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As a given temperature and pressure, which of the following would be expected to have the greatest molar entropy? a. \(\mathrm{Br}_{2}(\mathrm{~g})\) b. \(\mathrm{Br}_{2}(\mathrm{~s})\) c. \(\mathrm{Br}_{2}\) (I) d. All of these would be expected to have the same molar entropy.

Short Answer

Expert verified
The greatest molar entropy is expected for \(\mathrm{Br}_{2}(\mathrm{~g})\).

Step by step solution

01

Understanding Entropy

Entropy is a measure of the disorder or randomness of a system. Generally, gases have higher entropy than liquids, which in turn have higher entropy than solids, because particles in gases are more disordered and have more freedom of movement.
02

Identify the States of Matter

Analyze the given substances: - \( \mathrm{Br}_{2}(\mathrm{~g}) \) is bromine gas. - \( \mathrm{Br}_{2}(\mathrm{~s}) \) is bromine solid. - \({\mathrm{Br}_{2}} ext{(I)} \) is bromine in liquid state.
03

Compare Entropy Based on States

Compare the entropy of each substance based on its state of matter. - Solids (such as \( \mathrm{Br}_{2}(\mathrm{~s}) \)) have the lowest entropy. - Liquids ( \ \( \mathrm{Br}_{2} \text{ (I)} \)) have a higher entropy than solids but lower than gases.- Gases (like \( \mathrm{Br}_{2}(\mathrm{~g}) \)) generally have the highest entropy due to the high degree of randomness and motion.
04

Conclusion Based on Entropy Comparison

The gas \(\mathrm{Br}_{2}(\mathrm{~g}) \) would be expected to have the greatest molar entropy compared to the solid and liquid forms of bromine.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Entropy and States of Matter
Entropy is a fascinating concept in thermodynamics that describes the degree of disorder or randomness in a system. It tells us how energy is spread in a system and how many configurations the system can have. One of the key aspects of understanding entropy is recognizing how it relates to the different states of matter. Each state鈥攕olid, liquid, and gas鈥攈as distinct characteristics that affect the system's entropy.
Solids have a very organized structure, with particles closely packed in a fixed arrangement. This limited arrangement means that solids have the lowest entropy among the three states of matter.
Liquids, on the other hand, have particles that can move around more freely compared to solids. This increased freedom of movement leads to a greater number of possible configurations, resulting in higher entropy than solids, but still less than gases.
Gases exhibit the highest entropy because their particles are widely spaced and can move rapidly in various directions. This high level of randomness and movement allows gases to have the highest number of possible configurations, and hence, the highest entropy.
Disorder and Randomness
When we talk about disorder and randomness, we're diving into another essential aspect of entropy. Disorder refers to the level of unpredictability or chaos in a system, while randomness pertains to the lack of a specific order or pattern. In thermodynamics, these terms help describe why and how entropy increases.
馃攳 **Why is Disorder Important?**
  • Disorder demonstrates how particles in different states of matter are arranged and move.
  • The greater the disorder, the higher the entropy because more configurations are possible.
As we progress from solid to liquid to gas, the molecules gain more kinetic energy, leading to increased disorder and randomness.
鉃★笍 **Examples of Randomness**
  • In solids, particles vibrate slightly around fixed positions, showcasing minimal randomness.
  • In liquids, particles slide over one another, indicating moderate randomness.
  • In gases, particles move chaotically and freely in all directions, representing the highest randomness.
Understanding these behaviors helps us comprehend why gases, like bromine gas, exhibit the greatest molar entropy in systems where comparisons are made.
Entropy Comparison
The process of comparing entropy among different substances or states provides insight into which systems are more disordered. This comparison also helps predict how a system may evolve over time. Let's compare the molar entropy of different states of bromine to understand these dynamics better.
  • **Solid Bromine**: In its solid state, bromine molecules are tightly packed. This rigid structure means fewer ways for particles to be arranged, giving solid bromine the lowest entropy.
  • **Liquid Bromine**: As a liquid, bromine particles have more freedom to move compared to a solid. This movement allows for a moderate level of disorder, making liquid bromine's entropy higher than solid bromine but lower than its gaseous form.
  • **Gaseous Bromine**: Here, bromine particles have the most freedom to move in any direction, resulting in the highest entropy. The extensive movement and spacing between particles create maximum disorder and randomness.
In conclusion, by understanding how to compare entropy across different states, we recognize that gaseous bromine holds the greatest molar entropy due to its high level of disorder and particle freedom.

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Most popular questions from this chapter

In a constant volume calorimeter, \(3.5\) of a gas with molecular weight 28 was burnt in excess oxygen at \(298.0 \mathrm{~K}\) The temperature of the calorimeter was found to increase from \(298.0 \mathrm{~K}\) to \(298.45 \mathrm{~K}\) due to the combustion process. Given that the heat capacity of the calorimeter is \(2.5 \mathrm{~kJ} \mathrm{~K}^{-1}\), the numerical value for the enthalpy of combustion of the gas in \(\mathrm{kJ} \mathrm{mol}^{-1}\) is a. 10 b. 100 c. 5 d. 95 [IIT 2009]

Which of the following expression is correct for an adiabatic process? a. \(\left(\mathrm{T}_{2} / \mathrm{T}_{1}\right)=\left(\mathrm{V}_{1} / \mathrm{V}_{2}\right)^{\mathrm{y}-1}\) b. \(\mathrm{P}_{2} / \mathrm{P}_{1}=\left(\mathrm{T}_{1} / \mathrm{T}_{2}\right)^{\gamma-1 / \mathrm{r}}\) c. \(\mathrm{P}_{2} \mathrm{~V}_{2}^{\gamma}=\mathrm{P}_{1} \mathrm{~V}_{1}^{\gamma}\) d. \(\mathrm{P}_{1} \mathrm{~V}_{1}^{-1}=\mathrm{P}_{2} \mathrm{~V}_{2}{ }^{\gamma-1}\)

Two mole of an ideal gas is expanded isothermally and reversibly from 1 litre of 10 litre at \(300 \mathrm{~K}\). The enthalpy change (in \(\mathrm{kJ}\) ) for the process is a. \(11.4 \mathrm{~kJ}\) b. \(-11.4 \mathrm{~kJ}\) c. \(0 \mathrm{~kJ}\) d. \(4.8 \mathrm{~kJ}\). [IIT 2004]

Which of the following is in accord with the three laws of thermodynamics? (I) The entropy of the universe never decreases. (II) A non-spontaneous process can occur if it is coupled to a process that is sufficiently spontaneous. a. I is true and II is false. b. I is false and II is true. c. Both I and II are true. d. Both I and II are false.

A particular reaction given below can be spontaneous if \(2 \mathrm{POCl}_{3}(\mathrm{~g}) \rightarrow 2 \mathrm{PCL}_{3}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g})\) \(\Delta \mathrm{H}^{\circ}=572 \mathrm{~kJ} ; \Delta \mathrm{S}^{\circ}=179 \mathrm{~J} / \mathrm{K}\) a. \(\mathrm{T}>1200 \mathrm{~K}\) b. \(\mathrm{T}>1600 \mathrm{~K}\) c. \(\mathrm{T}>2400 \mathrm{~K}\) d. \(T>3200 \mathrm{~K}\)

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