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Which of these quantities are same for all ideal gases at any particular temperature? a. The number of molecules in \(1 \mathrm{gm}\) b. The kinetic energy of \(1 \mathrm{~mole}\) c. The kinetic energy of \(1 \mathrm{gm}\) d. The number of molecules in 1 mole

Short Answer

Expert verified
The quantities that are the same for all ideal gases at a particular temperature are the kinetic energy of 1 mole (b) and the number of molecules in 1 mole (d).

Step by step solution

01

Understanding the Question

We need to identify which physical quantity is the same for all ideal gases at a particular temperature. The options involve concepts like the number of molecules and kinetic energy of gases.
02

Recognize Ideal Gas Properties

Recall that for any ideal gas, at a specific temperature, the kinetic energy of 1 mole of the gas is determined by its temperature and is given by the formula: \[ KE = \frac{3}{2}RT \]where \( R \) is the gas constant and \( T \) is the temperature in Kelvin. This is the same for all gases when considering 1 mole at the same temperature.
03

Examining Individual Options

Let's evaluate each option: 1. Number of molecules in 1 gm depends on the molecular weight of the gas, hence variable.2. Kinetic energy of 1 mole is consistent for all ideal gases at that temperature due to the formula \( KE = \frac{3}{2}RT \).3. Kinetic energy of 1 gm varies by type of gas (due to different molecular weights).4. Number of molecules in 1 mole is invariant due to Avogadro's number, always \( 6.022 \times 10^{23} \) for any substance.
04

Evaluating Consistent Quantities

Among the options, both the kinetic energy of 1 mole (Option b) and the number of molecules in 1 mole (Option d) are consistent across all ideal gases at a given temperature. The key differences arise in parts a and c because they depend on the identity of the gas due to variations in molecular weight.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Kinetic Energy of Gases
When studying ideal gases, it's essential to grasp the concept of kinetic energy. Kinetic energy in gases refers to the energy that their molecules have due to motion. For any ideal gas at a specific temperature, the kinetic energy of the gas molecules depends on that temperature and is actually independent of the gas type.

The kinetic energy equation for one mole of an ideal gas is expressed as: \[ KE = \frac{3}{2}RT \] where:
  • \( KE \) is the kinetic energy,
  • \( R \) is the universal gas constant \( (8.314 \text{ J/mol K}) \),
  • \( T \) is the absolute temperature in Kelvin.
This equation illustrates that the kinetic energy of one mole of an ideal gas at a given temperature is consistent, regardless of the gas type. Thus, for quantities like the kinetic energy of 1 mole of an ideal gas, their values remain unchanged for different gases at the same temperature.
The Role of Avogadro's Number
Avogadro's number is a fundamental constant in chemistry and plays a crucial role in understanding the behavior of gases. It represents the number of particles, usually atoms or molecules, in one mole of a substance. Numerically, Avogadro's number is: \( 6.022 \times 10^{23} \) particles per mole.

This constant is vital when considering the number of molecules in any given mole of a gas or any substance. It ensures consistency across different ideal gases. For instance, 1 mole of oxygen gas (\( O_2 \)) contains the same number of molecules as 1 mole of hydrogen gas (\( H_2 \))—both have \( 6.022 \times 10^{23} \) molecules.

Avogadro's number allows chemists and scientists to convert between the number of atoms/molecules and moles effortlessly, making calculations and comparisons straightforward.
Temperature Dependence of Kinetic Energy
The kinetic energy of gases is intricately linked to temperature. In physics and chemistry, the kinetic theory of gases explains this relationship using the ideal gas law and kinetic energy equations. Fundamentally, the temperature of a gas is a measure of the average kinetic energy of its molecules. As the temperature increases, so does the average kinetic energy, leading to faster molecular motion.

When the temperature of an ideal gas rises:
  • The speed of the gas molecules increases, which can be observed as higher kinetic energy.
  • The kinetic energy formula \( KE = \frac{3}{2}RT \) shows direct proportionality to temperature \( T \), meaning as \( T \) increases, so does \( KE \).
This temperature dependence is crucial because it explains why the behavior of gases changes under different thermal conditions. For example, a gas at higher temperature will exert more pressure on its container walls due to the higher kinetic energy of its molecules compared to the same gas at a lower temperature. Understanding this concept helps explain and predict the behavior of gases when subjected to heat changes.

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Most popular questions from this chapter

At low pressures, the van der Waal's gas equation for 1 mole of a gas may be written as a. \(\mathrm{PV}=\mathrm{RT}-\frac{\mathrm{a}}{\mathrm{V}}\) b. \(\mathrm{PV}=\mathrm{RT}\) c. \(\mathrm{PV}=\mathrm{RT}+\mathrm{Pb}\) d. \(\mathrm{P}+\frac{\mathrm{a}}{\mathrm{V}^{2}}=\frac{\mathrm{RT}}{\mathrm{V}}\)

(A): The gases \(\mathrm{He}\) and \(\mathrm{CO}_{2}\) are very different in their behaviour at any temperature and pressure, but their compressilibility factors are nearly the same. (R): The 'Law of corresponding states' states that the compressibility factor of any gas can be written as a universal function of the reduced variables.

The rate of effusion of two gases 'a' and 'b' under identical conditions of temperature and pressure are in the ratio of \(2: 1\). What is the ratio of \(\mathrm{rms}\) velocity of their molecules if \(\mathrm{T}_{\mathrm{a}}\) and \(\mathrm{T}_{\mathrm{b}}\) are in the ratio of \(2: 1\) ? a. \(\sqrt{2}: 1\) b. \(2: 1\) c. \(1: \sqrt{2}\) d. \(2 \sqrt{2}: 1\)

A flask filled with \(\mathrm{CCl}_{4}\) vapour was weighed at a temperature and pressure. The flask was then filled with oxygen at the same temperature and pressure. The mass of \(\mathrm{CCl}_{4}\) vapours would be about a. Five times as heavy as oxygen b. Twice as heavy as oxygen c. The same as that of the oxygen d. One-fifth as heavy as oxygen

At constant volume, for a fixed number of mole of a gas, the pressure of the gas increases with rise of temperature due to a. Increased rate of collisions amongst molecules b. Decrease in mean free path c. Increase in average molecular speed d. Increase in molecular attraction

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