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In the following questions, two statements (Assertion) \(\mathrm{A}\) and Reason (R) are given. Mark a. If \(\mathrm{A}\) and \(\mathrm{R}\) both are correct and \(\mathrm{R}\) is the correct explanation of \(\mathrm{A}\) b. If \(\mathrm{A}\) and \(\mathrm{R}\) both are correct but \(\mathrm{R}\) is not the correct explanation of A c. A is true but \(\mathrm{R}\) is false d. A is false but \(\mathrm{R}\) is true e. \(\mathrm{A}\) and \(\mathrm{R}\) both are false (A): The kinetic energy of the photo-electron ejected increases with increase in intensity of incident light. \((\mathbf{R}):\) Increase in intensity of incident light increases the rate of emission.

Short Answer

Expert verified
d. A is false but R is true

Step by step solution

01

Identify the Assertion

The assertion (A) states that the kinetic energy of the photo-electron ejected increases with an increase in the intensity of incident light.
02

Determine the Truthfulness of the Assertion

The kinetic energy of the photo-electrons depends on the frequency of the incident light, not its intensity. Therefore, the assertion is false.
03

Identify the Reason

The reason (R) given is that an increase in the intensity of incident light increases the rate of emission of photo-electrons.
04

Determine the Truthfulness of the Reason

The rate of emission of photo-electrons does increase with an increase in the intensity of the incident light. Thus, the reason is true.
05

Evaluate the Relationship Between Assertion and Reason

Since the assertion is false, regardless of the reason being true, we need to select the option corresponding to false assertion and true reason.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
In the context of the photoelectric effect, kinetic energy refers to the energy that the ejected electrons acquire when light strikes the surface of a material. It's important to understand that this energy is not affected by the intensity of the light. Rather, it is determined by the frequency of the incident light. This is because only photons with sufficient energy (related to frequency) can transfer enough energy to release electrons from the material.

According to the equation governing the photoelectric effect, \[ \text{Kinetic Energy (KE)} = hf - \phi \] where \( h \) is Planck's constant, \( f \) is the frequency of the light, and \( \phi \) is the work function of the material. As such, higher frequency light (such as ultraviolet) leads to higher kinetic energy for the ejected electrons, provided it surpasses the work function. However, increasing the light's intensity doesn't increase the electrons' kinetic energy.
Light Intensity
Light intensity refers to the power per unit area received by the surface. In the photoelectric effect, intensity represents the number of photons striking the surface per second. Although it might seem intuitive to think that higher light intensity would result in more energetic electrons, that isn't the case. Instead, light intensity impacts other aspects of the phenomenon.

- More intensity translates to more photons. - More photons increase the number of ejected electrons but not their kinetic energy. - Intensity is sometimes confused with frequency, but they are distinct parameters of light. Understanding this distinction is vital when studying how light interacts with matter, especially in the photoelectric effect, where intensity specifically increases the quantity of electrons but not their energy output.
Emission Rate
The rate of emission in the context of the photoelectric effect relates to how quickly electrons are ejected from the material's surface. This is influenced directly by the intensity of the incoming light. As light intensity grows, more photons bombard the surface of the material in a given time. This increase in the number of photons directly translates to an increase in the number of electrons that are released.

Key points related to emission rate: - Emission rate is proportional to light intensity. - More light intensity means more electrons but does not affect their speed or energy. - It's possible to have a high emission rate with a relatively low kinetic energy if the frequency does not meet the necessary threshold for high energy.
Frequency Dependence
Frequency dependence is a pivotal concept in understanding the photoelectric effect. The frequency of incident light determines whether the photons have enough energy to eject electrons from the surface of a material.

Here's how it works: - Each material has a specific threshold frequency, which corresponds to the minimum energy required to release electrons. - If the light's frequency is below this threshold, no electrons will be emitted regardless of intensity. - Above this frequency, electrons will be emitted with kinetic energy proportional to the excess frequency (beyond the threshold). Therefore, frequency is the key factor controlling the kinetic energy of emitted electrons. The crucial formula linking frequency and kinetic energy is given by the equation mentioned previously. In essence, while intensity can increase emission rate, only frequency can alter the energy with which electrons are ejected.

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Most popular questions from this chapter

The atomic numbers of elements \(\mathrm{X}, \mathrm{Y}, \mathrm{Z}\) are 19,21 and 25 respectively. The number of electrons present in the 'M' shells of these elements follow the order a. \(Z>Y>X\) b. \(X>Y>Z\) c. \(Z>X>Y\) d. \(\mathrm{Y}>\mathrm{Z}>\mathrm{X}\)

Which of the following statement(s) about spectral series is/are correct? a. Paschen series appears in the infrared region b. The lines in the Balmer series corresponds to electron transitions from energy levels higher than \(\mathrm{n}=2\) energy level. c. Transitions from higher energy levels to \(5^{\text {th }}\) energy level produce Pfund series which falls in the infrared region d. The lines of Lyman series appear in the visible region

The Balmer-Rydberg equation can be extended to ions with only one electron, such as \(\mathrm{He}^{+}\). In that case it has the form: \(1 / \lambda=\mathrm{Z}^{2} \mathrm{R}\left(1 / \mathrm{m}^{2}-1 / \mathrm{n}^{2}\right)\), here \(\mathrm{Z}\) is the atomic number. What is the energy of the photon required to promote an electron in He' from a 1 s-orbital to a \(2 \mathrm{p}\)-orbital? a. 12 hcR b. 6 hcR c. 3 hcR d. \((3 / 4)\) hcR

Transition of an electron from \(\mathrm{n}=3\) level to \(\mathrm{n}=1\) level results in: a. Band spectrum b. IR spectrum c. Emission spectrum d. X-ray spectrum

Which of the following is/are correct? a. the energy of an electron depends only on the principal quantum numbers not on the other quantum numbers b. the energy of an electron depends only on the principal quantum number in case of hydrogen and hydrogen like atoms. c. the difference in potential energies of any two energy level is always more than the difference in kinetic energies of these two levels. d. an electron in an excited state can always emit a photon or two but can not absorb a photon

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