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Which of the following gases has the highest average speed at \(400 \mathrm{~K}\) ? a. \(\mathrm{SF}_{6}\) b. \(\mathrm{UF}_{6}\) c. \(\mathrm{CO}_{2}\) d. \(\mathrm{N}_{2} \mathrm{O}_{4}\)

Short Answer

Expert verified
\( \mathrm{CO}_{2} \) has the highest average speed at 400 K.

Step by step solution

01

Understanding Root Mean Square Speed Formula

To determine which gas has the highest average speed, we'll use the formula for the root mean square speed (RMS speed) of gas molecules: \( v_{rms} = \sqrt{\frac{3kT}{m}} \), where \( k \) is the Boltzmann constant, \( T \) is the temperature in Kelvin, and \( m \) is the molar mass of the gas. Notice that the speed is inversely proportional to the square root of the molar mass \( m \). Therefore, to find the gas with the highest speed, we need to find the one with the lowest molar mass.
02

Calculating Molar Masses

For each gas, calculate its molar mass:- \( \mathrm{SF}_{6} \): sulfur (32 g/mol) + 6 fluorines (6 x 19 g/mol) = 146 g/mol- \( \mathrm{UF}_{6} \): uranium (238 g/mol) + 6 fluorines (6 x 19 g/mol) = 352 g/mol- \( \mathrm{CO}_{2} \): carbon (12 g/mol) + 2 oxygens (2 x 16 g/mol) = 44 g/mol- \( \mathrm{N}_{2} \mathrm{O}_{4} \): 2 nitrogens (2 x 14 g/mol) + 4 oxygens (4 x 16 g/mol) = 92 g/mol
03

Identifying the Gas with Lowest Molar Mass

From the calculated molar masses, \( \mathrm{CO}_{2} \) has the lowest molar mass of 44 g/mol. Since RMS speed is inversely related to the square root of molar mass, \( \mathrm{CO}_{2} \) should have the highest average speed among the gases listed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Root Mean Square Speed
The concept of Root Mean Square Speed (RMS speed) is crucial in understanding the behavior of gas molecules. It offers a way to measure the average speed of particles in a gas. The formula for RMS speed is given by: \[ v_{rms} = \sqrt{\frac{3kT}{m}} \] where:
  • \( v_{rms} \) is the root mean square speed.
  • \( k \) is the Boltzmann constant (\(1.38 \times 10^{-23} \mathrm{~J/K}\)).
  • \( T \) is the temperature in Kelvin.
  • \( m \) is the molar mass of the gas molecules.
The equation reveals that RMS speed depends on both the temperature and the molar mass of the gas. More specifically, it shows that as the temperature increases, the RMS speed rises. Conversely, higher molar mass results in a lower RMS speed. Therefore, understanding the interplay between these variables helps us predict which gas particles will travel faster, with lighter gases generally moving quicker at the same temperature.
Molar Mass Calculation
Calculating the molar mass of a gas is a fundamental step in determining various properties of the gas, like its root mean square speed. Molar mass is found by summing up the atomic masses of all atoms in a molecule. Let's consider the gases in the example: - For \( \mathrm{SF}_6 \), sulfur has an atomic mass of 32 g/mol, and each fluorine atom has 19 g/mol. Thus, \( \mathrm{SF}_6 \) = 32 + (6 \times 19) = 146 g/mol. - For \( \mathrm{UF}_6 \), the uranium atom has 238 g/mol. So, \( \mathrm{UF}_6 \) = 238 + (6 \times 19) = 352 g/mol. - In \( \mathrm{CO}_2 \), carbon is 12 g/mol and oxygen is 16 g/mol, hence, \( \mathrm{CO}_2 \) = 12 + (2 \times 16) = 44 g/mol. - Lastly, for \( \mathrm{N}_2\mathrm{O}_4 \), nitrogen is 14 g/mol and oxygen is 16 g/mol, resulting in \( \mathrm{N}_2\mathrm{O}_4 \) = (2 \times 14) + (4 \times 16) = 92 g/mol.
By comparing the molar masses, it’s clear that \( \mathrm{CO}_2 \) has the lowest molar mass, which corresponds to the highest RMS speed within this group of gases.
Boltzmann Constant
The Boltzmann constant is a vital component in the realm of thermodynamics and statistical mechanics. This constant, denoted by \( k \), links the average kinetic energy of particles in a gas with the temperature of the gas and works as a bridge between macroscopic and microscopic physics. Its value is \( 1.38 \times 10^{-23} \mathrm{~J/K} \).
This constant appears in the equation for root mean square speed, embedding the connection between temperature and kinetic energy into the speed calculation. Essentially, it allows us to understand how temperature influences the speed and energy of particles. At a higher temperature, the boost in energy means particles move faster, a concept that is mathematically supported by the Boltzmann constant in our RMS speed equation.
Thus, the Boltzmann constant serves an essential role in unlocking the mysteries of molecular motion, highlighting its importance in practical calculations involving gases and their behaviors.

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Most popular questions from this chapter

The gas equation for a real gas is: \(P(V-b)=R T\) Here, the parameter 'b' is Van der Waal's constant. The graph of pressure against temperature (isochore) will give straight line of slope: a. Negative b. Zero c. \(\mathrm{R} /(\mathrm{V}-\mathrm{b})\) d. \(\mathrm{R} / \mathrm{P}\)

Match the following: Column I (Gases under Column II (Properties) specified condition) A. Hydrogen gas \((\mathrm{P}=\) (p) Compressibility fac\(200 \mathrm{~atm}, \mathrm{~T}=273 \mathrm{~K}\) ) tor \(\neq 1\) B. Hydrogen gas ( \(\mathrm{P} \sim 0\), (q) Attractive forces are \(\mathrm{T}=273 \mathrm{~K})\) dominant C. \(\mathrm{CO}_{2}(\mathrm{P}=1 \mathrm{~atm}, \mathrm{~T}=\) (r) \(\mathrm{PV}=\mathrm{nRT}\) \(273 \mathrm{~K}\) ) D. Real gas with very (s) \(\mathrm{P}(\mathrm{V}-\mathrm{nb})=\mathrm{nRT}\) large molar volume

Equal weights of methane and oxygen are mixed in an empty container at \(25^{\circ} \mathrm{C}\). the fraction of the total pressure exerted by oxygen is a. \(1 / 2\) b. \(2 / 3\) c. \(1 / 3 \times 273 / 298\) d. \(1 / 3\)

If a gas expands at constant temperature a. the pressure decreases b. the kinetic energy of the molecules remains the same c. the kinetic energy of the molecules decreases d. the number of molecules of the gas increase.

Which of the following statement is/are correct here? a. Gases cannot be directly condensed into solids without passing through liquid state b. Gases and liquids have viscosity as common property c. Gases and liquids have pressure as common property d. Particles in all the three states have random translational motion.

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