Chapter 11: Problem 46
Two radioactive elements A and B have decay constant \(\lambda\) and \(10 \lambda\) respectively. If decay begins with the same number of atoms of the \(n\), the ratio of atoms of \(\mathrm{A}\) to those of \(\mathrm{B}\) after time \(1 / 9 \lambda\) will be a. \(e^{-3}\) b. \(e^{2}\) c. e d. \(\mathrm{e}^{-1}\)
Short Answer
Step by step solution
Understanding Decay Formula
Determine Remaining Atoms of A
Determine Remaining Atoms of B
Calculate Ratio of A to B Atoms
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Decay Constant
- A higher decay constant means the substance will decay faster.
- A smaller decay constant indicates a slower rate of decay.
Exponential Decay Formula
- \(N(t)\) is the number of atoms remaining after time \(t\).
- \(N_0\) is the initial number of atoms.
- \(\lambda\) is the decay constant.
- \(t\) is the time elapsed.
Ratio of Radioactive Atoms
- The number of atoms remaining for element A is \( n e^{-\frac{1}{9}} \).
- The number of atoms remaining for element B is \( n e^{-\frac{10}{9}} \).