Chapter 2: Problem 191
Match the following: Column I Column II A. Gas constant (R) (p) \(\mathrm{mol} \mathrm{dm}^{-3}\) B. Ionic product of water (q) \(\mathrm{mol}^{2} \mathrm{dm}^{-6}\) \((\mathrm{Kw})\) C. Van der Waal's con- (r) \(\mathrm{dm}^{3}\) atm \(\mathrm{K}^{-1} \mathrm{~mol}^{-1}\) stant (A) D. Equilibrium constant (s) \(\mathrm{dm}^{6}\) atm \(\mathrm{mol}^{-2}\) of \(\mathrm{HA}_{c}(\mathrm{k})\)
Short Answer
Step by step solution
Identify Units
Match Gas Constant (R)
Match Ionic Product of Water (Kw)
Match Van der Waal's Constant (A)
Match Equilibrium Constant
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gas Constant
The value of \( R \) can be expressed in various units, but in most cases, it is often given as \( 8.314 \, \text{J} \, \text{mol}^{-1} \, \text{K}^{-1} \) or \( 0.0821 \, \text{dm}^3 \, \text{atm} \, \text{K}^{-1} \, \text{mol}^{-1} \). The unit \( \text{dm}^3 \text{ atm } \text{K}^{-1} \text{ mol}^{-1} \) is particularly useful when dealing with gas reactions at standard atmospheric pressure.
Knowing \( R \) allows us to predict how a gas will behave under different temperatures and pressures, which is crucial for many practical applications in fields such as chemistry and engineering.
- Common unit: \( \text{dm}^3 \text{ atm } \text{K}^{-1} \text{ mol}^{-1} \)
- Key equation: \( PV = nRT \)
Ionic Product of Water
- Formula: \( K_w = [\text{H}^+][\text{OH}^-] \)
- Key value at 25°C: \( 1.0 \times 10^{-14} \) \( \text{mol}^2 \text{ dm}^{-6} \)
Van der Waal's Constant
- Equation: \[\left(P + \frac{a}{V_m^2}\right)(V_m - b) = RT\]
- Constant \( A \, \) units: \( \text{dm}^6 \text{ atm } \text{ mol}^{-2} \)
Equilibrium Constant
Equilibrium constants are core to understanding chemical dynamics, reactions in aqueous solutions, and predicting how changes in conditions impact reaction equilibrium.
- Formula: \( K_{eq} = \frac{[C]^c [D]^d}{[A]^a [B]^b} \)
- Application: Predicts reaction dynamics