Chapter 4: Problem 8
The enthalpy change \((\Delta \mathrm{H})\) for the reaction, \(\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{NH}_{3}(\mathrm{~g})\) is \(-92.38 \mathrm{~kJ}\) at \(298 \mathrm{~K}\). The internal energy change \(\Delta \mathrm{U}\) at \(298 \mathrm{~K}\) is a. \(-92.38 \mathrm{~kJ}\) b. \(-87.42 \mathrm{~kJ}\) c. \(-97.34 \mathrm{~kJ}\) d. \(-89.9 \mathrm{~kJ}\)
Short Answer
Step by step solution
Understand the Relationship Between ΔH and ΔU
Calculate Change in Moles of Gas (Δn)
Convert R to kJ and Calculate ΔnRT
Calculate ΔU Using ΔH and ΔnRT
Determine the Correct Answer
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