Chapter 3: Problem 109
The wavelength of the radiation emitted, when in a hydrogen atom electron falls from infinity to stationary state 1 , would be (Rydberg constant \(=1.097\) \(\left.\times 10^{7} \mathrm{~m}^{-1}\right)\) a. \(91 \mathrm{~nm}\) b. \(192 \mathrm{~nm}\) c. \(406 \mathrm{~nm}\) d. \(9.1 \times 10^{-3} \mathrm{~nm}\)
Short Answer
Step by step solution
Understanding the energy transition
Using the Rydberg Formula
Applying values to the formula
Calculating the wavelength
Verifying the solution with given options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hydrogen Atom Transitions
Wavelength Calculation
- \( \lambda \) is the wavelength of the emitted light
- \( R \) is the Rydberg constant, which is \( 1.097 \times 10^7 \text{ m}^{-1} \)
- \( n_1 \) and \( n_2 \) are the principal quantum numbers of the initial and final energy levels