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The kinetic energy of photoelectron emitted on irradiating a metal surface with frequency \(v\) is related by \(\mathrm{KE}=\mathrm{hv}-\mathrm{IE}\). The plots of \(\mathrm{KE}\) vs. incidented frequency \(\mathrm{v}\) shows: a. A straight line with slope equal to Planck's constant. b. A straight line with intercept on \(x\)-axis equal to the product of threshold frequency and Planck's constant. c. A straight line with extrapolated intercept on \(\mathrm{y}\) axis equal to ionization energy d. A straight line with intercept on \(x\)-axis equal to threshold frequency

Short Answer

Expert verified
Options a, c, and d are correct.

Step by step solution

01

Understanding the Equation

The equation given is \( KE = hv - IE \), where \( KE \) is the kinetic energy of the photoelectron, \( h \) is Planck's constant, \( v \) is the frequency of the incident light, and \( IE \) is the ionization energy. This equation resembles the equation of a straight line \( y = mx + c \), where the slope \( m \) is Planck's constant \( h \), and the intercept \( c \) is \(-IE\).
02

Analyzing Plot of KE vs. Frequency \( v \)

When \( KE \) is plotted against \( v \), the plot is a straight line with slope equal to \( h \), based on \( KE = hv - IE \). The equation suggests that when zero kinetic energy is reached, the frequency \( v \) is equal to the threshold frequency \( u_0 \), because that's when the photon energy \( hv \) matches the ionization energy, making the remaining energy (kinetic energy) zero.
03

Understanding Intercepts on the Axes

The line intercepts the \( x \)-axis when \( KE = 0 \), meaning when \( hv = IE \). Thus, the intercept on the \( x \)-axis is the threshold frequency \( u_0 = \frac{IE}{h} \). For the \( y \)-axis, when \( v = 0 \), the \( KE \) is \(-IE\), showing the \( y \)-intercept represents the negative of the ionization energy.
04

Matching with Options

Based on our interpretation: - (a) is correct as the slope is \( h \), Planck's constant.- (b) is incorrect because the \( x \)-axis intercept represents \( u_0 \), not \( u_0 \cdot h \).- (c) is correct because the \( y \)-intercept is indeed \(-IE\).- (d) is correct as the \( x \)-intercept is the threshold frequency \( u_0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy of Photoelectrons
The kinetic energy of photoelectrons emitted from a metal surface is a fundamental concept of the photoelectric effect. When light with a certain frequency hits the surface, electrons are ejected. The energy these electrons carry when they leave the surface is what we refer to as their kinetic energy (KE).
The formula that represents this is given by \( KE = hv - IE \). In this equation:
  • \( KE \) stands for the kinetic energy of the photoelectrons.
  • \( h \) is Planck's constant.
  • \( v \) is the frequency of the incident light.
  • \( IE \) is the ionization energy of the metal.
Understanding this equation is like looking at a straight line equation \( y = mx + c \), where the slope \( m \) corresponds to Planck’s constant \( h \). The ionization energy \( IE \), representing the energy required to remove an electron, acts as the constant \( c \). The kinetic energy comes into play only when the photon energy \( hv \) surpasses the ionization energy \( IE \). Therefore, it highlights when electrons are ejected with measurable speed.
Planck's Constant
Planck’s constant \( h \) is a very important element of quantum mechanics. It is a universal constant that relates the energy of a photon to its frequency. The equation \( E = hv \) encapsulates this relationship where \( E \) is energy, \( h \) is Planck’s constant, and \( v \) is frequency.
In the context of the photoelectric effect:
  • Planck's constant appears as the slope in the kinetic energy equation \( KE = hv - IE \).
  • Acts as a bridge to convert the light frequency into energy that can be applied to eject an electron.
The value of Planck’s constant is approximately \( 6.626 \times 10^{-34} \) joule-seconds. This small value reflects the atomic scale on which these interactions occur. It plays a critical role in determining the energy level of the emitted photoelectrons.
Threshold Frequency
The threshold frequency \( u_0 \) is the minimum frequency of light required to liberate electrons from a metal surface. This concept is key in understanding which frequencies can initiate the photoelectric effect.
If the frequency of the incident light is below this threshold, regardless of the intensity or the duration of exposure, no electrons will be emitted. Here is how it ties into the equation:
  • The threshold frequency can be derived when \( KE = 0 \), resulting in \( u_0 = \frac{IE}{h} \).
  • It marks the point at which \( hv = IE \) — the photon energy just matches the ionization energy.
When plotting the kinetic energy vs. the frequency of incident light, the threshold frequency appears as the intercept on the x-axis, indicating the lowest point where electrons can start being emitted.

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