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\((\Delta H-\Delta U)\) for the formation of carbon monoxide (CO) from its elements at \(298 \mathrm{~K}\) is a. \(-1238.78 \mathrm{~J} \mathrm{~mol}^{-1}\) b. \(1238.78 \mathrm{~J} \mathrm{~mol}^{-1}\) c. \(-2477.57 \mathrm{~J} \mathrm{~mol}^{-1}\) d. \(2477.57 \mathrm{~J} \mathrm{~mol}^{-1}\)

Short Answer

Expert verified
The correct answer is option b: \(1238.78 \mathrm{~J} \mathrm{~mol}^{-1}\).

Step by step solution

01

Identify Given Reaction

The formation of carbon monoxide (CO) from its elements is given by the reaction: \[ \text{C (s)} + \frac{1}{2} \text{O}_2 (g) \rightarrow \text{CO} (g) \] at 298 K.
02

Write the Formula for \( \Delta H - \Delta U \)

The relationship between the change in enthalpy (\( \Delta H \)) and the change in internal energy (\( \Delta U \)) for gases is given by: \[ \Delta H - \Delta U = \Delta nRT \] where \( \Delta n \) is the change in moles of gas, \( R \) is the ideal gas constant \( (8.314 \, \text{J mol}^{-1} \text{K}^{-1}) \), and \( T \) is the temperature in Kelvin.
03

Calculate Change in Moles of Gas (\( \Delta n \))

In the given reaction: \[ \text{C (s)} + \frac{1}{2} \text{O}_2 (g) \rightarrow \text{CO} (g) \] the change in moles of gas \( (\Delta n) \) is calculated by subtracting the moles of gaseous reactants from the moles of gaseous products. \( \Delta n = 1 - \frac{1}{2} = \frac{1}{2} \).
04

Substitute Values into the Formula

Substitute \( \Delta n = \frac{1}{2} \), \( R = 8.314 \, \text{J mol}^{-1} \text{K}^{-1} \), and \( T = 298 \, \text{K} \) into the formula: \[ \Delta H - \Delta U = \left( \frac{1}{2} \right) \times 8.314 \, \text{J mol}^{-1} \text{K}^{-1} \times 298 \, \text{K} \].
05

Calculate \( \Delta H - \Delta U \)

Continuing the calculation: \[ \Delta H - \Delta U = \left( \frac{1}{2} \right) \times 8.314 \times 298 = 1238.78 \, \text{J mol}^{-1} \].
06

Determine the Correct Option

The calculated value of \( \Delta H - \Delta U \) for the formation of CO is \( 1238.78 \, \text{J mol}^{-1} \), which corresponds to option b.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Carbon monoxide formation
Carbon monoxide (CO) formation is a chemical reaction involving elements in their elemental form. In the case of CO formation, carbon (C) in solid form reacts with oxygen gas (\(\text{O}_2\)) to form carbon monoxide gas. This reaction can be represented as: \[\text{C (s)} + \frac{1}{2} \text{O}_2 (g) \rightarrow \text{CO} (g)\].
  • The reaction occurs at a temperature of 298 Kelvin.
  • This is an exothermic reaction, meaning it releases energy.
Understanding the molecular level of this reaction is important as carbon monoxide is a significant industrial gas and also an environmental pollutant. By comprehending its formation, we can understand its uses and how to control its emissions.
Ideal Gas Law
The Ideal Gas Law is a fundamental concept in chemistry that provides a simple relationship between pressure, volume, temperature, and the number of moles of a gas. It is represented by the equation: \(PV = nRT\). Here,
  • \(P\) stands for pressure,
  • \(V\) is volume,
  • \(n\) is the number of moles of the gas,
  • \(R\) is the ideal gas constant,\(8.314 \, \text{J mol}^{-1} \text{K}^{-1}\),
  • \(T\) is the temperature in Kelvin.
For the reaction \(\text{C (s)} + \frac{1}{2} \text{O}_2 (g) \rightarrow \text{CO} (g)\), the Ideal Gas Law allows us to assess changes that involve gases, like the change in number of moles. Knowledge of this law helps in deriving critical calculations like \(\Delta H - \Delta U\), crucial for understanding energetics of gas-phase reactions.
Reaction stoichiometry
Stoichiometry involves the quantitative relationship between reactants and products in a chemical reaction. For \(\text{C (s)} + \frac{1}{2} \text{O}_2 (g) \rightarrow \text{CO} (g)\), stoichiometry shows that one mole of carbon reacts with half a mole of oxygen gas to produce one mole of carbon monoxide gas. This calculation is key for determining the change in moles of gas \((\Delta n)\).
  • Products: 1 mole of CO gas.
  • Reactants: \(\frac{1}{2}\) mole of \(\text{O}_2\) gas.
The change in moles, \(\Delta n\), is calculated as: \(1 - \frac{1}{2} = \frac{1}{2}\). This value is essential in determining the energy change between enthalpy \((\Delta H)\) and internal energy \((\Delta U)\), indicating the extent of reaction under specific conditions. Stoichiometry thus forms a cornerstone of chemical calculation, linking microscopic interactions at molecular levels with observable macroscopic chemical phenomena.

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Most popular questions from this chapter

Among the following, the state function(s) is/are a. Internal energy b. Irreversible expansion work c. Reversible expansion work d. Molar enthalpy

A process is carried out at constant pressure. Given that \(\Delta \mathrm{H}\) is negative and \(\Delta \mathrm{E}\) is less than \(\Delta \mathrm{H}\), a. The system loses heat and contracts during the process b. The system loses heat and expands during the process c. The system absorbs heat and expands during the process d. The system absorbs heat and contracts during the process

The correct statement/s among the following is/are a. mass plus energy of the universe remains always constant while entropy of the universe remains increasing continuously b. an exothermic reaction with \(\Delta \mathrm{S}\) being positive, will be spontaneous only at high temperature c. in a reversible process, the system always in equilibrium with surroundings d. in any cyclic process \(\Delta \mathrm{X}=0\) where \(\mathrm{X}\) is a state fuction.

The heat liberated on complete combustion of \(7.8\) g benzene is \(327 \mathrm{~kJ}\). This heat was measured at constant volume and at \(27^{\circ} \mathrm{C}\). Calculate the heat of combustion of benzene at constant pressure ( \(\mathrm{R}\) \(\left.=8.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)\) a. \(-3274 \mathrm{~kJ} \mathrm{~mol}^{-1}\) b. \(-1637 \mathrm{~kJ} \mathrm{~mol}^{-1}\) c. \(-3270 \mathrm{~kJ} \mathrm{~mol}^{-1}\) d. \(-3637 \mathrm{~kJ} \mathrm{~mol}^{-1}\)

The solubility of manganese (II) fluoride in water is \(6.6 \mathrm{~g} / \mathrm{ml}\) at \(40^{\circ} \mathrm{C}\) and \(4.8 \mathrm{~g}\) /litre at \(100^{\circ} \mathrm{C}\). Based on this data, what is the sign of \(\Delta \mathrm{H}^{\circ}\) and \(\Delta \mathrm{S}^{\circ}\) for the following process? \(\mathrm{MnF}_{2}(\mathrm{~s}) \Rightarrow \mathrm{Mn}^{2+}(\mathrm{aq})+2 \mathrm{~F}^{-}(\mathrm{aq})\) a. \(\Delta \mathrm{H}^{\circ}\) is negative and \(\Delta \mathrm{S}^{\circ}\) is positive b. \(\Delta \mathrm{H}^{\circ}\) is negative and \(\Delta \mathrm{S}^{\circ}\) is negative c. \(\Delta \mathrm{H}^{\circ}\) is positive and \(\Delta \mathrm{S}^{\circ}\) is positive d. \(\Delta \mathrm{H}^{\circ}\) is positive and \(\Delta \mathrm{S}^{\circ}\) is negative

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