Cl鈦 (neutral ion). The NH鈧勨伜 ion hydrolyzes to produce H鈦 ions, making the solution slightly acidic, so the pH < 7.
04

Analyzing KCN

KCN dissociates into K鈦 (neutral) and CN鈦 ions. CN鈦 is a weak base that hydrolyzes to form OH鈦 ions, making the solution basic, so the pH > 7.
05

Analyzing HCl

HCl completely ionizes into H鈦 and Cl鈦 ions. The presence of free H鈦 ions makes HCl a strong acid, resulting in a much lower pH compared to the other solutions.
06

Determine order of increasing pH

Considering the above analyses: - \(\mathrm{HCl}\) will have the lowest \(\mathrm{pH}\).- \(\mathrm{NH}_{4}\mathrm{Cl}\) will have a higher \(\mathrm{pH}\) than \(\mathrm{HCl}\).- \(\mathrm{KCl}\) will be close to neutral but higher than \(\mathrm{NH}_{4}\mathrm{Cl}\).- \(\mathrm{KCN}\) will have the highest \(\mathrm{pH}\) as it's basic.So, the order is: HCl < NH鈧凜l < KCl < KCN.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acidic and Basic Properties
Acidic and basic properties of a substance are determined by its ability to donate or accept protons (H鈦 ions) in a solution. Strong acids, like hydrochloric acid (HCl), completely ionize in water, releasing a large number of H鈦 ions, which decreases the pH of the solution significantly. This makes the solution quite acidic. Conversely, bases release hydroxide ions (OH鈦) or accept protons, increasing a solution's pH and making it more basic.

Neutral solutions have equal concentrations of H鈦 and OH鈦 ions, which is typically what salts like potassium chloride (KCl) create. Although salts themselves are neither acids nor bases, their dissociation can affect a solution's pH depending on the nature of the ions produced. Understanding these properties is crucial for predicting the behavior of solutions, as well as for arranging substances by their increasing or decreasing pH levels.
Electrolyte Dissociation
Electrolyte dissociation refers to the process where ionic compounds dissociate into ions when dissolved in a solvent like water. This process is key to understanding the conductivity and pH of solutions.

For instance, when KCl dissolves in water, it breaks down into K鈦 and Cl鈦 ions, resulting in a neutral pH because both ions originate from a strong acid (HCl) and a strong base (KOH), which cancel each other's effects. Meanwhile, NH鈧凜l dissociates into NH鈧勨伜 and Cl鈦 ions. Here, NH鈧勨伜 is a weak acid, which undergoes hydrolysis (a process where it reacts with water to produce H鈦 ions), making the solution slightly acidic.
  • KCN, on the other hand, dissociates into K鈦 (neutral) and CN鈦 (weak base) ions, where CN鈦 hydrolyzes to form OH鈦 ions, making the solution basic.
  • Strong acids like HCl dissociate completely into H鈦 and Cl鈦, strongly decreasing the pH of the solution.
Understanding how different electrolytes dissociate helps predict and manipulate the pH of solutions.
Hydrolysis of Ions
Hydrolysis of ions is a chemical reaction where ions interact with water, affecting the pH of a solution. This is particularly important with ions that come from weak acids or bases. When such ions dissolve in water, they react to either release or absorb hydrogen ions (H鈦) or hydroxide ions (OH鈦), respectively.

For example, the NH鈧勨伜 ion, when in solution from NH鈧凜l, engages in hydrolysis to release H鈦 ions, thereby making the solution acidic. Similarly, the CN鈦 ion from KCN undergoes hydrolysis to release OH鈦 ions into the solution, thus making it basic.

Hydrolysis is key to explaining why salts derived from weak acids or bases can have non-neutral pH values.
Strong and Weak Acids and Bases
The distinction between strong and weak acids and bases lies in their ability to ionize in water. Strong acids, such as HCl, ionize completely, releasing all available H鈦 ions into the solution. This feature is also true for strong bases, which completely dissociate to produce OH鈦 ions.

Conversely, weak acids, like acetic acid (not in the current exercise context but relevant as a general example), only partially ionize, releasing fewer H鈦 ions into the solution. The same principle applies to weak bases, such as ammonia, which only partially dissociate in solution to produce OH鈦 ions.

This understanding helps predict solution pH and places substances like HCl at the far end of the pH scale as a strong acid, ensuring a clear comprehension of their role in achieving desired pH levels in various chemical processes.

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Most popular questions from this chapter

Which of the following are homogeneous equilibria? a. \(\mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}_{2}(\mathrm{~g})\) b. \(\mathrm{H}_{2}(\mathrm{~g})+\mathrm{X}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HX}(\mathrm{g})\) c. \(\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightleftharpoons \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) d. \(\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})\)

When \(0.1\) mole of \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) (ionization constant \(\left.\mathrm{K}_{\mathrm{b}}=5 \times 10^{-4}\right)\) is mixed with \(0.08 \mathrm{~mol} \mathrm{HCl}\) and the volume is made up of 1 litre. Find the \(\left[\mathrm{H}^{+}\right]\)of resulting solution. a. \(8 \times 10^{-2}\) b. \(2 \times 10^{-11}\) c. \(1.23 \times 10^{-4}\) d. \(8 \times 10^{-11}\)

Which of the following statement (s) is/are correct: a. A plot of \(\mathrm{P}\) vs \(1 / \mathrm{V}\) is linear at constant temperature b. A plot of \(\log _{10} K_{p}\) vs \(1 / T\) is linear c. A plot of \(\log [\mathrm{X}]\) vs time is linear for a first order reaction, \(\mathrm{X} \rightarrow \mathrm{P}\) d. A plot of \(\log _{10} \mathrm{P}\) vs \(1 / \mathrm{T}\) is linear at constant volume

Cyclohexane \(\left(\mathrm{C}_{6} \mathrm{H}_{12}\right)\) undergoes a molecular rearrangement in the presence of \(\mathrm{AlCl}_{3}\) to form methylcyclopentane (MCP) according to the equation: \(\mathrm{C}_{6} \mathrm{H}_{12} \rightleftharpoons \mathrm{MCP}\) If \(\mathrm{K}_{\mathrm{C}}=0.143\) at \(25^{\circ} \mathrm{C}\) for this reaction, predict the direction the reaction will shift, if the initial concentrations of \(\mathrm{C}_{6} \mathrm{H}_{12}\) and \(\mathrm{MCP}\) are \(0.200 \mathrm{M}\) and \(0.100 \mathrm{M}\), respectively. The system a. is already at equilibrium b. will shift right c. will shift left d. is not at equilibrium and will remain in an unequilibrated state.

The following two isomers of \(\mathrm{C}_{3} \mathrm{H}_{7} \mathrm{NO}\) exist in equilibrium with each other in solution: If \(\mathrm{K}_{\mathrm{C}}=0.57\) at \(25^{\circ} \mathrm{C}\) and the initial concentration of the reactant is \(0.50 \mathrm{M}\) and the product is \(0.70 \mathrm{M}\), what are the concentrations at equilibrium? a. \([\) Reactant \(]=0.46 \mathrm{M}\) and \([\) Product \(]=0.28 \mathrm{M}\) b. [Reactant] \(=0.69 \mathrm{M}\) and \([\) Product \(]=0.48 \mathrm{M}\) c. \([\) Reactant \(]=0.96 \mathrm{M}\) and \([\) Product \(]=0.47 \mathrm{M}\) d. [Reactant \(]=0.76 \mathrm{M}\) and [Product \(]=0.44 \mathrm{M}\)

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