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The equivalent weight of phosphoric acid \(\left(\mathrm{H}_{3} \mathrm{PO}_{4}\right)\) in the reaction: \(\mathrm{NaOH}+\mathrm{H}_{3} \mathrm{PO}_{4} \rightarrow \mathrm{NaH}_{2} \mathrm{PO}_{4}+\mathrm{H}_{2} \mathrm{O}\) is a. 89 b. 98 c. 59 d. 29

Short Answer

Expert verified
The equivalent weight of H鈧働O鈧 in this reaction is 98 g/eq, so answer b is correct.

Step by step solution

01

Define Equivalent Weight

Equivalent weight is defined as the molecular weight of a substance divided by the number of moles of reactive species (H+ ions in the case of acids) that participate in the chemical reaction.
02

Determine Molecular Weight of H鈧働O鈧

To calculate the molecular weight of phosphoric acid (H鈧働O鈧), sum the atomic weights of all atoms: 3 Hydrogen (H) atoms (3 脳 1 = 3), 1 Phosphorus (P) atom (1 脳 31 = 31), and 4 Oxygen (O) atoms (4 脳 16 = 64). The molecular weight is 3 + 31 + 64 = 98 g/mol.
03

Identify the Reaction Context

In the given reaction, \( ext{NaOH + H}_3 ext{PO}_4 ightarrow ext{NaH}_2 ext{PO}_4 + ext{H}_2 ext{O}\), H鈧働O鈧 contributes only one ionizable hydrogen ion (H鈦) to form NaH鈧侾O鈧. Thus, it acts as a monoprotic acid here.
04

Compute Equivalent Weight of H鈧働O鈧

Since in this specific reaction phosphoric acid behaves as if it donates only one H鈦 ion, its equivalent weight here is its molecular weight divided by 1. Therefore, the equivalent weight of H鈧働O鈧 is 98/1 = 98 g/eq.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Phosphoric Acid
Phosphoric acid, with the chemical formula \( \mathrm{H}_3 \mathrm{PO}_4 \), is a common inorganic acid used in various chemical applications. It is a triprotic acid, meaning it has three hydrogen atoms that can potentially dissociate as hydrogen ions \( \text{H}^+ \). This property makes it highly versatile, as it can participate in different reactions depending on the chemical circumstances. In its pure form, phosphoric acid is a crystalline solid at room temperature, but it is usually encountered in liquid form as aqueous solutions. Understanding the behavior of phosphoric acid in chemical reactions is crucial for various industrial processes, such as fertilizer production and metal treatment.
Chemical Reaction
Chemical reactions involve the transformation of one or more substances into new substances through the breaking and forming of chemical bonds. In the reaction given, phosphoric acid \( \mathrm{H}_3 \mathrm{PO}_4 \) and sodium hydroxide \( \mathrm{NaOH} \) are the reactants. The product formed by this specific reaction includes sodium dihydrogen phosphate \( \mathrm{NaH}_2 \mathrm{PO}_4 \) and water \( \mathrm{H}_2 \mathrm{O} \). This is an example of an acid-base reaction where an acid reacts with a base to produce salt and water. Such reactions are central to understanding chemical processes in biological systems and industrial settings.
Molecular Weight
Molecular weight, also known as molecular mass, is the sum of the atomic weights of all atoms in a molecule. It's expressed in units of grams per mole (g/mol), helping quantify substances in chemical reactions. To calculate the molecular weight of phosphoric acid \( \mathrm{H}_3 \mathrm{PO}_4 \), add up the atomic weights:
  • 3 atoms of Hydrogen (H): \(3 \times 1 = 3\) g/mol
  • 1 atom of Phosphorus (P): \(1 \times 31 = 31\) g/mol
  • 4 atoms of Oxygen (O): \(4 \times 16 = 64\) g/mol
Combine these values for a total molecular weight of \(98\) g/mol. This value is vital for determining the equivalent weight and plays a crucial role in stoichiometry calculations within chemical reactions.
Acid-Base Reaction
Acid-base reactions are a fundamental type of chemical reaction characterized by the transfer of \( \text{H}^+ \) ions from an acid to a base. In the reaction between phosphoric acid \( \mathrm{H}_3 \mathrm{PO}_4 \) and sodium hydroxide \( \mathrm{NaOH} \), the \( \text{H}^+ \) ion from phosphoric acid reacts with the \( \text{OH}^- \) ion from sodium hydroxide to form water. The remaining parts of the molecules combine to form sodium dihydrogen phosphate. This exchange of ions emphasizes the versatile nature of acids in donating protons and bases in accepting them, which is a key concept in the study of chemistry. Understanding acid-base reactions is essential for grasping broader chemical phenomena, such as buffer solutions and the pH scale.

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Most popular questions from this chapter

The weight of a single atom of oxygen is a. \(5.057 \times 10^{23} \mathrm{~g}\) b. \(1.556 \times 10^{25} \mathrm{~g}\) c. \(2.656 \times 10^{-25} \mathrm{~g}\) d. \(4.538 \times 10^{-23} \mathrm{~g}\)

1 \(\mathrm{g}\) atom of oxygen can have a. \(22.4\) litre of \(\mathrm{O}_{2}\) at N.T.P. b. \(6.02 \times 10^{25} \mathrm{O}_{2}\) molecules c. \(16 \mathrm{~g}\) of \(\mathrm{O}_{2}\) d. \(11.2\) litre of \(\mathrm{O}_{2}\) at N.T.P.

Which one of the following statements is/are correct? a. One mole of \(\mathrm{CH}_{4}\) and \(17 \mathrm{~g} \mathrm{NH}_{3}\) at NTP occupies same volume b. One gram mole of silver equals \(108 / 6.023 \times 10^{25} \mathrm{~g}\) c. One gram mole of \(\mathrm{CO}_{2}\) is \(6.023 \times 10^{23}\) times heavier than one molecule of \(\mathrm{CO}_{2}\) d. One mole Ag weighs more than that of two moles of Ca

A \(6.977 \mathrm{~g}\) sample of a mixture was analysed for barium ion by adding a small excess of sulphuric acid to an aqueous solution of the sample. The resultant reaction produced a precipitate of barium sulphate, which was collected by filtration, washed, dried and weighed. If \(0.4123 \mathrm{~g}\) of barium sulphate was obtained, what was the mass percentage of barium in the sample? a. \(6.952 \%\) b. \(3.476 \%\) c. \(4.376 \%\) d. \(1.738 \%\)

(A): In CO molecule 12 parts by mass of carbon combine with 16 parts by mass of oxygen and in \(\mathrm{CO}_{2}, 12\) parts by mass of carbon combine with 32 parts by mass of oxygen. (R): When two elements combine separately with a fixed mass or a third element, then the ratio of their masses in which they do so is either the same or whole number multiple of the ratio in which they combine with each other.

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