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The Arrhenius parameters for the reaction described by \\[ \mathrm{HO}_{2}(\mathrm{g})+\mathrm{OH}(\mathrm{g}) \longrightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \\] are \(A=5.01 \times 10^{10} \mathrm{dm}^{3} \cdot \mathrm{mol}^{-1} \cdot \mathrm{s}^{-1}\) and \(E_{\mathrm{a}}=4.18 \mathrm{kJ} \cdot \mathrm{mol}^{-1}\). Determine the value of the rate constant for this reaction at \(298 \mathrm{K}\).

Short Answer

Expert verified
The rate constant \( k \) at 298 K is approximately \( 9.27 \times 10^9 \, \mathrm{dm}^3 \, \mathrm{mol}^{-1} \, \mathrm{s}^{-1} \).

Step by step solution

01

Understand the Arrhenius Equation

The Arrhenius equation is given by \( k = A e^{-E_a/(RT)} \), where \( k \) is the rate constant, \( A \) is the pre-exponential factor, \( E_a \) is the activation energy, \( R \) is the universal gas constant \(8.314 \text{ J/mol·K}\), and \( T \) is the temperature in Kelvin.
02

Convert Units if Necessary

Since the activation energy \(E_a\) is given in kilojoules per mole (kJ/mol), convert it to joules per mole (J/mol) by multiplying by 1000. Thus, \( E_a = 4.18 \times 1000 = 4180 \text{ J/mol} \).
03

Plug Values into the Arrhenius Equation

Substitute the values into the Arrhenius equation: \[ k = 5.01 \times 10^{10} \, \mathrm{dm}^3 \, \mathrm{mol}^{-1} \, \mathrm{s}^{-1} \times e^{-4180/(8.314 \, \times \, 298)} \]
04

Calculate the Exponential Term

First calculate the exponent: \( \frac{4180}{8.314 \times 298} \approx 1.686 \). Then compute the exponential: \( e^{-1.686} \approx 0.185 \).
05

Calculate the Rate Constant

Now, calculate the rate constant by multiplying the pre-exponential factor \( A \) by the exponential term: \( k = 5.01 \times 10^{10} \times 0.185 \approx 9.27 \times 10^{9} \, \mathrm{dm}^3 \, \mathrm{mol}^{-1} \, \mathrm{s}^{-1} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Constant
The rate constant, usually represented by the symbol \( k \), is a fundamental part of the Arrhenius equation used to describe the rate of a chemical reaction. It indicates how fast a reaction proceeds at a given temperature. In many cases, the larger the rate constant, the faster the reaction.

When dealing with temperature-dependent reactions, the Arrhenius Equation,\[ k = A e^{-E_a/(RT)} \] is used to calculate \( k \). Here:
  • \( A \) is the pre-exponential factor
  • \( E_a \) is the activation energy
  • \( R \) is the universal gas constant
  • \( T \) is the temperature in Kelvin
For example, if one substitutes known values into the equation, such as in our given reaction at \( 298 \text{ K} \) with \( A = 5.01 \times 10^{10} \) and calculated \( e^{-1.686} \approx 0.185 \), the rate constant can be computed to be \( 9.27 \times 10^{9} \, \text{dm}^3 \, \text{mol}^{-1} \, \text{s}^{-1} \). This outcome suggests a reasonably quick reaction under these conditions.
Activation Energy
Activation energy, denoted as \( E_a \), is the minimum energy required for a reaction to occur. It represents a barrier that reactant molecules must overcome for a reaction to proceed.

In the context of the Arrhenius equation, activation energy plays a crucial role in determining the rate constant. It is inversely related to the rate of reaction; a lower activation energy means a faster reaction because less energy is needed for the reactants to reach the transition state. The exponential term \( e^{-E_a/(RT)} \) becomes significant here, as even small changes in \( E_a \) can lead to large changes in the reaction rate.
  • \( E_a \) is usually given in \( \text{kJ/mol} \), but needs converting to \( \text{J/mol} \) in calculations.
  • Impacts how temperature changes affect reaction speed.
For the given reaction, the activation energy \( E_a \) is \( 4.18 \text{ kJ/mol} \), converted to \( 4180 \text{ J/mol} \) for usage in the calculation. This value impacts how sensitively the rate constant will respond to changes in temperature.
Pre-exponential Factor
The pre-exponential factor, denoted by \( A \) in the Arrhenius equation, is often referred to as the frequency factor or the steric factor. It represents the number of correctly oriented collisions between reactant molecules per unit time and is usually obtained experimentally.

This factor accounts for the frequency and orientation of collisions that result in the formation of products. In essence, \( A \) indicates the inherent likelihood of a reaction occurring, provided the correct orientation and proximity of reacting molecules.
  • \( A \) is a constant specific to each chemical reaction.
  • It has the same units as the rate constant, ensuring dimensional consistency.
From our exercise, \( A \) is given as \( 5.01 \times 10^{10} \, \text{dm}^3 \, \text{mol}^{-1} \, \text{s}^{-1} \), showing a high collision frequency, implying that under ideal conditions, the reaction could proceed very swiftly. Understanding \( A \) helps assess how different reactions might proceed under similar conditions.

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Most popular questions from this chapter

Consider the general chemical reaction \\[ A+B \stackrel{k_{1}}{\sum_{i=1}} P \\] If we assume that both the forward and reverse reactions are first order in their respective reactants, the rate law is given by (Equation 26.52 ) \\[ \frac{d[\mathrm{P}]}{d t}=k_{1}[\mathrm{A}][\mathrm{B}]-k_{-1}[\mathrm{P}] \\] Now consider the response of this chemical reaction to a temperature jump. Let \([\mathrm{A}]=\) \([\mathrm{A}]_{2 . \mathrm{c}_{9}}+\Delta[\mathrm{A}],[\mathrm{B}]=[\mathrm{B}]_{2, \mathrm{eq}}+\Delta[\mathrm{B}],\) and \([\mathrm{P}]=[\mathrm{P}]_{2, \mathrm{eq}}+\Delta[\mathrm{P}],\) where the subscript "2,eq" \(^{\text {" }}\) refers to the new equilibrium state. Now use the fact that \(\Delta[\mathrm{A}]=\Delta[\mathrm{B}]=-\Delta[\mathrm{P}]\) to show that Equation 1 becomes \\[ \begin{aligned} \frac{d \Delta[\mathrm{P}]}{d t}=& k_{1}[\mathrm{A}]_{2, \mathrm{eq}}[\mathrm{B}]_{2, \mathrm{eq}}-k_{-1}[\mathrm{P}]_{2, \mathrm{eq}} \\\ &-\left\\{k_{1}\left([\mathrm{A}]_{2, \mathrm{eq}}+[\mathrm{B}]_{2, \mathrm{eq}}\right)+k_{-1}\right\\} \Delta[\mathrm{P}]+O\left(\Delta[\mathrm{P}]^{2}\right) \end{aligned} \\] Show that the first terms on the right side of this equation cancel and that Equations 26.53 and 26.54 result.

Hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}\), decomposes in water by a first-order kinetic process. A \(0.156\)-mol \(\cdot \mathrm{dm}^{-3}\) solution of \(\mathrm{H}_{2} \mathrm{O}_{2}\) in water has an initial rate of \(1.14 \times\) \(10^{-5} \mathrm{~mol} \cdot \mathrm{dm}^{-3} \cdot \mathrm{s}^{-1}\). Calculate the rate constant for the decomposition reaction and the half-life of the decomposition reaction.

The oxidation of hydrogen peroxide by permanganate occurs according to the equation \\[ \begin{aligned} 2 \mathrm{KMnO}_{4}(\mathrm{aq})+3 \mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq})+5 \mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq}) \longrightarrow 2 \mathrm{MnSO}_{4}(\mathrm{aq}) \\ +8 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+5 \mathrm{O}_{2}(\mathrm{g})+\mathrm{K}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \end{aligned} \\] Define \(v,\) the rate of reaction, in terms of each of the reactants and products.

The reaction \\[ \mathrm{SO}_{2} \mathrm{Cl}_{2}(\mathrm{g}) \rightarrow \mathrm{SO}_{2}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g}) \\] is first order and has a rate constant of \(2.24 \times 10^{-5} \mathrm{s}^{-1}\) at \(320^{\circ} \mathrm{C}\). Calculate the half-life of the reaction. What fraction of a sample of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}(\mathrm{g})\) remains after being heated for 5.00 hours at \(320^{\circ} \mathrm{C} ?\) How long will a sample of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}(\mathrm{g})\) need to be maintained at \(320^{\circ} \mathrm{C}\) to decompose \(92.0 \%\) of the initial amount present?

The gas-phase rearrangement reaction vinyl allyl ether \(\longrightarrow\) allyl acetone has a rate constant of \(6.015 \times 10^{-5} \mathrm{s}^{-1}\) at \(420 \mathrm{K}\) and a rate constant of \(2.971 \times 10^{-3} \mathrm{s}^{-1}\) at \(470 \mathrm{K} .\) Calculate the values of the Arrhenius parameters \(A\) and \(E_{\mathrm{g}^{*}}\) Calculate the values of \(\Delta^{\dagger} H^{\circ}\) and \(\Delta^{\dagger} S^{\circ}\) at \(420 \mathrm{K} .\) (Assume ideal-gas behavior.)

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